Re: Admin Panel

[Derek]

For a better looking admin, try:

* https://django-grappelli.readthedocs.io/en/latest/
* https://djangosuit.com/

For "admin issues" you'll need to be more specific.  There are very few, if 
any, unsolved bugs in the Admin code

On Thursday, 9 January 2020 21:02:03 UTC+2, APIJAY SHARMA wrote:
>
> Can anyone help me out with good looking admin panels and how to customize 
> it and if possible how to make it more reliable!!!  I am just getting 
> frustrated with admin issues in most of the modules
>
>

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Re: Make a Django query filter at runtime

[Derek]

There is a long discussion about "not equals" here:

https://stackoverflow.com/questions/687295/how-do-i-do-a-not-equal-in-django-queryset-filtering

I am sure you can adapt one of the suggestions there for your specific 
needs.

On Friday, 10 January 2020 14:35:48 UTC+2, Ezequias Rocha wrote:
>
> Hi Alex
>
> I could do almost all query but not the "not equals" could you give me 
> some tip to add this operator to my object?
>
> I am doing the following way:
>
>   if (operador == 'equals'):
> d[realname] = value
>   elif (operador == greather than'):
> d[realname + '__gt'] = value
> elif (operador == 'less than'):
> d[realname + '__lt'] = value
> elif (operador == 'not equals'):
> 
> . . .
> qs = classDjango.objects.filter(**d)
>
> return qf
>
>
> Best regards
> Ezequias
> On Wednesday, January 8, 2020 at 10:08:18 PM UTC-3, Alex Conselvan de 
> Oliveira wrote:
>>
>> Hi Ezequias,
>>
>> You could use a dict:
>>
>> data = {
>>   'name': 'John',
>>   'age': 42,
>> }
>>
>> model.filter(**data)
>>
>> Best Regards!
>>
>> Em qua., 8 de jan. de 2020 às 18:09, Ezequias Rocha  
>> escreveu:
>>
>>> Hi everyone
>>>
>>> I am in a doubt about creating django filters dynamically.
>>>
>>> All you know a filter is made by using the parameters like:
>>>
>>> model.filter(name='John', age=42)
>>>
>>> But if I can't type all fields and values at design time but at runtime 
>>> how to do that?
>>>
>>> Best regards
>>> Ezequias
>>>
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>>>  
>>> 
>>> .
>>>
>>

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Pagination in Admin class

[Bruckner de Villiers]

Does anyone have some example code to achieve pagination to display a model 
with many records in Admin, please?

 

admin.py – 

 

class CurrencyAdmin(admin.ModelAdmin):

    paginate_by=10

    list_display = ('id', 'currency_Code', 'currency_Description')

    fieldsets = (

    (None, {'fields':('currency_Code', 'currency_Description')}),

    )

 

Much obliged,

 

Bruckner de Villiers

083 625 1086

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"This field is required." error in REST

[Yash Garg]

I have created a User registration rest api app
 
views.py-
class UserRegister(APIView):

throttle_classes = [UserRateThrottle]
def post(self, request, format='json'):
serializer = UserRegisterSerializer(data=request.data)
if serializer.is_valid():
user = serializer.save()
if user:
return Response(serializer.data, status=status.HTTP_201_CREATED)
return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)

serializers.py

class UserRegisterSerializer(serializers.ModelSerializer):

class Meta:
model = UserRegister
fields = ('first_name', 'last_name', 'email', 'password')

def save(self):
  user = UserRegister(first_name = self.validated_data['first_name'],
  last_name = self.validated_data['last_name'],
  email =  self.validated_data['email'],
  password = self.validated_data['password'],
)
  user.save()
  return user

when i POST the values from postman it gives 
{
"first_name": [
"This field is required."
],
"last_name": [
"This field is required."
],
"email": [
"This field is required."
],
"password": [
"This field is required."
]
}
please suggest how can i resolve this.

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Re: Regarding Internship

[Laura Pérez]

Hi!! 
I’m interested in this position. 
Best!

Enviado desde mi iPhone

> El 11 ene. 2020, a la(s) 1:51 a.m., Ravi Shankar  
> escribió:
> 
> 
> Hi Deepak,
> 
> I work for Qwikcilver a Fintech company and also we have NGO Career Vizion, 
> we training students to become industry-ready. 
> 
> Call me on 9900777110 or send me message on shankar...@yahoo.com.
> 
> Regards,
> H C Ravishankar
> 
>> On Sun, 22 Dec 2019 at 17:53, Deepak Singh  
>> wrote:
>> Hi there all,
>> 
>> I am looking for an Internship. I am 4th year student of computer science. 
>> My recent project was on algorithmic trading. I love to work on fintech 
>> projects but right now anything will do.
>> 
>> Regards 
>> Deepak Singh 
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Facebook Like app with Django

[Sky Luv]

Hi, 

I am creating a social app something like facebook with Django.
I do not want to "reinvent the wheel" and I know there are a lot of awesome 
Django packages.

