Re: PostgreSQL backend - Ident authentication failed?
On Monday 21 June 2010 12:24:58 Torsten Bronger wrote: > > Also, is this recommended practice, to use "www-data" as the > > backend database username? > > No, not recommended, but not forbidden either. > should be forbidden - one does not want apache to have direct access to the database -- Regards Kenneth Gonsalves Senior Associate NRC-FOSS at AU-KBC -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: PostgreSQL backend - Ident authentication failed?
heya, Using "www-data" as the backend database username in settings.py doesn't quite work. If you try to run a ./manage.py syncdb, it spits out: Traceback (most recent call last): File "./manage.py", line 11, in execute_manager(settings) File "/usr/local/lib/python2.6/dist-packages/django/core/ management/__init__.py", line 438, in execute_manager utility.execute() File "/usr/local/lib/python2.6/dist-packages/django/core/ management/__init__.py", line 379, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/usr/local/lib/python2.6/dist-packages/django/core/ management/base.py", line 191, in run_from_argv self.execute(*args, **options.__dict__) File "/usr/local/lib/python2.6/dist-packages/django/core/ management/base.py", line 220, in execute output = self.handle(*args, **options) File "/usr/local/lib/python2.6/dist-packages/django/core/ management/base.py", line 351, in handle return self.handle_noargs(**options) File "/usr/local/lib/python2.6/dist-packages/django/core/ management/commands/syncdb.py", line 52, in handle_noargs cursor = connection.cursor() File "/usr/local/lib/python2.6/dist-packages/django/db/backends/ __init__.py", line 75, in cursor cursor = self._cursor() File "/usr/local/lib/python2.6/dist-packages/django/db/backends/ postgresql_psycopg2/base.py", line 136, in _cursor self.connection = Database.connect(**conn_params) psycopg2.OperationalError: FATAL: Ident authentication failed for user "www-data" I've changed the authentication in my pg_hba.conf from "ident" to "password", and it now works with "victorhooi" as the backend database username =). So there's no need to use a PostgreSQL www-data account. I'm still curious what changed? Perhaps Ubuntu's default pg_hba.conf file changed from 9.04 to 10.04? AFAIK, there wasn't any such change, although I don't have a 9.04 system around to verify. Anyhow, is this the recommended configuration, what I have now? Just want to know the right way of doing things? Cheers, Victor On Jun 21, 4:54 pm, Torsten Bronger wrote: > Hall chen! > > Victor Hooi writes: > > [...] > > > However, I'm still curious as to what changed, as I'm fairly sure > > this setup worked on the old Ubuntu 9.04 server? And I'm > > definitely sure that the database username was set to "victorhooi" > > on that old system - I copied the settings.py file over using > > verbatim (rsync). > > Maybe pg_hba.conf has changed. > > > Also, is this recommended practice, to use "www-data" as the > > backend database username? > > No, not recommended, but not forbidden either. We didn't use > "ident" but "password" in pg_hba.conf. This way, you are not bound > to user accounts of the underlying operating system. > > But possibly we switch to "ident" for local connections > (i.e. command line) and "password" for TCP/IP connections. The > reason is that passwords make command line scripting harder. > > Tsch , > Torsten. > > -- > Torsten Bronger, aquisgrana, europa vetus > Jabber ID: torsten.bron...@jabber.rwth-aachen.de > orhttp://bronger-jmp.appspot.com -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Apache + Gunicorn + Django? Sample Configs?
Hi, I'm currently deploying Django on Apache with WSGI. Anyhow, I've heard really good things about the Gunicorn (http:// gunicorn.org/) WSGI server, so I was hoping to try it out. I'm running Ubuntu 10.04, so I've installed the packages from the official PPA (https://launchpad.net/~bchesneau/+archive/gunicorn) However, I'm having trouble finding detailed instructions for Gunicorn + Django in English. E.g.: http://blog.exirel.me/technique/apache-proxy-gunicorn-runit-django http://blog.sietch-tabr.com/index.php/post/2010/04/04/Heberger-des-projets-Django-avec-Nginx-et-Gunicorn Nor can I seem to find anything on how to deploy Apache + Django + Gunicorn in English either. Has anybody had success with getting it properly setup in production with Django, and if so, would it be possible to post up your sample config scripts? Many of the guides refer to using Nginx - however, I need Apache running on this server (other sites), and I only have a single IP address on this system. And I'm not aware of any way of passing only specific virtual-hosts through to Nginx, to then pass onto Gunicorn. But if there's an easy way of doing that, I'm open to using Nginx + Django + Gunicorn as an alternative. Cheers, Victor -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: PostgreSQL backend - Ident authentication failed?
On Monday 21 June 2010 12:45:11 Victor Hooi wrote: > I'm still curious what changed? Perhaps Ubuntu's default pg_hba.conf > default always has ident in all distros that I am aware of -- Regards Kenneth Gonsalves Senior Associate NRC-FOSS at AU-KBC -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Django templates and libraries
i think i'd be right in saying that template tags are different to the eggs issue. i found a post on b-list which explained templatetags and where to put them. http://www.b-list.org/weblog/2007/dec/04/magic-tags/ so pretty much always drop the tags inside a folder named templatetags in your app folder. have you done that? Matt On Jun 20, 11:34 pm, tanman wrote: > Hello, I'm trying to setup an existing Django site up on WebFaction. > I've uploaded the code and installed the libraries, but I'm having > trouble getting the site to use my libraries. I've figured out that > when I installed libraries with easy_install, they were installed to / > home/jhumunc/lib/python2.5 instead of /home/jhumunc/webapps/jhumunc/ > lib/python2.5 and I found a recommendation to copy all the eggs from > to the latter directory but I don't know if this actually helped at > all. I've also added some of the template directories from within the > eggs to my settings.py file. I'm trying to get the page > athttp://www.jhumunc.webfactional.com/accounts/register/to work > properly. The pages uses the forms library and I've made sure that the > library is on the template_dirs list in the settings.py file (/home/ > jhumunc/webapps/jhumunc/lib/python2.5/django_forms-0.5-py2.5.egg/forms/ > templates). However, when I load the page, it's saying that it can't > find the templatetags that correspond to that template. I know the > correct directory to look in is /home/jhumunc/webapps/jhumunc/lib/ > python2.5/django_forms-0.5-py2.5.egg/forms/templatetags but I can't > figure out where to specify this. > > Any help would be appreciated. Thanks! -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: PostgreSQL backend - Ident authentication failed?
On 21 June 2010 17:04, Kenneth Gonsalves wrote: > On Monday 21 June 2010 12:24:58 Torsten Bronger wrote: >> > Also, is this recommended practice, to use "www-data" as the >> > backend database username? >> >> No, not recommended, but not forbidden either. >> > > should be forbidden - one does not want apache to have direct access to the > database Storing a password in plaintext file makes me uneasy, even though it is locked away through file-system permissions. Having spent some time recently in the Windows world, I take integrated auth for granted, and it works fine, making sysadmin much easier. You do bring up a interesting point though, and I don't know much about the architecture of Apache and how holes are exploited when they exist, but if the trespasser can execute arbitary code as www-data, wouldn't they have access to settings.py anyway? > -- > Regards > Kenneth Gonsalves > Senior Associate > NRC-FOSS at AU-KBC > > -- > You received this message because you are subscribed to the Google Groups > "Django users" group. > To post to this group, send email to django-us...@googlegroups.com. > To unsubscribe from this group, send email to > django-users+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/django-users?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Actions after HttpResponse rendered?
On Jun 21, 6:46 am, DaNmarner wrote: > There's a similar question as mine on stackoverflow.com: > > http://stackoverflow.com/questions/1081340/how-do-you-do-something-af... > > and there isn't a satisfactory answer there. > > Basically, how do I do some thing after a view returns the response? > Does request_finished enables that kind of operations? Why do you think none of those answers is satisfactory? There are a few useful recommendations on that page. What exactly do you need that isn't covered? -- DR. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
How much would you charge for this? £5k? £15k? £5 0k?
I'm just starting out with Django so using an hourly rate isn't really applicable because I'm going to be much slower that a 'real' developer. So far I've spent about 6 months part time. What kind of ballpark amounts would people suggest this is worth? I'm not going to tell you how much they think it was ... well maybe I'll tell you later. I'm trying to help them out so it's considerably cheaper than I think it should be. What is it? The application is helps the sales staff organize product demonstrations around the country. They can book demonstrators to do an event. The demonstrators do the events and then enter the details of how it went. The system provides invoice generation, event tracking and custom reporting. Features - Dynamic questionnaire and report form generation into pdf. - Dynamic invoice generation into pdf. - Work-flow with page locking, rollback and automatic email generation on status change. - Daily (and horribly complex) automatic summary excel reports - Sales and questionnaire summary reports - Designing and building the site -- Models (about 32) -- Setting up the admin interface -- 12 key views plus goodness knows how many auxiliary views. -- Look and feel Other activities - Weekly automatic importing of data from another accounting database - Importing of existing event data. - Importing of product prices and rates, existing staff details, demonstrator details, - Finding and setting up a VPS host - Installing and configuring the site - Support for a year (occasional changes, bug fixes and helping them settle in) - Training materials ... and this doesn't even take into account the changes they made halfway though. I should have been more formal with the spec but I know them and didn't think it would be necessary. Once bitten Appreciate this is a bit finger in the air, but like I said ... ballparking. ALJ -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: PostgreSQL backend - Ident authentication failed?
