Re: Django Captcha Ajax call not working
Hi Melvyin still not working
$(".captcha_form").submit(function(event){
event.preventDefault();
var form = $(this)
alert (form.serialize())
$.ajax({
type: "POST",
url: "./captcha",
contentType: "application/json",
data: form.serialize(),
dataType: "json",
success: function(data) {
alert(data.status);
},
error: function(data) {
alert("NOT_OK");
}
});
});
});
{%csrf_token%}
{{form.as_p}}
If i make the call using form post method it validates, if use ajax post
method with form.serialize() it not validates? The problem for sure ios
with ajax call!
Please help out!
rgds valerio
On Monday, March 27, 2017 at 5:44:34 PM UTC+2, valerio orfano wrote:
>
> Hi Melvyn
>
> thanx a lot . I will try tomorrow early morning and will let u know.
> Thanx. valerio
>
> On Monday, March 27, 2017 at 3:31:38 PM UTC+2, Melvyn Sopacua wrote:
>>
>> Hi,
>>
>>
>>
>> {% if field.name = 'captcha' %}
>>
>>
>>
>> assigns 'captcha' to field.name and returns if that succeeded. So it's
>> always true. You probably mean:
>>
>> {% if field.name == 'captcha' %}
>>
>>
>>
>> From what you describe, testfield shows up and your template code says it
>> shouldn't show up.
>>
>>
>>
>> However, when debugging a problem, always reduce to the simplest case, so
>> try with this template code:
>>
>>
>>
>> > method="post">{%csrf_token%}
>>
>> {{ form }}
>>
>> > value="Invio"/>
>>
>>
>>
>>
>>
>> On Monday 27 March 2017 05:43:53 valerio orfano wrote:
>>
>> > testfield is where i type my captcha, sorry
>>
>> >
>>
>> > On Monday, March 27, 2017 at 2:38:15 PM UTC+2, valerio orfano wrote:
>>
>> > > Hi Melvyn thanx for ur reply,
>>
>> > >
>>
>> > > this is my form.
>>
>> > >
>>
>> > > class AjaxForm(forms.ModelForm):
>>
>> > > captcha = CaptchaField()
>>
>> > >
>>
>> > > class Meta:
>>
>> > > model = ajaxModel
>>
>> > > exclude = []
>>
>> > >
>>
>> > > class ajaxModel(models.Model):
>>
>> > > testfield = models.TextField(null=True, blank=True)
>>
>> > >
>>
>> > > If i don't use a ajaxmodel a get an error, so testfield is just a
>>
>> > > dummy field, just to avoid error.
>>
>> > >
>>
>> > > valerio
>>
>> > >
>>
>> > > On Monday, March 27, 2017 at 2:22:44 PM UTC+2, Melvyn Sopacua wrote:
>>
>> > >> On Monday 27 March 2017 04:46:06 valerio orfano wrote:
>>
>> > >> > {% if field.name = 'captcha' %}
>>
>> > >>
>>
>> > >> It may not make a difference if you only have one visible field,
>>
>> > >> but this is not a comparison.
>>
>> > >>
>>
>> > >>
>>
>> > >> Melvyn Sopacua
>>
>>
>>
>> --
>>
>> Melvyn Sopacua
>>
>
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Re: Update dict JsonField Postgresql
On Monday 27 March 2017 15:03:17 Martin Peveri wrote:
> Perfect!! This code works:
>
> data = objectitem.data
>
> data[0]['processed'] = True
>
> objectitem.data = data
>
> objectitem.save()
>
> A last query that is not related to the insertion, but to the query.
>
> If I want to get only records processed in True as I have to do?
>
> This does not work, I get all the records:
>
> objectitem.filter(data__contains=[{'processed': True}])
Looking at your data model, you should probably make data an ArrayField of
JSONFields...
This would simplify things quite a bit.
That said, I would try data__contains={'processed': True}, but if that doesn't
work,
your problem is that your outer structure is a list, not an object, making
filtering a lot
harder.
--
Melvyn Sopacua
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Re: Update dict JsonField Postgresql
It does not work :(
With ArrayField Will I be able to filter the content of the field?. For
example, if i have one record and in the field data a list of dict with
50k. Can I filter it?. That is to say, to bring only in the array the
records with 'processed' true.
Thanks!
El martes, 28 de marzo de 2017, 6:58:51 (UTC-3), Melvyn Sopacua escribió:
>
> On Monday 27 March 2017 15:03:17 Martin Peveri wrote:
>
> > Perfect!! This code works:
>
> >
>
> > data = objectitem.data
>
> >
>
> > data[0]['processed'] = True
>
> >
>
> > objectitem.data = data
>
> >
>
> > objectitem.save()
>
> >
>
> > A last query that is not related to the insertion, but to the query.
>
> >
>
> > If I want to get only records processed in True as I have to do?
>
> >
>
> > This does not work, I get all the records:
>
> >
>
> > objectitem.filter(data__contains=[{'processed': True}])
>
>
>
> Looking at your data model, you should probably make data an ArrayField of
> JSONFields...
>
> This would simplify things quite a bit.
>
>
>
> That said, I would try data__contains={'processed': True}, but if that
> doesn't work, your problem is that your outer structure is a list, not an
> object, making filtering a lot harder.
>
>
>
> --
>
> Melvyn Sopacua
>
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Re: django sample projects
On Monday 27 March 2017 09:27:59 Shahab Emami wrote: > hello > > i have question: > where can i find a few django sample projects? Mezzanine[1] and Cartridge[2] probably fit the bills best. Mezzanine comes with it's own mezzanine-project command, which creates a project and after running createdb is a fully functional site with user accounts, blog, gallery and editable pages. In the end though, a Django project is a collection of apps tied to urls. If you can write an app, all you need to do is tie them to urls and add the homepage and global navigation. -- Melvyn Sopacua [1] http://mezzanine.jupo.org/ [2] http://cartridge.jupo.org/ -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To post to this group, send email to django-users@googlegroups.com. Visit this group at https://groups.google.com/group/django-users. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/14636786.7DRbtNKXo2%40devstation. For more options, visit https://groups.google.com/d/optout.
Re: Django signup problem Urgent
On Monday 27 March 2017 20:19:11 Babatunde Akinyanmi wrote: > Hello Idowu. > You were supposed to include your stack trace so that there can be a > proper diagnosis of the problem. Now we can only guess. > > I guess you are submitting your form with the `description` field > empty because your defined it with `blank=True` in your models.py. Wrong diagnosis. You would not get a "field is required" message, but "this field cannot be null" (which comes from the model layer, not the form layer). The problem is two-fold: 1) You're trying to do everything yourself that's already abstracted. Use at minimum generic.FormView[1] 2) The image field: it is required and you're not passing request.FILES to the form. And maybe a third: encoding type of the form should be set correctly. -- Melvyn Sopacua [1] https://ccbv.co.uk/projects/Django/1.10/django.views.generic.edit/FormView/ -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To post to this group, send email to django-users@googlegroups.com. Visit this group at https://groups.google.com/group/django-users. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/1782037.10WnRrGJpY%40devstation. For more options, visit https://groups.google.com/d/optout.
python-social-auth-django for Twitter
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