Could you kindly list packages that I should install to my app?

Thank a lot in advance!

Best

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Re: Facebook Like app with Django

[Motaz Hejaze]

Ofcourse you can make use of many packages ..

Djangorestframework
Allauth

As a start ..

On Sat, 11 Jan 2020, 3:14 pm Sky Luv,  wrote:

> Hi,
>
> I am creating a social app something like facebook with Django.
> I do not want to "reinvent the wheel" and I know there are a lot of
> awesome Django packages.
>
> Could you kindly list packages that I should install to my app?
>
> Thank a lot in advance!
>
> Best
>
> --
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> 
> .
>

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react.js not rendering anything in django project

[engineer sahab]

check here full code and all details: 
https://stackoverflow.com/questions/59694929/react-js-not-rendering-in-django-project

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Re: react.js not rendering anything in django project

[Integr@te System]

Hi,

Plz look at an answer that an expert point out your typo, case sensitive
usual mistakes.
Thanks.

On Sat, Jan 11, 2020, 21:55 engineer sahab  wrote:

> check here full code and all details:
> https://stackoverflow.com/questions/59694929/react-js-not-rendering-in-django-project
>
> --
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> 
> .
>

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specefic field(s) for each query.

[Mohsen Pahlevanzadeh]

Hello everybody,

I can write django code for "select * from mytables;", but I can't specefic 
fields such as "select field(s) from my table;"

Please help me..

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specefic field(s) for each query.

[Santhosh sridhar]

You can query like this in Django, say the table name is A and column name is 
name.
A.objects.all() will give all the objects and A.objects.filter(name='Django') 
will give all the objects whose name is Django.

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Re: specefic field(s) for each query.

[山村維宏]

use values().

example:
Foo.objects.filter(name='foo').values('bar', 'baz')

2020年1月12日(日) 2:38 Mohsen Pahlevanzadeh :

> Hello everybody,
>
> I can write django code for "select * from mytables;", but I can't
> specefic fields such as "select field(s) from my table;"
>
> Please help me..
>
> --
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> 
> .
>

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specefic field(s) for each query.

[Santhosh sridhar]

You can query like this in Django, say A is the table name and B is the 
columns. A.objects.all().values('B') or 
A.objects.all().values_list('B',flat=True)

Regards,
San

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Re: "This field is required." error in REST

[Integr@te System]

Hi Garg,

Which your expected results in your code!?

Where the points you see errors!?

Plz review again and provide us more details.
Nice.







On Sat, Jan 11, 2020, 18:19 Yash Garg  wrote:

> I have created a User registration rest api app
>
> views.py-
> class UserRegister(APIView):
>
> throttle_classes = [UserRateThrottle]
> def post(self, request, format='json'):
> serializer = UserRegisterSerializer(data=request.data)
> if serializer.is_valid():
> user = serializer.save()
> if user:
> return Response(serializer.data, status=status.HTTP_201_CREATED)
> return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)
>
> serializers.py
>
> class UserRegisterSerializer(serializers.ModelSerializer):
>
> class Meta:
> model = UserRegister
> fields = ('first_name', 'last_name', 'email', 'password')
>
> def save(self):
>   user = UserRegister(first_name = self.validated_data['first_name'],
>   last_name = self.validated_data['last_name'],
>   email =  self.validated_data['email'],
>   password = self.validated_data['password'],
> )
>   user.save()
>   return user
>
> when i POST the values from postman it gives
> {
> "first_name": [
> "This field is required."
> ],
> "last_name": [
> "This field is required."
> ],
> "email": [
> "This field is required."
> ],
> "password": [
> "This field is required."
> ]
> }
> please suggest how can i resolve this.
>
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> 
> .
>

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Re: react.js not rendering anything in django project

[engineer sahab]

yes don't know what was mistake but started from scratch and now it's 
working

On Saturday, January 11, 2020 at 10:24:17 PM UTC+5:30, Integr@te System 
wrote:
>
> Hi, 
>
> Plz look at an answer that an expert point out your typo, case sensitive 
> usual mistakes.
> Thanks.
>
> On Sat, Jan 11, 2020, 21:55 engineer sahab  > wrote:
>
>> check here full code and all details: 
>> https://stackoverflow.com/questions/59694929/react-js-not-rendering-in-django-project
>>
>> -- 
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>> email to django...@googlegroups.com .
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>>  
>> 
>> .
>>
>

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contrib.sites readonly question

[Mike Dewhirst]

I use contrib.sites I think successfully to differentiate between dev, 
staging and production for purposes of adjusting URLs as intended for 
linked resources.