On Monday 21 June 2010 13:39:42 Sam Lai wrote: > > should be forbidden - one does not want apache to have direct access to > > the database > > Storing a password in plaintext file makes me uneasy, even though it > is locked away through file-system permissions. > > Having spent some time recently in the Windows world, I take > integrated auth for granted, and it works fine, making sysadmin much > easier. and a single point of entry to all systems for a cracker > > You do bring up a interesting point though, and I don't know much > about the architecture of Apache and how holes are exploited when they > exist, but if the trespasser can execute arbitary code as www-data, > wouldn't they have access to settings.py anyway? > and just to add to your worries, assuming that you have debug on in your production system, somewhere deep down in the traceback, you may see your database username and password! As for the apache question there are experts in this list who can anwer them. -- Regards Kenneth Gonsalves Senior Associate NRC-FOSS at AU-KBC -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
RE: Problem trying to configure Django with FastCGI and Lighttpd
I know this thread is rather old but for those who come across this trying to identify their issues here's how I got things working for me on Ubuntu 10.04. The major issue to the above poster's issue was with permissions. The www-data user that's running the lighttpd process needs to be able to execute the .fcgi script. Once that is fixed then running is easy. Your user that's running your server process maybe named something else. I use 'htop' to see running processes (or you can use 'top' since it's likely to already be installed on your distro) and who owns those processes. Here's my .fcgi script: #!/usr/bin/python import sys, os # Add a custom Python path. sys.path.insert(0, "/var/www/sites/example/mysite") # Switch to the directory of your project. (Optional.) # os.chdir("/home/user/myproject") # Set the DJANGO_SETTINGS_MODULE environment variable. os.environ['DJANGO_SETTINGS_MODULE'] = "mysite.settings" from django.core.servers.fastcgi import runfastcgi runfastcgi(method="prefork", daemonize="false") And my relevant lighttpd.conf setup: == fastcgi.server = ( "/example.fcgi" => ( "main" => ( # Use host / port instead of socket for TCP fastcgi "bin-path" => "/var/www/sites/example/mysite.fcgi", "host" => "127.0.0.1", "port" => 2001, #"socket" => "/var/www/sites/example/example.sock", "check-local" => "disable", "max-procs" => 2, "idle-timeout" => 20, ) ), ) I was running with a .sock file setup where I ran ./manage.py runfcgi ... but I didn't want to have a process that had to trigger on server startup and would rather just let the server own the starting so that's why I went the route of using a .fcgi script and setting up the .conf to start the processes. I do have one issue though and maybe someone can help answer why this is. Even though I have "max-procs" => 2, I count 12 processes that are running ... is this because I'm not specifying a child process count or something? Also, on my rackspace cloud server I'm only getting about 30 requests/sec on static or dynamic content using AB from my local desktop and hitting my server...is there something I should be looking into to find out why this is the case? I'm very new to the who sysadmin thing and having to wear this hat for now. Thanks in advance for any pointers/help - I was able to get about 350+ requests/sec using Apache2 and mod_wsgi on a VM player Ubuntu appliance (using Ubuntu 10.04 just like on the cloud)...so unless my cable connection to the outside world is slowing things up for me I don't see why lighttpd and/or my server environment is running so slow. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Mysql-Python error
When installing Mysql-Python I get this error. Traceback (most recent call last): File "setup.py", line 5, in from setuptools import setup, Extension ImportError: No module named setuptools Can anyone please help me. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Mysql-Python error
On Monday 21 June 2010 13:04:19 Eduan wrote: > When installing Mysql-Python I get this error. > > Traceback (most recent call last): > File "setup.py", line 5, in > from setuptools import setup, Extension > ImportError: No module named setuptools > install setuptools -- Regards Kenneth Gonsalves Senior Associate NRC-FOSS at AU-KBC -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: PostgreSQL backend - Ident authentication failed?
On 21 June 2010 19:47, Kenneth Gonsalves wrote: > On Monday 21 June 2010 13:39:42 Sam Lai wrote: >> > should be forbidden - one does not want apache to have direct access to >> > the database >> >> Storing a password in plaintext file makes me uneasy, even though it >> is locked away through file-system permissions. >> >> Having spent some time recently in the Windows world, I take >> integrated auth for granted, and it works fine, making sysadmin much >> easier. > > and a single point of entry to all systems for a cracker I'm not running them all as admin (aka. root) obviously. Integrated auth doesn't mean every user account can access every resource. It's really just delegating an application's authentication system to the operating system (note authentication, not authorization). I fail to see how it is a single-point of entry to all systems. Yes, it means there's one less layer of security, but that extra layer provided by the DBMS isn't security anyway if as that OS user, you can access the password to get past that extra layer of security anyway. I don't believe this is an implementation of defense in depth. >> You do bring up a interesting point though, and I don't know much >> about the architecture of Apache and how holes are exploited when they >> exist, but if the trespasser can execute arbitary code as www-data, >> wouldn't they have access to settings.py anyway? >> > > and just to add to your worries, assuming that you have debug on in your > production system, somewhere deep down in the traceback, you may see your > database username and password! As for the apache question there are experts > in this list who can anwer them. Thanks for mocking what was and still is a serious point. > -- > Regards > Kenneth Gonsalves > Senior Associate > NRC-FOSS at AU-KBC > > -- > You received this message because you are subscribed to the Google Groups > "Django users" group. > To post to this group, send email to django-us...@googlegroups.com. > To unsubscribe from this group, send email to > django-users+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/django-users?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: PostgreSQL backend - Ident authentication failed?
On Monday 21 June 2010 15:37:50 Sam Lai wrote: > > and a single point of entry to all systems for a cracker > > I'm not running them all as admin (aka. root) obviously. Integrated > auth doesn't mean every user account can access every resource. It's > really just delegating an application's authentication system to the > operating system (note authentication, not authorization). > > I fail to see how it is a single-point of entry to all systems. Yes, > it means there's one less layer of security, but that extra layer > provided by the DBMS isn't security anyway if as that OS user, you can > access the password to get past that extra layer of security anyway. I > don't believe this is an implementation of defense in depth. I am no expert on windows, so cannot comment. > > >> You do bring up a interesting point though, and I don't know much > >> about the architecture of Apache and how holes are exploited when they > >> exist, but if the trespasser can execute arbitary code as www-data, > >> wouldn't they have access to settings.py anyway? > > > > and just to add to your worries, assuming that you have debug on in your > > production system, somewhere deep down in the traceback, you may see your > > database username and password! As for the apache question there are > > experts in this list who can anwer them. > > Thanks for mocking what was and still is a serious point. > I am sorry if you feel I was mocking - it was not my intention. And the point you were bringing up about Apache is a vast subject and I am not competent to answer it. As for the debug thing, it is just a warning not to run debug in production. -- Regards Kenneth Gonsalves Senior Associate NRC-FOSS at AU-KBC -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Actions after HttpResponse rendered?
On 21/06/10 06:46, DaNmarner wrote: There's a similar question as mine on stackoverflow.com: http://stackoverflow.com/questions/1081340/how-do-you-do-something-after-you-render-the-view-django and there isn't a satisfactory answer there. Basically, how do I do some thing after a view returns the response? Short answer: save yourself hassle and set up celery. The answers on that page do talk in general terms about using message queues and background processes, which is exactly what celery helps you do concretely in a django context: http://celeryproject.org/ -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: UnicodeDecodeError (ordinal not in range) when deleting an inline item - 1.2.1
Federico, When trying out what Karen suggests then in the unlikely event that Red Hat doesn't load the environment variables from /etc/apache2/ envvars, one way to find it without consulting documents is to look at the apache start-up script (e.g. /usr/sbin/apache2ctl) so find that on your server and look at what that loads - for example the copy I've got has the following: # the path to the environment variable file test -z "$APACHE_ENVVARS" && APACHE_ENVVARS='/etc/apache2/envvars' # pick up any necessary environment variables if test -f $APACHE_ENVVARS; then . $APACHE_ENVVARS fi Of course as you can see from that it's possible to set an environment variable before running apache2ctl to change the location of envvars, but it's unlikely they'd do that. Matt > > I am not familiar with Red Hat so I can't give you any more specific advice > than that. If it does not use /etc/apache2/envvars (or if you are using some > server other than Apache), then you need to consult the Red Hat doc or > forums to find out how to configure your web server to run with a LANG other > than C or whatever it is currently using. > -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: PostgreSQL backend - Ident authentication failed?
