Re: [CentOS] Not Able to Configure Nagios Server 4.3.4 in Centos 7

[Abhinay Khanna]

Thanks for your reply


Actually the case is that the compiling  process and make all, make install 
processes didn't report any errors but when I trying to access or start the 
service Nagios it gives me an error stating it's unable to find that service.

This happens with me when I try to manually install the applications from 
source.
Am I missing any important step in the installation process that could be 
causing this issue.

Thanks and Regards,
Abhinay

Get Outlook for Android


From: CentOS  on behalf of Chris Beattie 

Sent: Tuesday, October 24, 2017 8:16:00 PM
To: CentOS mailing list
Subject: Re: [CentOS] Not Able to Configure Nagios Server 4.3.4 in Centos 7

> As per the installation instructions I ran the commands in the concerned
> folders of ./configure , make , make install for both the core and the Nagios
> plugins.
>
> I am not able to figure out the issue behind that it is not working It did got
> installed using yum which was a previous 4.3.2 that that had it's own errors
> and wanted me to update with no update of it available in the epel
> repository.

What's not working?  Did it compile correctly?  Nagios needs some extra 
packages to for all of its features to work.  These can be installed via YUM 
even if you compile Nagios itself from source.

Also, if you install Nagios from source, SELinux will prevent it from doing a 
lot of stuff by default.  However, it's entirely possible to run Nagios with 
SELinux in Enforcing mode with the right policy.
___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos
___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

[CentOS] [OT] Bash help

[Mark Haney]

I know this is for CentOS stuff, but I'm at a loss on how to build a 
script that does what I need it to do.  It's probably really logically 
simple, I'm just not seeing it.  Hopefully someone will take pity on me 
and at least give me a big hint.


I have a file with two columns 'email' and 'total' like this:

m...@example.com 20
m...@example.com 40
y...@domain.com 100
y...@domain.com 30

I need to get the total number of messages for each email address.  This 
type of code has always been the hardest for me for whatever reason, and 
honestly, I don't write many scripts these days. I'm struggling to get 
psuedocode that works, much less a working script. I know this is off 
topic, and if it gets modded out, that's fine.  I just can't wrap my 
brain around it.


--
Mark Haney
Network Engineer at NeoNova
919-460-3330 option 1
mark.ha...@neonova.net
www.neonova.net

___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Robert Arkiletian]

On Wed, Oct 25, 2017 at 9:02 AM, Mark Haney  wrote:
> I know this is for CentOS stuff, but I'm at a loss on how to build a script
> that does what I need it to do.  It's probably really logically simple, I'm
> just not seeing it.  Hopefully someone will take pity on me and at least
> give me a big hint.
>
> I have a file with two columns 'email' and 'total' like this:
>
> m...@example.com 20
> m...@example.com 40
> y...@domain.com 100
> y...@domain.com 30
>
> I need to get the total number of messages for each email address.  This
> type of code has always been the hardest for me for whatever reason, and
> honestly, I don't write many scripts these days. I'm struggling to get
> psuedocode that works, much less a working script. I know this is off topic,
> and if it gets modded out, that's fine.  I just can't wrap my brain around
> it.
>

here is a python solution

#!/usr/bin/python
#python 2 (did not check if it works)
f=open('yourfilename')
D={}
for line in f:
email,num = line.split()
if email in D:
D[email] = D[email] + num
else:
D[email] = num
f.close()
for key in D:
print key, D[key]
___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Mark Haney]

On 10/25/2017 12:33 PM, Robert Arkiletian wrote:

here is a python solution
#!/usr/bin/python
#python 2 (did not check if it works)
f=open('yourfilename')
D={}
for line in f:
 email,num = line.split()
 if email in D:
 D[email] = D[email] + num
 else:
 D[email] = num
f.close()
for key in D:
 print key, D[key]
___
That gets me closer, I think.  It's concatenating the number of 
messages, but it's a start. Thanks.