However, I cannot find a way to make contrib.sites data readonly in the 
Admin


How can I make it readonly in the Admin?

I've tried changing settings to make it a local app "sites" instead of 
"django.contrib.sites" and importing it as follows ...


#myproject/sites/__init__.py
from django.contrib.sites import *


#myproject/sites/admin.py
from django.contrib import admin
from .admin import SiteAdmin
from .models import Site

admin.site.unregister(Site)

class MySiteAdmin(SiteAdmin):

    verbose_name = "Website"

    def has_add_permission(self, request=None, obj=None):
    return False

    def has_change_permission(self, request=None, obj=None):
    return False

    def has_delete_permission(self, request=None, obj=None):
    return False

    def has_view_permission(self, request=None, obj=None):
    return False

admin.site.register(MySite, SiteAdmin)

This has no effect

Is there a way to do this?

Thanks

Mike


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Re: contrib.sites readonly question

[Daksh agnihotri]

In admin.py

Class UserProfileAdmin(admin.ModelAdmin):
List_display = ()
Readonly_fields =()

...
...
..
Field in readonly_field... will have read permissions only..

I have used it.

On Sun, Jan 12, 2020, 8:47 AM Mike Dewhirst  wrote:

> I use contrib.sites I think successfully to differentiate between dev,
> staging and production for purposes of adjusting URLs as intended for
> linked resources.
>
> However, I cannot find a way to make contrib.sites data readonly in the
> Admin
>
> How can I make it readonly in the Admin?
>
> I've tried changing settings to make it a local app "sites" instead of
> "django.contrib.sites" and importing it as follows ...
>
> #myproject/sites/__init__.py
> from django.contrib.sites import *
>
>
> #myproject/sites/admin.py
> from django.contrib import admin
> from .admin import SiteAdmin
> from .models import Site
>
> admin.site.unregister(Site)
>
> class MySiteAdmin(SiteAdmin):
>
>  verbose_name = "Website"
>
>  def has_add_permission(self, request=None, obj=None):
>  return False
>
>  def has_change_permission(self, request=None, obj=None):
>  return False
>
>  def has_delete_permission(self, request=None, obj=None):
>  return False
>
>  def has_view_permission(self, request=None, obj=None):
>  return False
>
> admin.site.register(MySite, SiteAdmin)
>
> This has no effect
>
> Is there a way to do this?
>
> Thanks
>
> Mike
>
>
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> .
>

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How to Extract values of diffrent from foreign key in django models

[manas srivastava]

I have made a model to make friends using Django model. Now I am unable to 
get the friend id through the model. The model is as follows

class Friend(models.Model):

users = models.ManyToManyField(User) #following users

current_user = models.ForeignKey(User, related_name='owner', 
null=True,on_delete=models.CASCADE)  #followers

@classmethod

def make_friend(cls, current_user, new_friend):

friend, created = cls.objects.get_or_create(

current_user = current_user

)

friend.users.add(new_friend)



@classmethod

def lose_friend(cls, current_user, new_friend):

friend, created = cls.objects.get_or_create(

current_user = current_user

)

friend.users.remove(new_friend)

How can I extract the friend id

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Re: How to Extract values of diffrent from foreign key in django models

[Integr@te System]

Hi Manas,

What about User model!? (Because of ForeignKey you declared)

This is where Friend.object.get() come from Friend model of current user.




On Sun, Jan 12, 2020, 11:50 manas srivastava 
wrote:

>
>
>
> I have made a model to make friends using Django model. Now I am unable to
> get the friend id through the model. The model is as follows
>
> class Friend(models.Model):
>
> users = models.ManyToManyField(User) #following users
>
> current_user = models.ForeignKey(User, related_name='owner', 
> null=True,on_delete=models.CASCADE)  #followers
>
> @classmethod
>
> def make_friend(cls, current_user, new_friend):
>
> friend, created = cls.objects.get_or_create(
>
> current_user = current_user
>
> )
>
> friend.users.add(new_friend)
>
>
>
> @classmethod
>
> def lose_friend(cls, current_user, new_friend):
>
> friend, created = cls.objects.get_or_create( style="border-bottom-color: currentColor; border-bottom-style: none; 
> border-bottom-width: 0px; border-image-outset: 0; border-image-repeat: 
> stretch; border-image-slice: 100%; border-image-source: none; 
> border-image-width: 1; border-left-color: currentColor; border-left-style: 
> none; border-left-width: 0px; border-right-color: currentColor; 
> border-right-style: none; border-right-width: 0px; border-top-color: 
> currentColor; border-top-style: none; border-top-width: 0px; box-sizing: 
> inherit; color: rgb(48, 51, 54); font-family: inherit; font
>
>

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