On 21 June 2010 20:16, Kenneth Gonsalves wrote: > On Monday 21 June 2010 15:37:50 Sam Lai wrote: >> >> You do bring up a interesting point though, and I don't know much >> >> about the architecture of Apache and how holes are exploited when they >> >> exist, but if the trespasser can execute arbitary code as www-data, >> >> wouldn't they have access to settings.py anyway? >> > >> > and just to add to your worries, assuming that you have debug on in your >> > production system, somewhere deep down in the traceback, you may see your >> > database username and password! As for the apache question there are >> > experts in this list who can anwer them. >> >> Thanks for mocking what was and still is a serious point. >> > > I am sorry if you feel I was mocking - it was not my intention. And the point > you were bringing up about Apache is a vast subject and I am not competent to > answer it. As for the debug thing, it is just a warning not to run debug in > production. Ah I must've interpreted it incorrectly, I apologise. I'm definitely no expert on *nix and Apache security, so I'd appreciate it if anyone could clarify as well. >From the PGSQL docs [1], "On systems supporting SO_PEERCRED requests for Unix-domain sockets (currently Linux, FreeBSD, NetBSD, OpenBSD, BSD/OS, and Solaris), ident authentication can also be applied to local connections. In this case, no security risk is added by using ident authentication; indeed it is a preferable choice for local connections on such systems." http://www.postgresql.org/docs/current/static/auth-methods.html So it seems the postgresql people think it is ok, but I'm not sure once you add in Apache and things like Django on top of it. > -- > Regards > Kenneth Gonsalves > Senior Associate > NRC-FOSS at AU-KBC > > -- > You received this message because you are subscribed to the Google Groups > "Django users" group. > To post to this group, send email to django-us...@googlegroups.com. > To unsubscribe from this group, send email to > django-users+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/django-users?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: fieldsets django
I don't know I'm wondering how to use the fieldsets.can you help me...how to use the fieldsets...? On 20 jun, 15:01, Francis Gulotta wrote: > You might want to look into a css solution. > > -Francis > > --- > Francis Gulotta > wiz...@roborooter.com > > On Fri, Jun 18, 2010 at 3:40 PM, Waléria Antunes David < > > > > waleriantu...@gmail.com> wrote: > > I have a form with various fields and I need to split these fields so that > > it looks like the image attached. I was reading about FIELDSETS but do not > > know how to use. > > > -- > > You received this message because you are subscribed to the Google Groups > > "Django users" group. > > To post to this group, send email to django-us...@googlegroups.com. > > To unsubscribe from this group, send email to > > django-users+unsubscr...@googlegroups.com > > . > > For more options, visit this group at > >http://groups.google.com/group/django-users?hl=en. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: PostgreSQL backend - Ident authentication failed?
On Monday 21 June 2010 16:21:10 Sam Lai wrote: > >From the PGSQL docs [1], > > "On systems supporting SO_PEERCRED requests for Unix-domain sockets > (currently Linux, FreeBSD, NetBSD, OpenBSD, BSD/OS, and Solaris), > ident authentication can also be applied to local connections. In this > case, no security risk is added by using ident authentication; indeed > it is a preferable choice for local connections on such systems." > > http://www.postgresql.org/docs/current/static/auth-methods.html > > So it seems the postgresql people think it is ok, but I'm not sure > once you add in Apache and things like Django on top of it. > I am not too sure whether connection over tcp/ip comes under 'local' -- Regards Kenneth Gonsalves Senior Associate NRC-FOSS at AU-KBC -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: How much would you charge for this? £5k? £15k? £50k?
... I've just noticed the title and hope this doesn't look too much like spam!! On Jun 21, 11:12 am, ALJ wrote: > I'm just starting out with Django so using an hourly rate isn't really > applicable because I'm going to be much slower that a 'real' > developer. So far I've spent about 6 months part time. > > What kind of ballpark amounts would people suggest this is worth? > > I'm not going to tell you how much they think it was ... well maybe > I'll tell you later. I'm trying to help them out so it's considerably > cheaper than I think it should be. > > What is it? > The application is helps the sales staff organize product > demonstrations around the country. They can book demonstrators to do > an event. The demonstrators do the events and then enter the details > of how it went. The system provides invoice generation, event tracking > and custom reporting. > > Features > - Dynamic questionnaire and report form generation into pdf. > - Dynamic invoice generation into pdf. > - Work-flow with page locking, rollback and automatic email generation > on status change. > - Daily (and horribly complex) automatic summary excel reports > - Sales and questionnaire summary reports > > - Designing and building the site > -- Models (about 32) > -- Setting up the admin interface > -- 12 key views plus goodness knows how many auxiliary views. > -- Look and feel > > Other activities > - Weekly automatic importing of data from another accounting database > - Importing of existing event data. > - Importing of product prices and rates, existing staff details, > demonstrator details, > - Finding and setting up a VPS host > - Installing and configuring the site > - Support for a year (occasional changes, bug fixes and helping them > settle in) > - Training materials > > ... and this doesn't even take into account the changes they made > halfway though. I should have been more formal with the spec but I > know them and didn't think it would be necessary. Once bitten > > Appreciate this is a bit finger in the air, but like I said ... > ballparking. > > ALJ -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: fieldsets django
On Mon, Jun 21, 2010 at 12:12 PM, Waleria wrote: > I don't know I'm wondering how to use the fieldsets.can you > help me...how to use the fieldsets...? > Be a bit clearer please. Fieldset is a HTML tag, it has nothing to do with django. It is used to group similar fields and surround them with a nice border. Formsets are in django arrays of forms. If you have one form, and want to repeat it 20 times on one page, then you want a formset. If you do want a formset, documentation is here: http://docs.djangoproject.com/en/1.2/topics/forms/formsets/#topics-forms-formsets Cheers Tom -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
outer join in orm
I have some models that (simplified) look like the following. class Answer(models.Model): id = models.CharField(max_length=32, primary_key=True) text = models.TextField(blank=False) question = models.ForeignKey(Question) candidate = models.ForeignKey(Candidate) class Question(models.Model): id = models.CharField(max_length=32, primary_key=True) text = models.TextField(blank=False) class Candidate(models.Model): id = models.CharField(max_length=32, primary_key=True) name = models.CharField(max_length=32, blank=False) class Race(models.Model): id = models.CharField(max_length=32, primary_key=True) name = models.CharField(max_length=128, blank=False) questions = models.ManyToManyField(Question) candidates = models.ManyToManyField(Candidate) So, a Race has Candidates and Questions, and a Candidate has Answers. Each answer is associated with a Question and a Candidate. Displaying the question associated with an answer is easy: # context variable in view answers = Answer.objects.filter(candidate=candidate) # template code {% for answer in answers %} {{answer.question.text}} {{answer.text}} {% endfor %} >From the point of view of the Candidate, I need to display all the questions, including the ones without Answers. I know how to to do this using raw sql and an outer join. How to do it in the orm? Thanks in advance for any ideas. --Jeff -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
FW: google search
Hi, I am trying to optimize the search of users, as google does. So I thought having a 2. column in DB with a "normalized" version of the string. By normalize I mean convert ä to ae etc. Someone done this before? On my way searching for a solution, I found this lib for a "did you mean" search: http://norvig.com/spell-correct.html Can we integrate this into ORM? and build the "big.txt" from the DB in the DB instead of disk? Or is it too much overhead? I know, haystack can do this for you, but brings in a lot of overhead (like the searchengines) to you, along with a lot of features not all people may need. Any one there with an other idea? regards Henrik >forward of message: >date: 18.06.2010 20:22:29 >from: "Henrik Genssen" >to: "Django users" >subject: google search > >Hi, > >does someone know a simple way or app for a better search like google does it? >Not in the meaning of: did you mean, but ignore chars like ",.-#+? and convert >special chars like ä to ae, ü to ue and so on... > > >regards > >Henrik -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: outer join in orm
On Jun 21, 12:51 pm, JeffH wrote: > I have some models that (simplified) look like the following. > > class Answer(models.Model): > id = models.CharField(max_length=32, primary_key=True) > text = models.TextField(blank=False) > question = models.ForeignKey(Question) > candidate = models.ForeignKey(Candidate) > > class Question(models.Model): > id = models.CharField(max_length=32, primary_key=True) > text = models.TextField(blank=False) > > class Candidate(models.Model): > id = models.CharField(max_length=32, primary_key=True) > name = models.CharField(max_length=32, blank=False) > > class Race(models.Model): > id = models.CharField(max_length=32, primary_key=True) > name = models.CharField(max_length=128, blank=False) > questions = models.ManyToManyField(Question) > candidates = models.ManyToManyField(Candidate) > > So, a Race has Candidates and Questions, and a Candidate has Answers. > Each answer is associated with a Question and a Candidate. Displaying > the question associated with an answer is easy: > > # context variable in view > answers = Answer.objects.filter(candidate=candidate) > > # template code > > {% for answer in answers %} > > {{answer.question.text}} > {{answer.text}} > > {% endfor %} > > > From the point of view of the Candidate, I need to display all the > questions, including the ones without Answers. I know how to to do > this using raw sql and an outer join. How to do it in the orm? > > Thanks in advance for any ideas. > > --Jeff Not quite enough information here to answer. What are you wanting to join? If you just want to display all the questions, why do you need a join at all? -- DR. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: FW: google search
On Mon, Jun 21, 2010 at 1:37 PM, Henrik Genssen wrote: > Hi, > > I am trying to optimize the search of users, as google does. > So I thought having a 2. column in DB with a "normalized" version of the > string. > By normalize I mean convert ä to ae etc. > > Someone done this before? > > On my way searching for a solution, I found this lib for a "did you mean" > search: > http://norvig.com/spell-correct.html > Can we integrate this into ORM? and build the "big.txt" from the DB in the DB > instead of disk? > Or is it too much overhead? > > I know, haystack can do this for you, but brings in a lot of overhead (like > the searchengines) to you, > along with a lot of features not all people may need. > > Any one there with an other idea? > > regards > > Henrik > > This normalization is called stubbing or tokenization in search terminology, and is quite an in-depth topic. If you take a look at the number of tokenizers available in the stock version of solr[1], you'll see why. You rule this out as an option, but you should be looking at the overhead of haystack/solr. The interface to google is simple, and this makes people think that the backend is easy too; it's not. Either plan on spending a lot of time researching search technologies and developing your own solution, or settle for the overhead. Cheers Tom [1] http://wiki.apache.org/solr/AnalyzersTokenizersTokenFilters -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Force ContentType id