--

Mark Haney
Network Engineer at NeoNova
919-460-3330 option 1
mark.ha...@neonova.net
www.neonova.net

___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Pete Biggs]

On Wed, 2017-10-25 at 12:02 -0400, Mark Haney wrote:
> I know this is for CentOS stuff, but I'm at a loss on how to build a 
> script that does what I need it to do.  It's probably really logically 
> simple, I'm just not seeing it.  Hopefully someone will take pity on me 
> and at least give me a big hint.
> 
> I have a file with two columns 'email' and 'total' like this:
> 
> m...@example.com 20
> m...@example.com 40
> y...@domain.com 100
> y...@domain.com 30
> 
> I need to get the total number of messages for each email address.  This 
> type of code has always been the hardest for me for whatever reason, and 
> honestly, I don't write many scripts these days. I'm struggling to get 
> psuedocode that works, much less a working script. I know this is off 
> topic, and if it gets modded out, that's fine.  I just can't wrap my 
> brain around it.
> 
Not bash but perl:

#
#!/usr/bin/perl
my %dd;
while (<>) {
my @f=split;
$dd{$f[0]}{COUNT}+=$f[1];
}
print "\nSums:\n";
for (keys %dd) { print "$_\t $dd{$_}{COUNT}\n"; };


It takes the data on stdin, sums it into an associative array and
prints out the result

Results:
##
$ ./ppp
m...@example.com 20
m...@example.com 40
y...@domain.com 100
y...@domain.com 30

Sums:
y...@domain.com  130
m...@example.com 60
##

I'm sure some perl monk can come up with a single line command to do
the same thing.

P.

___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Bowie Bailey]

On 10/25/2017 12:41 PM, Mark Haney wrote:

On 10/25/2017 12:33 PM, Robert Arkiletian wrote:

here is a python solution
#!/usr/bin/python
#python 2 (did not check if it works)
f=open('yourfilename')
D={}
for line in f:
 email,num = line.split()
 if email in D:
 D[email] = D[email] + num
 else:
 D[email] = num
f.close()
for key in D:
 print key, D[key]
___
That gets me closer, I think.  It's concatenating the number of 
messages, but it's a start. Thanks.




I do this kind of thing on a fairly regular basis with a Perl one-liner:

perl -ne '($email, $num) = split; $tot{$email} += $num; END { for $email 
(keys %tot) { print "$email $tot{$email}\n" } }' < yourfile


--
Bowie
___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Warren Young]

On Oct 25, 2017, at 10:02 AM, Mark Haney  wrote:
> 
> I have a file with two columns 'email' and 'total' like this:
> 
> m...@example.com 20
> m...@example.com 40
> y...@domain.com 100
> y...@domain.com 30
> 
> I need to get the total number of messages for each email address.

This screams out for associative arrays.  (Also called hashes, dictionaries, 
maps, etc.)

That does limit you to CentOS 7+, or maybe 6+, as I recall.  CentOS 5 is 
definitely out, as that ships Bash 3, which lacks this feature.


#!/bin/bash
declare -A totals

while read line
do
IFS="\t " read -r -a elems <<< "$line"
email=${elems[0]}
subtotal=${elems[1]}

declare -i n=${totals[$email]}
n=n+$subtotal
totals[$email]=$n
done < stats

for k in "${!totals[@]}"
do
printf "%6d  %s\n" ${totals[$k]} $k
done


You’re making things hard on yourself by insisting on Bash, by the way.  This 
solution is better expressed in Perl, Python, Ruby, Lua, JavaScript…probably 
dozens of languages.
___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Robert Arkiletian]

On Wed, Oct 25, 2017 at 9:41 AM, Mark Haney  wrote:
> On 10/25/2017 12:33 PM, Robert Arkiletian wrote:
>>
>> here is a python solution
>> #!/usr/bin/python
>> #python 2 (did not check if it works)
>> f=open('yourfilename')
>> D={}
>> for line in f:
>>  email,num = line.split()
>>  if email in D:

>>  D[email] = D[email] + int(num)

>>  else:

>>  D[email] = int(num)

>> f.close()
>> for key in D:
>>  print key, D[key]
>> ___
>
> That gets me closer, I think.  It's concatenating the number of messages,
> but it's a start. Thanks.
>
>
> --
>
> Mark Haney
> Network Engineer at NeoNova
> 919-460-3330 option 1
> mark.ha...@neonova.net
> www.neonova.net
>
> ___
> CentOS mailing list
> CentOS@centos.org
> https://lists.centos.org/mailman/listinfo/centos
___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Leroy Tennison]

Although "not my question", thanks, I learned a lot about array processing from 
your example.

- Original Message -
From: "warren" 
To: "centos" 
Sent: Wednesday, October 25, 2017 11:47:12 AM
Subject: Re: [CentOS] [OT] Bash help

On Oct 25, 2017, at 10:02 AM, Mark Haney  wrote:
> 
> I have a file with two columns 'email' and 'total' like this:
> 
> m...@example.com 20
> m...@example.com 40
> y...@domain.com 100
> y...@domain.com 30
> 
> I need to get the total number of messages for each email address.