I had to clean my application database from old models without losing data. So, I copied my tables to another db, dropped them, run syncdb and copied data back. But the app stopped working, because some tables used GenericRelations and still pointed to the old ContentType; so, I had to change that id manually. Is there a way to force the id of a model in django_content_type table? Or, is there a way to run a syncdb to apply changes without losing data? Thanks. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
escapejs inside {% trans %}
Hi, I had this code in a template file: alert('{% trans "a string" %}') It gave error when translated bacause the translated string had a ' inside. So, I replaced " with ' in the template line and all worked fine. To avoid any problem with 'escape chars', is there a way to escape translated strings, like the 'escapejs' filter tag does? Something like "{% trans "a string" | escapejs %}" Thank you -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: escapejs inside {% trans %}
On Mon, Jun 21, 2010 at 2:17 PM, donato.gr wrote: > Hi, > I had this code in a template file: > alert('{% trans "a string" %}') > > It gave error when translated bacause the translated string had a ' > inside. So, I replaced " with ' in the template line and all worked > fine. > > To avoid any problem with 'escape chars', is there a way to escape > translated strings, like the 'escapejs' filter tag does? > Something like "{% trans "a string" | escapejs %}" > > Thank you > Yes, instead of using {% trans "foo" %}, you can use this alternative form, for use inside an output tag: {{ _("foo")|escapejs }} Cheers Tom -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Mysql-Python error
Ok thanks. I've installed the setuptools but now i get another error. setup_windows.py", line 7, in get_config serverKey = _winreg.OpenKey(_winreg.HKEY_LOCAL_MACHINE, options['registry_key']) WindowsError: [Error 2] The system cannot find the file specified Thanks for all your effort. Regards Eduan Bekker -- On Jun 21, 12:04 pm, Kenneth Gonsalves wrote: > On Monday 21 June 2010 13:04:19 Eduan wrote: > > > When installing Mysql-Python I get this error. > > > Traceback (most recent call last): > > File "setup.py", line 5, in > > from setuptools import setup, Extension > > ImportError: No module named setuptools > > install setuptools > -- > Regards > Kenneth Gonsalves > Senior Associate > NRC-FOSS at AU-KBC -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: outer join in orm
To clarify: Each race has a set of questions. The candidate may have responded to none, some, or all. The answers are linked to the candidate (and to the question). For each candidate, I want to display all the questions, with or without answer. The way it works currently, only the questions with answers get displayed. On Jun 21, 8:41 am, Daniel Roseman wrote: > On Jun 21, 12:51 pm, JeffH wrote: > > > > > I have some models that (simplified) look like the following. > > > class Answer(models.Model): > > id = models.CharField(max_length=32, primary_key=True) > > text = models.TextField(blank=False) > > question = models.ForeignKey(Question) > > candidate = models.ForeignKey(Candidate) > > > class Question(models.Model): > > id = models.CharField(max_length=32, primary_key=True) > > text = models.TextField(blank=False) > > > class Candidate(models.Model): > > id = models.CharField(max_length=32, primary_key=True) > > name = models.CharField(max_length=32, blank=False) > > > class Race(models.Model): > > id = models.CharField(max_length=32, primary_key=True) > > name = models.CharField(max_length=128, blank=False) > > questions = models.ManyToManyField(Question) > > candidates = models.ManyToManyField(Candidate) > > > So, a Race has Candidates and Questions, and a Candidate has Answers. > > Each answer is associated with a Question and a Candidate. Displaying > > the question associated with an answer is easy: > > > # context variable in view > > answers = Answer.objects.filter(candidate=candidate) > > > # template code > > > > {% for answer in answers %} > > > > {{answer.question.text}} > > {{answer.text}} > > > > {% endfor %} > > > > > From the point of view of the Candidate, I need to display all the > > questions, including the ones without Answers. I know how to to do > > this using raw sql and an outer join. How to do it in the orm? > > > Thanks in advance for any ideas. > > > --Jeff > > Not quite enough information here to answer. What are you wanting to > join? If you just want to display all the questions, why do you need a > join at all? > -- > DR. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
djapian not working with apach2
hi all, im using djapian for my search , it seems to work fine when i run it in django development server but when i configure my sites to use apach2 im always getting this error when i try to search : "Caught OSError while rendering: [Errno 13] Permission denied: '/ index'" i am sure it is not a folder permission issue because when i run my sites using ./manage.py runserver i get the results of my search. im using mod_wsgi my locasites.conf : # --- ServerName mysite.name ServerAlias mysitealias WSGIScriptAlias / "/path/to/my/apache/file.wsgi" Allow from all Alias /site_media/ "/path/to/mysite/media/" Order allow,deny Options Indexes FollowSymLinks Allow from all IndexOptions FancyIndexing Alias /media/ "/usr/local/lib/python2.6/dist-packages/django/ contrib/admin/media/" Order allow,deny Options Indexes FollowSymLinks Allow from all IndexOptions FancyIndexing this is repeated for all the sites. can anyone help with issue regards -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: How much would you charge for this? £5k? £15k? £50k?
It sounds like your project is pretty fully featured and if you claim to be "inexperienced" in Django development this much work is pretty impressive on a part-time basis over 6 months! Currently the Django project I am working on has taken over 2.5 years (and is ongoing). Although we don't just do Django, it's what we do most of the time. Our application has 213 models with 78742 lines of python code. I would estimate (although this is a bit of a guess) that the developer cost for this has been approximately £350k. You might be able to scale that to your workload. Hope that helps, Euan On Jun 21, 10:12 am, ALJ wrote: > I'm just starting out with Django so using an hourly rate isn't really > applicable because I'm going to be much slower that a 'real' > developer. So far I've spent about 6 months part time. > > What kind of ballpark amounts would people suggest this is worth? > > I'm not going to tell you how much they think it was ... well maybe > I'll tell you later. I'm trying to help them out so it's considerably > cheaper than I think it should be. > > What is it? > The application is helps the sales staff organize product > demonstrations around the country. They can book demonstrators to do > an event. The demonstrators do the events and then enter the details > of how it went. The system provides invoice generation, event tracking > and custom reporting. > > Features > - Dynamic questionnaire and report form generation into pdf. > - Dynamic invoice generation into pdf. > - Work-flow with page locking, rollback and automatic email generation > on status change. > - Daily (and horribly complex) automatic summary excel reports > - Sales and questionnaire summary reports > > - Designing and building the site > -- Models (about 32) > -- Setting up the admin interface > -- 12 key views plus goodness knows how many auxiliary views. > -- Look and feel > > Other activities > - Weekly automatic importing of data from another accounting database > - Importing of existing event data. > - Importing of product prices and rates, existing staff details, > demonstrator details, > - Finding and setting up a VPS host > - Installing and configuring the site > - Support for a year (occasional changes, bug fixes and helping them > settle in) > - Training materials > > ... and this doesn't even take into account the changes they made > halfway though. I should have been more formal with the spec but I > know them and didn't think it would be necessary. Once bitten > > Appreciate this is a bit finger in the air, but like I said ... > ballparking. > > ALJ -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: outer join in orm
There may well be a better way to do this, especially since it's been a good year since I was struggling with this myself. (Very similar case to yours, different subject matter of course.) The way I ended up doing it was to use a template tag and some list comprehensions to whittle things down. E.g.: questions = Questions.objects.all() answers = Answers.objects.filter(candidate=my_candidate) questions_and_answers = [(q, [a for a in answers if a.question = q]) for q in questions] ...which should give you a list of (question, ) tuples. On Jun 21, 10:00 am, JeffH wrote: > To clarify: Each race has a set of questions. The candidate may have > responded to none, some, or all. The answers are linked to the > candidate (and to the question). For each candidate, I want to display > all the questions, with or without answer. The way it works currently, > only the questions with answers get displayed. > > On Jun 21, 8:41 am, Daniel Roseman wrote: > > > > > On Jun 21, 12:51 pm, JeffH wrote: > > > > I have some models that (simplified) look like the following. > > > > class Answer(models.Model): > > > id = models.CharField(max_length=32, primary_key=True) > > > text = models.TextField(blank=False) > > > question = models.ForeignKey(Question) > > > candidate = models.ForeignKey(Candidate) > > > > class Question(models.Model): > > > id = models.CharField(max_length=32, primary_key=True) > > > text = models.TextField(blank=False) > > > > class Candidate(models.Model): > > > id = models.CharField(max_length=32, primary_key=True) > > > name = models.CharField(max_length=32, blank=False) > > > > class Race(models.Model): > > > id = models.CharField(max_length=32, primary_key=True) > > > name = models.CharField(max_length=128, blank=False) > > > questions = models.ManyToManyField(Question) > > > candidates = models.ManyToManyField(Candidate) > > > > So, a Race has Candidates and Questions, and a Candidate has Answers. > > > Each answer is associated with a Question and a Candidate. Displaying > > > the question associated with an answer is easy: > > > > # context variable in view > > > answers = Answer.objects.filter(candidate=candidate) > > > > # template code > > > > > > {% for answer in answers %} > > > > > > {{answer.question.text}} > > > {{answer.text}} > > > > > > {% endfor %} > > > > > > > From the point of view of the Candidate, I need to display all the > > > questions, including the ones without Answers. I know how to to do > > > this using raw sql and an outer join. How to do it in the orm? > > > > Thanks in advance for any ideas. > > > > --Jeff > > > Not quite enough information here to answer. What are you wanting to > > join? If you just want to display all the questions, why do you need a > > join at all? > > -- > > DR. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Price fixing (was Re: How much would you charge for this? £5k? £15k? £50k?)
On Mon, Jun 21, 2010 at 2:12 AM, ALJ wrote: > I'm just starting out with Django so using an hourly rate isn't really > applicable because I'm going to be much slower that a 'real' > developer. So far I've spent about 6 months part time. > > What kind of ballpark amounts would people suggest this is worth? I don't know about the law elsewhere, but in the United States, having a discussion with other vendors on what to charge clients opens you up to prosecution for price fixing. It almost certainly should be a banned topic here. For a fairly good description of the issue, look at the HTML Writer's Guild guidelines: http://www.hwg.org/resources/faqs/priceFAQ.html Nick -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: outer join in orm
That looks reasonable... but I wonder if the ORM can do it directly somehow. Anyone? On Jun 21, 10:14 am, Scott Gould wrote: > There may well be a better way to do this, especially since it's been > a good year since I was struggling with this myself. (Very similar > case to yours, different subject matter of course.) > > The way I ended up doing it was to use a template tag and some list > comprehensions to whittle things down. E.g.: > > questions = Questions.objects.all() > answers = Answers.objects.filter(candidate=my_candidate) > > questions_and_answers = [(q, [a for a in answers if a.question = q]) > for q in questions] > > ...which should give you a list of (question, ) > tuples. > > On Jun 21, 10:00 am, JeffH wrote: > > > To clarify: Each race has a set of questions. The candidate may have > > responded to none, some, or all. The answers are linked to the > > candidate (and to the question). For each candidate, I want to display > > all the questions, with or without answer. The way it works currently, > > only the questions with answers get displayed. > > > On Jun 21, 8:41 am, Daniel Roseman wrote: > > > > On Jun 21, 12:51 pm, JeffH wrote: > > > > > I have some models that (simplified) look like the following. > > > > > class Answer(models.Model): > > > > id = models.CharField(max_length=32, primary_key=True) > > > > text = models.TextField(blank=False) > > > > question = models.ForeignKey(Question) > > > > candidate = models.ForeignKey(Candidate) > > > > > class Question(models.Model): > > > > id = models.CharField(max_length=32, primary_key=True) > > > > text = models.TextField(blank=False) > > > > > class Candidate(models.Model): > > > > id = models.CharField(max_length=32, primary_key=True) > > > > name = models.CharField(max_length=32, blank=False) > > > > > class Race(models.Model): > > > > id = models.CharField(max_length=32, primary_key=True) > > > > name = models.CharField(max_length=128, blank=False) > > > > questions = models.ManyToManyField(Question) > > > > candidates = models.ManyToManyField(Candidate) > > > > > So, a Race has Candidates and Questions, and a Candidate has Answers. > > > > Each answer is associated with a Question and a Candidate. Displaying > > > > the question associated with an answer is easy: > > > > > # context variable in view > > > > answers = Answer.objects.filter(candidate=candidate) > > > > > # template code > > > > > > > > {% for answer in answers %} > > > > > > > > {{answer.question.text}} > > > > {{answer.text}} > > > > > > > > {% endfor %} > > > > > > > > > From the point of view of the Candidate, I need to display all the > > > > questions, including the ones without Answers. I know how to to do > > > > this using raw sql and an outer join. How to do it in the orm? > > > > > Thanks in advance for any ideas. > > > > > --Jeff > > > > Not quite enough information here to answer. What are you wanting to > > > join? If you just want to display all the questions, why do you need a > > > join at all? > > > -- > > > DR. > > -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
optional ForeignKey
Hi, I'm trying to make model that has itself as a foreign key, in an attempt to store a reverse tree in Django. However, I can't find a way to set a default value to models.ForeignKey or make it optional. My model is like this: class Node(models.Model): name = models.CharField(max_length=100) parent = models.ForeignKey('self') runserver doesn't complain, but whenever I try to enter data to the model with Django's admin interface I get a "This field is required." message, and it want's me to select a entry, but there are none. -- Magnus -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: optional ForeignKey
You want: parent = models.ForeignKey('self', null=True, blank=True) On Jun 21, 3:37 pm, Magnus Valle wrote: > Hi, > I'm trying to make model that has itself as a foreign key, in an > attempt to store a reverse tree in Django. > However, I can't find a way to set a default value to > models.ForeignKey or make it optional. > > My model is like this: > class Node(models.Model): > name = models.CharField(max_length=100) > parent = models.ForeignKey('self') > > runserver doesn't complain, but whenever I try to enter data to the > model with Django's admin interface I get a "This field is required." > message, and it want's me to select a entry, but there are none. > > -- > Magnus -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: optional ForeignKey
On Mon, Jun 21, 2010 at 10:37 AM, Magnus Valle wrote: > Hi, > I'm trying to make model that has itself as a foreign key, in an > attempt to store a reverse tree in Django. > However, I can't find a way to set a default value to > models.ForeignKey or make it optional. > > My model is like this: > class Node(models.Model): >name = models.CharField(max_length=100) >parent = models.ForeignKey('self') > > runserver doesn't complain, but whenever I try to enter data to the > model with Django's admin interface I get a "This field is required." > message, and it want's me to select a entry, but there are none. > You make a ForeignKey field optional by specifying blank=True, null=True: http://docs.djangoproject.com/en/1.2/ref/models/fields/#null Karen -- http://tracey.org/kmt/ -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
File upload from python client to Django app
Hello to all, I'm trying to do a POST from a python client to a Django webapp using urllib2 but I'm getting http 403 error. On the Django side I'm using a Form so I suspect the problem is {% csrf_token %} (csrf middleware enabled) which I can't provide from the client side. Is there other way to do this? Your advice is much appreciated, Regards, Sorin -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: File upload from python client to Django app
urllib2 can handle cookies and therefore you should be able to handle the login. It will probably be a fair bit of work to get the client to submit the various parts, but I'm sure I've seen some examples around on how to do such a thing. Euan On Jun 21, 3:52 pm, srn wrote: > Hello to all, > > I'm trying to do a POST from a python client to a Django webapp using > urllib2 but I'm getting http 403 error. > On the Django side I'm using a Form so I suspect the problem is {% > csrf_token %} (csrf middleware enabled) which I can't provide from the > client side. > > Is there other way to do this? > > Your advice is much appreciated, > Regards, > Sorin -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Price fixing (was Re: How much would you charge for this? £5k? £15k? £50k?)
I'm no master of the law, I have a lawyer for that, but a quick read about price fixing seems to suggest that this is not that at all. Rather, price fixing is an agreement made so that competition in a market is lost by vendors agreeing upon a rate to sell a product or service for current and future clients, making it impossible for them (the clients) to seek better deals elsewhere (or for the market to be fairly regulated by supply, demand, and so forth). This is not a case of that, because ALJ is not trying to fix the market at a particular price (i.e., he is not saying "Calling all Django Developers; cap your rates at <$x>/hour so we are all equal.") To the Frequently Asked Question entry that you point to, it mentions that "several brokers in DC were successfully prosecuted for simply discussing an increase of fees at a dinner meeting." That appears to be specific to multiple competitors seeking to agree upon a rate so that they are all equal in their pricing (and therefore do not compete based upon that), rather than a case in which an up-and-coming broker is simply trying to learn how prices are determined. Regardless, it does not seem like ALJ is trying to formulate a charge for this current project, which is already underway (as indicated by there being such a plethora of changes only halfway through). Instead, it seems to me as if ALJ is merely trying to educate himself on how experienced developers determine pricing, so that he may understand what sort of expenses to take into account to accurately judge the worth of a project. Just my two cents. If this is on the border of being illegal (or otherwise off-topic for this group), then the topic should by all means be dropped, but I do not think that any activity as indicated by my reading about price fixing is taking place. To ALJ, it is difficult to determine a price for these specific requirements (especially when changes are being made after). I would recommend that you consider how this project will add to your reputation and education, especially since you are inexperienced with this framework (and perhaps the language). Newer developers will often have to 'sacrifice' a higher pay so that they may build their portfolio and learn more about what common jobs require they know. As they do this and continue to prove themselves worthy, they can raise their rates--not to something that necessarily matches what everyone else is charging, but to what they feel is representative of their time spent, and knowledge used, on the project. Sincerely, Michael A. Schade On Jun 21, 2010, at 9:19 AM, Nick Arnett wrote: On Mon, Jun 21, 2010 at 2:12 AM, ALJ wrote: > I'm just starting out with Django so using an hourly rate isn't really > applicable because I'm going to be much slower that a 'real' > developer. So far I've spent about 6 months part time. > > What kind of ballpark amounts would people suggest this is worth? I don't know about the law elsewhere, but in the United States, having a discussion with other vendors on what to charge clients opens you up to prosecution for price fixing. It almost certainly should be a banned topic here. For a fairly good description of the issue, look at the HTML Writer's Guild guidelines: http://www.hwg.org/resources/faqs/priceFAQ.html Nick -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: optional ForeignKey
Ah, OK, Thanks! I didn't know that blank and null are available for all field-types, I should have known. Thanks!! On Mon, Jun 21, 2010 at 15:41, Karen Tracey wrote: > On Mon, Jun 21, 2010 at 10:37 AM, Magnus Valle wrote: >> >> Hi, >> I'm trying to make model that has itself as a foreign key, in an >> attempt to store a reverse tree in Django. >> However, I can't find a way to set a default value to >> models.ForeignKey or make it optional. >> >> My model is like this: >> class Node(models.Model): >> name = models.CharField(max_length=100) >> parent = models.ForeignKey('self') >> >> runserver doesn't complain, but whenever I try to enter data to the >> model with Django's admin interface I get a "This field is required." >> message, and it want's me to select a entry, but there are none. > > > You make a ForeignKey field optional by specifying blank=True, null=True: > > http://docs.djangoproject.com/en/1.2/ref/models/fields/#null > > Karen > -- > http://tracey.org/kmt/ > > -- > You received this message because you are subscribed to the Google Groups > "Django users" group. > To post to this group, send email to django-us...@googlegroups.com. > To unsubscribe from this group, send email to > django-users+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/django-users?hl=en. > -- Magnus -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: outer join in orm
I hope you get an ORM answer, too. I'm a newbie following this thread and this sounds like the type of problem I have run into a couple of times already. On Mon, Jun 21, 2010 at 9:37 AM, JeffH wrote: > That looks reasonable... but I wonder if the ORM can do it directly > somehow. Anyone? > > On Jun 21, 10:14 am, Scott Gould wrote: > > There may well be a better way to do this, especially since it's been > > a good year since I was struggling with this myself. (Very similar > > case to yours, different subject matter of course.) > > > > The way I ended up doing it was to use a template tag and some list > > comprehensions to whittle things down. E.g.: > > > > questions = Questions.objects.all() > > answers = Answers.objects.filter(candidate=my_candidate) > > > > questions_and_answers = [(q, [a for a in answers if a.question = q]) > > for q in questions] > > > > ...which should give you a list of (question, ) > > tuples. > > > > On Jun 21, 10:00 am, JeffH wrote: > > > > > To clarify: Each race has a set of questions. The candidate may have > > > responded to none, some, or all. The answers are linked to the > > > candidate (and to the question). For each candidate, I want to display > > > all the questions, with or without answer. The way it works currently, > > > only the questions with answers get displayed. > > > > > On Jun 21, 8:41 am, Daniel Roseman wrote: > > > > > > On Jun 21, 12:51 pm, JeffH wrote: > > > > > > > I have some models that (simplified) look like the following. > > > > > > > class Answer(models.Model): > > > > > id = models.CharField(max_length=32, primary_key=True) > > > > > text = models.TextField(blank=False) > > > > > question = models.ForeignKey(Question) > > > > > candidate = models.ForeignKey(Candidate) > > > > > > > class Question(models.Model): > > > > > id = models.CharField(max_length=32, primary_key=True) > > > > > text = models.TextField(blank=False) > > > > > > > class Candidate(models.Model): > > > > > id = models.CharField(max_length=32, primary_key=True) > > > > > name = models.CharField(max_length=32, blank=False) > > > > > > > class Race(models.Model): > > > > > id = models.CharField(max_length=32, primary_key=True) > > > > > name = models.CharField(max_length=128, blank=False) > > > > > questions = models.ManyToManyField(Question) > > > > > candidates = models.ManyToManyField(Candidate) > > > > > > > So, a Race has Candidates and Questions, and a Candidate has > Answers. > > > > > Each answer is associated with a Question and a Candidate. > Displaying > > > > > the question associated with an answer is easy: > > > > > > > # context variable in view > > > > > answers = Answer.objects.filter(candidate=candidate) > > > > > > > # template code > > > > > > > > > > {% for answer in answers %} > > > > > > > > > > {{answer.question.text}} > > > > > {{answer.text}} > > > > > > > > > > {% endfor %} > > > > > > > > > > > > From the point of view of the Candidate, I need to display all the > > > > > questions, including the ones without Answers. I know how to to do > > > > > this using raw sql and an outer join. How to do it in the orm? > > > > > > > Thanks in advance for any ideas. > > > > > > > --Jeff > > > > > > Not quite enough information here to answer. What are you wanting to > > > > join? If you just want to display all the questions, why do you need > a > > > > join at all? > > > > -- > > > > DR. > > > > > > -- > You received this message because you are subscribed to the Google Groups > "Django users" group. > To post to this group, send email to django-us...@googlegroups.com. > To unsubscribe from this group, send email to > django-users+unsubscr...@googlegroups.com > . > For more options, visit this group at > http://groups.google.com/group/django-users?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: outer join in orm
AFAIK there is no direct way to do this sort of thing in a single query. select_related will only get foreign key relations into the query so the ORM will always do an SQL query for each row in your many to many. In these types of situations I tend to select everything I need and then run some sort of pre-processing to put the two sets together, thus ensuring only 2 queries rather than n+1 (where n is the number of items in your original queryset). Scott Gould's answer is about as good as you'll get I reckon. On Jun 21, 3:37 pm, JeffH wrote: > That looks reasonable... but I wonder if the ORM can do it directly > somehow. Anyone? > > On Jun 21, 10:14 am, Scott Gould wrote: > > > There may well be a better way to do this, especially since it's been > > a good year since I was struggling with this myself. (Very similar > > case to yours, different subject matter of course.) > > > The way I ended up doing it was to use a template tag and some list > > comprehensions to whittle things down. E.g.: > > > questions = Questions.objects.all() > > answers = Answers.objects.filter(candidate=my_candidate) > > > questions_and_answers = [(q, [a for a in answers if a.question = q]) > > for q in questions] > > > ...which should give you a list of (question, ) > > tuples. > > > On Jun 21, 10:00 am, JeffH wrote: > > > > To clarify: Each race has a set of questions. The candidate may have > > > responded to none, some, or all. The answers are linked to the > > > candidate (and to the question). For each candidate, I want to display > > > all the questions, with or without answer. The way it works currently, > > > only the questions with answers get displayed. > > > > On Jun 21, 8:41 am, Daniel Roseman wrote: > > > > > On Jun 21, 12:51 pm, JeffH wrote: > > > > > > I have some models that (simplified) look like the following. > > > > > > class Answer(models.Model): > > > > > id = models.CharField(max_length=32, primary_key=True) > > > > > text = models.TextField(blank=False) > > > > > question = models.ForeignKey(Question) > > > > > candidate = models.ForeignKey(Candidate) > > > > > > class Question(models.Model): > > > > > id = models.CharField(max_length=32, primary_key=True) > > > > > text = models.TextField(blank=False) > > > > > > class Candidate(models.Model): > > > > > id = models.CharField(max_length=32, primary_key=True) > > > > > name = models.CharField(max_length=32, blank=False) > > > > > > class Race(models.Model): > > > > > id = models.CharField(max_length=32, primary_key=True) > > > > > name = models.CharField(max_length=128, blank=False) > > > > > questions = models.ManyToManyField(Question) > > > > > candidates = models.ManyToManyField(Candidate) > > > > > > So, a Race has Candidates and Questions, and a Candidate has Answers. > > > > > Each answer is associated with a Question and a Candidate. Displaying > > > > > the question associated with an answer is easy: > > > > > > # context variable in view > > > > > answers = Answer.objects.filter(candidate=candidate) > > > > > > # template code > > > > > > > > > > {% for answer in answers %} > > > > > > > > > > {{answer.question.text}} > > > > > {{answer.text}} > > > > > > > > > > {% endfor %} > > > > > > > > > > > From the point of view of the Candidate, I need to display all the > > > > > questions, including the ones without Answers. I know how to to do > > > > > this using raw sql and an outer join. How to do it in the orm? > > > > > > Thanks in advance for any ideas. > > > > > > --Jeff > > > > > Not quite enough information here to answer. What are you wanting to > > > > join? If you just want to display all the questions, why do you need a > > > > join at all? > > > > -- > > > > DR. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: How much would you charge for this? £5k? £15k? £50k?
Hi Euan, Cheers for that. It's my first Django project and I think in hindsight I should have started on something a little easier. Nevermind. It's been a good learning experience. Before they told me the spec, they said they thought it would cost about £3k! Cheers ALJ On Jun 21, 4:12 pm, "euan.godd...@googlemail.com" wrote: > It sounds like your project is pretty fully featured and if you claim > to be "inexperienced" in Django development this much work is pretty > impressive on a part-time basis over 6 months! > > Currently the Django project I am working on has taken over 2.5 years > (and is ongoing). Although we don't just do Django, it's what we do > most of the time. Our application has 213 models with 78742 lines of > python code. I would estimate (although this is a bit of a guess) that > the developer cost for this has been approximately £350k. > > You might be able to scale that to your workload. > > Hope that helps, Euan > > On Jun 21, 10:12 am, ALJ wrote: > > > I'm just starting out with Django so using an hourly rate isn't really > > applicable because I'm going to be much slower that a 'real' > > developer. So far I've spent about 6 months part time. > > > What kind of ballpark amounts would people suggest this is worth? > > > I'm not going to tell you how much they think it was ... well maybe > > I'll tell you later. I'm trying to help them out so it's considerably > > cheaper than I think it should be. > > > What is it? > > The application is helps the sales staff organize product > > demonstrations around the country. They can book demonstrators to do > > an event. The demonstrators do the events and then enter the details > > of how it went. The system provides invoice generation, event tracking > > and custom reporting. > > > Features > > - Dynamic questionnaire and report form generation into pdf. > > - Dynamic invoice generation into pdf. > > - Work-flow with page locking, rollback and automatic email generation > > on status change. > > - Daily (and horribly complex) automatic summary excel reports > > - Sales and questionnaire summary reports > > > - Designing and building the site > > -- Models (about 32) > > -- Setting up the admin interface > > -- 12 key views plus goodness knows how many auxiliary views. > > -- Look and feel > > > Other activities > > - Weekly automatic importing of data from another accounting database > > - Importing of existing event data. > > - Importing of product prices and rates, existing staff details, > > demonstrator details, > > - Finding and setting up a VPS host > > - Installing and configuring the site > > - Support for a year (occasional changes, bug fixes and helping them > > settle in) > > - Training materials > > > ... and this doesn't even take into account the changes they made > > halfway though. I should have been more formal with the spec but I > > know them and didn't think it would be necessary. Once bitten > > > Appreciate this is a bit finger in the air, but like I said ... > > ballparking. > > > ALJ -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Actions after HttpResponse rendered?
For one, I want to know if request_finished works here. On Jun 21, 3:39 am, Daniel Roseman wrote: > On Jun 21, 6:46 am, DaNmarner wrote: > > > There's a similar question as mine on stackoverflow.com: > > >http://stackoverflow.com/questions/1081340/how-do-you-do-something-af... > > > and there isn't a satisfactory answer there. > > > Basically, how do I do some thing after a view returns the response? > > Does request_finished enables that kind of operations? > > Why do you think none of those answers is satisfactory? There are a > few useful recommendations on that page. What exactly do you need that > isn't covered? > -- > DR. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
HOW TO? multiple sites, one virtual host, routing settings.py?
I'll soon be deploying a project that will need to be able to dynamically add domains. Each domain will have different users, separate data, and a different SITE_ID, but will all run off a single Django instance. The data will all be housed in a single database, since all domains' data will need to be accessible together via a global admin panel. I'm thinking that the simplest way to accomplish this on the hosting level would be a wildcard VirtualHost, and a separate settings.py for each site that simply specifies the SITE_ID and pulls in the global settings. Is there an easy way to route each domain to a separate settings file using a single virtual host? (I'm open to different server models -- leaning towards mod_wsgi but happy to use FCGI or mod_python if they'll make this more straightforward.) -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
ModelForm with ManyToManyField on the other side
class Material(models.Model): products = ManyToManyField('Product', related_name='materials') class Products(models.Model): ... class ProductForm(forms.ModelForm): class Meta: model = Product fields = ('materials', ) I want to do this. I saw this discussion: http://groups.google.com/group/django-users/browse_thread/thread/49213bf57a6a3033/cceb6912ad43fca0?show_docid=cceb6912ad43fca0&pli=1 And, I tried this snippet: http://djangosnippets.org/snippets/1295/ The related names of this snippet make no sense. If they are made to make sense, then there would be an accessor clash. Without the class, the accessors are redundant at best... Has any progress been made on this convenience or is the recommended course just to create a non-Model form and make a save method? -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: djapian not working with apach2
I would guess that you are trying to access /index with the webserver user but that is owned by another user and the user that owns the web process has not the sufficient permissions to do the attempted operation. Set the permissions on the directory accordingly, perhaps ownership as well. You could just nuke the permissions with a chmod 777 /index (or so) if security is not crucial. Otherwise you need to give permissions to the dir to your webserver user in a less nukular way. You could also run the wsgi process(es) as the user of your choice using perhaps http://code.google.com/p/modwsgi/wiki/ConfigurationDirectives#WSGIDaemonProcess hope that helps. On Jun 21, 10:03 am, watad wrote: > hi all, > > im using djapian for my search , it seems to work fine when i run it > in django development server > but when i configure my sites to use apach2 im always getting this > error when i try to search : > > "Caught OSError while rendering: [Errno 13] Permission denied: '/ > index'" > i am sure it is not a folder permission issue because when i run my > sites using ./manage.py runserver i get the results of my search. > > im using mod_wsgi > > my locasites.conf : > > # --- > > > ServerName mysite.name > ServerAlias mysitealias > > WSGIScriptAlias / "/path/to/my/apache/file.wsgi" > > Allow from all > > > Alias /site_media/ "/path/to/mysite/media/" > > Order allow,deny > Options Indexes FollowSymLinks > Allow from all > IndexOptions FancyIndexing > > > Alias /media/ "/usr/local/lib/python2.6/dist-packages/django/ > contrib/admin/media/" > admin/media/"> > Order allow,deny > Options Indexes FollowSymLinks > Allow from all > IndexOptions FancyIndexing > > > > > this is repeated for all the sites. > > can anyone help with issue > regards -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Running django-admin.py Commands without a Shell
I am working with my virtual hosting provider to enable him support Django. I have used him for ages, and having converted myself to Django would like to help establish another hosting provider with support for Django. I have a configuration for his servers and virtual hosting environment that works well, enabling the application to be developed on a development server using Django's 'runserver', and then transferred to the virtual hosting environment where the production service would run. I now need to work out how best to execute the various commands provided by django-admin.py. The hosted environment provides no shell access, only FTP to copy files to the site and phpMyAdmin to manage the database tables. This is basically a security feature. I would like to be able to execute django-admin.py through a web interface, ideally capturing the output and displaying it back to the user. Has this ever been tried before? Does anybody know of a package doing this? Am I crazy? Some insight from the community would be useful. Thanks in advance. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
How to map url **kwargs
First I'm new 2 django and have made rapid progress building my app based on the tutorial. As soon as I get it a little better, I'll clean it up and remove the "mysite/polls" references. I have a series of url's like this /mysite/myapp/datagrid/clients?letter=A /mysite/myapp/datagrid/reports /mysite/myapp/datagrid/reports?client=LA12345 /mysite/myapp/datagrid/stores/userid=mary I would like to map these to the same view.py method def datagrid(request, gridtype, **options): #where gridtype is one of clients, reports, stores #And options contains any parameters in the URL I would like to NOT define the legal options in the URL, because that gives me two places to define them (3 if you count the client) and frankly I'm not that skilled at regex. I've gotten this far, which maps the gridtype, but cannot get the parameters, even if I explicitly name them. Can someone explain what I'm doing wrong? Mysite/polls/urls.py contains urlpatterns = patterns('mysite.polls.views', (r'^datagrid/([a-z]*)/', 'datagrid'), ... ) And mysite/urls.py contains urlpatterns = patterns('', (r'^myapp/', include('mysite.polls.urls') ), ) -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: djapian not working with apach2
On Jun 22, 12:03 am, watad wrote: > hi all, > > im using djapian for my search , it seems to work fine when i run it > in django development server > but when i configure my sites to use apach2 im always getting this > error when i try to search : > > "Caught OSError while rendering: [Errno 13] Permission denied: '/ > index'" > i am sure it is not a folder permission issue because when i run my > sites using ./manage.py runserver i get the results of my search. > > im using mod_wsgi > > my locasites.conf : > > # --- > > > ServerName mysite.name > ServerAlias mysitealias > > WSGIScriptAlias / "/path/to/my/apache/file.wsgi" > > Allow from all > > > Alias /site_media/ "/path/to/mysite/media/" > > Order allow,deny > Options Indexes FollowSymLinks > Allow from all > IndexOptions FancyIndexing > > > Alias /media/ "/usr/local/lib/python2.6/dist-packages/django/ > contrib/admin/media/" > admin/media/"> > Order allow,deny > Options Indexes FollowSymLinks > Allow from all > IndexOptions FancyIndexing > > > > > this is repeated for all the sites. > > can anyone help with issue Don't use relative path names in your code, you must use absolute path names. As the current working directory under Apache is usually '/', relative path names will resolve relative to that and not your site directory as with runserver. Thus, if you have simple 'index' in your code as relative path name, that will resolve to '/index' and because Apache user cannot write to '/' directory you will get an OSError like you are seeing. Graham -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Force ContentType id
On Mon, Jun 21, 2010 at 8:49 PM, donato.gr wrote: > I had to clean my application database from old models without losing > data. > So, I copied my tables to another db, dropped them, run syncdb and > copied data back. > But the app stopped working, because some tables used GenericRelations > and still pointed to the old ContentType; so, I had to change that id > manually. > > Is there a way to force the id of a model in django_content_type > table? No - the content type handling is completely automated and non-optional. There's also no way to force a given model to have a specific content type id. However, you may be able to correct the problem using fixtures. Either dump the contenttypes from your old database; if you don't have the old database anymore, then dump the contenttypes of the new database into a fixture, and manually modify the primary keys. If you're using a database without referential integrity, you may be able to simply dump the current contents of the contenttypes table and load your corrected fixture. If you're using Postgres, this approach will cacade delete any foreign keys on ContentType, so you'll need to dump the entire database *except* for the contenttype table, load your fixture, then run sycndb to get the remaining tables. syncdb won't create new contenttypes if a record already exists, so it will use the contenttypes from your fixture. > Or, is there a way to run a syncdb to apply changes without losing > data? I'm not sure what you're asking here -- syncdb is *never* destructive. Running syncdb should never result in data loss. Yours, Russ Magee %-) -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Weekly rss feed
Hello all, i tried searching for a solution to this but didn't find it. If it's answered somewhere, please point me in the right direction :) I was wondering how to create a weekly feed for django. Lets say i have a table of objects that gets added to all week long. I'd like to allow people to subscribe to a feed that would give a single update with all items that were added that week. Since the client doesn't send anything about when it last checked for updates, it's hard to determine if the requesting client needs to be given an update or not. With a podcast or blog, you just post the new item each week and it works fine, but for something that needs to pool updates for a given time range is not working out. Is there a common way to do this? Thanks -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Running django-admin.py Commands without a Shell
On Tue, Jun 22, 2010 at 4:08 AM, maxweld wrote: > I am working with my virtual hosting provider to enable him support > Django. I have used him for ages, and having converted myself to > Django would like to help establish another hosting provider with > support for Django. > > I have a configuration for his servers and virtual hosting environment > that works well, enabling the application to be developed on a > development server using Django's 'runserver', and then transferred to > the virtual hosting environment where the production service would > run. > > I now need to work out how best to execute the various commands > provided by django-admin.py. The hosted environment provides no shell > access, only FTP to copy files to the site and phpMyAdmin to manage > the database tables. This is basically a security feature. There is a way to do this, but for some reason it doesn't appear to be documented (which is itself a bug that should be logged). However, the technique is mentioned in passing in the 1.0 porting guide: http://docs.djangoproject.com/en/dev/releases/1.0-porting-guide/#running-management-commands-from-your-code Ignore the old-style syntax, and just look at new-style management.call_command syntax. That allows you to call any management command you want, with whatever command-line arguments you want. > I would like to be able to execute django-admin.py through a web > interface, ideally capturing the output and displaying it back to the > user. Has this ever been tried before? Does anybody know of a package > doing this? Am I crazy? The output capture is the only difficult part; historically, admin commands have directly written out stdout. You can work around this with some monkeypatching of sys.stdout/stderr -- it's not pretty, but it does work. The good news is that in trunk, we've started to rectify this. We've added self.stdout and self.stderr to management commands; these act as mirrors of sys.stdout and sys.stderr by default, but you can programatically set them to be any other stream you want. See http://docs.djangoproject.com/en/dev/howto/custom-management-commands/ for usage, and the fixtures modeltest for an example of usage (and, for that matter, of an example of usage of call_command). Yours, Russ Magee %-) -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: outer join in orm
Doing a nested list comp has to be less efficient than an outer join done at the db level. For my issue, it's a relatively small data set, so I'd rather be more pythonic than eg running raw sql. Nonetheless, I view this as a weakness in Django's ORM, and would plead with TPTB to provide a solution, not that it would affect my current problem. On Jun 21, 11:46 am, "euan.godd...@googlemail.com" wrote: > AFAIK there is no direct way to do this sort of thing in a single > query. select_related will only get foreign key relations into the > query so the ORM will always do an SQL query for each row in your many > to many. In these types of situations I tend to select everything I > need and then run some sort of pre-processing to put the two sets > together, thus ensuring only 2 queries rather than n+1 (where n is the > number of items in your original queryset). > > Scott Gould's answer is about as good as you'll get I reckon. > > On Jun 21, 3:37 pm, JeffH wrote: > > > That looks reasonable... but I wonder if the ORM can do it directly > > somehow. Anyone? > > > On Jun 21, 10:14 am, Scott Gould wrote: > > > > There may well be a better way to do this, especially since it's been > > > a good year since I was struggling with this myself. (Very similar > > > case to yours, different subject matter of course.) > > > > The way I ended up doing it was to use a template tag and some list > > > comprehensions to whittle things down. E.g.: > > > > questions = Questions.objects.all() > > > answers = Answers.objects.filter(candidate=my_candidate) > > > > questions_and_answers = [(q, [a for a in answers if a.question = q]) > > > for q in questions] > > > > ...which should give you a list of (question, ) > > > tuples. > > > > On Jun 21, 10:00 am, JeffH wrote: > > > > > To clarify: Each race has a set of questions. The candidate may have > > > > responded to none, some, or all. The answers are linked to the > > > > candidate (and to the question). For each candidate, I want to display > > > > all the questions, with or without answer. The way it works currently, > > > > only the questions with answers get displayed. > > > > > On Jun 21, 8:41 am, Daniel Roseman wrote: > > > > > > On Jun 21, 12:51 pm, JeffH wrote: > > > > > > > I have some models that (simplified) look like the following. > > > > > > > class Answer(models.Model): > > > > > > id = models.CharField(max_length=32, primary_key=True) > > > > > > text = models.TextField(blank=False) > > > > > > question = models.ForeignKey(Question) > > > > > > candidate = models.ForeignKey(Candidate) > > > > > > > class Question(models.Model): > > > > > > id = models.CharField(max_length=32, primary_key=True) > > > > > > text = models.TextField(blank=False) > > > > > > > class Candidate(models.Model): > > > > > > id = models.CharField(max_length=32, primary_key=True) > > > > > > name = models.CharField(max_length=32, blank=False) > > > > > > > class Race(models.Model): > > > > > > id = models.CharField(max_length=32, primary_key=True) > > > > > > name = models.CharField(max_length=128, blank=False) > > > > > > questions = models.ManyToManyField(Question) > > > > > > candidates = models.ManyToManyField(Candidate) > > > > > > > So, a Race has Candidates and Questions, and a Candidate has > > > > > > Answers. > > > > > > Each answer is associated with a Question and a Candidate. > > > > > > Displaying > > > > > > the question associated with an answer is easy: > > > > > > > # context variable in view > > > > > > answers = Answer.objects.filter(candidate=candidate) > > > > > > > # template code > > > > > > > > > > > > {% for answer in answers %} > > > > > > > > > > > > {{answer.question.text}} > > > > > > {{answer.text}} > > > > > > > > > > > > {% endfor %} > > > > > > > > > > > > > From the point of view of the Candidate, I need to display all the > > > > > > questions, including the ones without Answers. I know how to to do > > > > > > this using raw sql and an outer join. How to do it in the orm? > > > > > > > Thanks in advance for any ideas. > > > > > > > --Jeff > > > > > > Not quite enough information here to answer. What are you wanting to > > > > > join? If you just want to display all the questions, why do you need a > > > > > join at all? > > > > > -- > > > > > DR. > > -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Weekly rss feed
On 2010-06-21, at 5:48 PM, TheIvIaxx wrote: > I was wondering how to create a weekly feed for django. Lets say i > have a table of objects that gets added to all week long. I'd like to > allow people to subscribe to a feed that would give a single update > with all items that were added that week. Since the client doesn't > send anything about when it last checked for updates, it's hard to > determine if the requesting client needs to be given an update or not. A few points: - RSS readers keep track of all the things that have been read and don't display duplicates, so I don't really see a need for doing this anyway - You maybe want a script that runs once a week and produces a summary post of all the things entered that week, but that just gives you one item. - Or you just do a query that specifies the time range, eg: filter and only show posts in the last seven days. -- Andy McKay, @andymckay Django Consulting, Training and Support -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
One to many django pagination
Hi, i recently encountered a problem due to inefficient performance of django pagination. After researching, i realized that there is a need to use django database queries when dealing with django-pagination as "LIMIT" will automatically be added. This is useful especially when dealing with huge chunk of data. However, i came across a problem where i could not figure out how to use django database query to extract the data. Lets say i have 3 tables, "Teachers", "Students", and "Teachers_profile" with a one-many relationship. The Teacher table contains teacher_id,.(teacher info) The Student table contains student_id,name,...(student info) The Teacher_profile table is the link between the 2 tables. It contains teacher_id,student_id How can i use django database query with filters to extract the teachers who is managing a student named "Jonny" for example? i'm not sure if this is an easy question, but i'm having some trouble in solving it :( -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Weekly rss feed
The problem with the first is that users would get a bunch of single items whenever they were added to the DB. I need to give them a digest of what happened that week. I had thought of the range idea, but then you're hitting the DB every hour all week for a single update which doesn't sound correct. So i think i'll have a cron task just update a field in a table each week that the actual Feed view will pull from. It's still a db hit, but a very simple one. On Jun 21, 6:15 pm, Andy McKay wrote: > On 2010-06-21, at 5:48 PM, TheIvIaxx wrote: > > > I was wondering how to create a weekly feed for django. Lets say i > > have a table of objects that gets added to all week long. I'd like to > > allow people to subscribe to a feed that would give a single update > > with all items that were added that week. Since the client doesn't > > send anything about when it last checked for updates, it's hard to > > determine if the requesting client needs to be given an update or not. > > A few points: > > - RSS readers keep track of all the things that have been read and don't > display duplicates, so I don't really see a need for doing this anyway > > - You maybe want a script that runs once a week and produces a summary post > of all the things entered that week, but that just gives you one item. > > - Or you just do a query that specifies the time range, eg: filter and only > show posts in the last seven days. > -- > Andy McKay, @andymckay > Django Consulting, Training and Support -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: automatic documentation (docutils) does not pull in class methods?
Answering my own question -- it is django.contrib.admindocs.view that limits the admindocs view to only list methods on a model that has a single argument. The lines: for func_name, func in model.__dict__.items(): if (inspect.isfunction(func) and len(inspect.getargspec(func) [0]) == 1): There is currently an open ticket http://code.djangoproject.com/ticket/12974 that patches it to handle the case where methods have decorator on them, hence reducing the number of args to zero. My question is why are we limiting the list of methods to single argument (self) methods? I put business logic in the model and usually the models will have many more methods that take additional arguments. P.K. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.