This screams out for associative arrays.  (Also called hashes, dictionaries, 
maps, etc.)

That does limit you to CentOS 7+, or maybe 6+, as I recall.  CentOS 5 is 
definitely out, as that ships Bash 3, which lacks this feature.


#!/bin/bash
declare -A totals

while read line
do
IFS="\t " read -r -a elems <<< "$line"
email=${elems[0]}
subtotal=${elems[1]}

declare -i n=${totals[$email]}
n=n+$subtotal
totals[$email]=$n
done < stats

for k in "${!totals[@]}"
do
printf "%6d  %s\n" ${totals[$k]} $k
done


You’re making things hard on yourself by insisting on Bash, by the way.  This 
solution is better expressed in Perl, Python, Ruby, Lua, JavaScript…probably 
dozens of languages.
___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos
___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Warren Young]

On Oct 25, 2017, at 11:00 AM, Leroy Tennison  wrote:
> 
> Although "not my question", thanks, I learned a lot about array processing 
> from your example.

Yeah, it’s amazing how many obscure corners of the Bash language must be tapped 
to solve such a simple problem.  I count 7 features in that script that I 
almost never use, because I’d have just written this one in Perl if not 
required to write it in Bash by the OP.

I expect that’s why the features are obscure to you, too: once you need to step 
beyond POSIX 1988 shell levels, most people just switch to some more powerful 
language, owing to the dark days when even a POSIX shell was sometimes tricky 
to find, much less a post-POSIX shell.  (Can you say /usr/xpg4/bin/sh ?   
Yyyeahh…)

That situation threw a long shadow over the shell scripting landscape, where 
relatively few dare to tread, even today.
___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Mark Haney]

On 10/25/2017 12:47 PM, Warren Young wrote:


You’re making things hard on yourself by insisting on Bash, by the way.  This 
solution is better expressed in Perl, Python, Ruby, Lua, JavaScript…probably 
dozens of languages.
Yeah, you're right, I am. An associative array was the first thing I 
thought of, then realized BASH doesn't do those.  I honestly expected 
there to be a fairly straight forward way to do it in BASH, but I was 
sadly mistaken.  In my defense, I gave virtually no thought on the logic 
of what I was trying to do until after I'd committed significant time to 
a BASH script.  (Well maybe that's not a defense, but an indictment.)


As I said, I don't do much scripting anymore as the majority of my time 
is spent DB tuning and Ansible automation.  Not really an excuse, and I 
appreciate your indulgence(s) in giving me a hand.  As embarrassed as I 
am, I'll just go sit in the corner the rest of the day.


Thanks again.


--
Mark Haney
Network Engineer at NeoNova
919-460-3330 option 1
mark.ha...@neonova.net
www.neonova.net

___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[m . roth]

Warren Young wrote:
> On Oct 25, 2017, at 10:02 AM, Mark Haney  wrote:
>>
>> I have a file with two columns 'email' and 'total' like this:
>>
>> m...@example.com 20
>> m...@example.com 40
>> y...@domain.com 100
>> y...@domain.com 30
>>
>> I need to get the total number of messages for each email address.
>
> This screams out for associative arrays.  (Also called hashes,
> dictionaries, maps, etc.)
>
> That does limit you to CentOS 7+, or maybe 6+, as I recall.  CentOS 5 is
> definitely out, as that ships Bash 3, which lacks this feature.

Associative arrays?

Awk! Awk! (No, I am not a seagull...)

sort file | awk '{ array[$1] += $2;} END { for (i in array) { print i "\t"
array[i];}'

  mark "associative arrays, how do I love thee? Let me tot the arrays..."


___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[m . roth]

Warren Young wrote:
> On Oct 25, 2017, at 11:00 AM, Leroy Tennison 
> wrote:
>>
>> Although "not my question", thanks, I learned a lot about array
>> processing from your example.
>
> Yeah, it’s amazing how many obscure corners of the Bash language must be
> tapped to solve such a simple problem.  I count 7 features in that script
> that I almost never use, because I’d have just written this one in Perl if
> not required to write it in Bash by the OP.

Let me say this: among the many reasons I like *Nix: in any other o/s,
it's "how co I create this report, and it takes from 2 days to 2 weeks. In
*Nix, it's "of all the ways I can create this report, how would I *prefer*
to do it"

___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Leroy Tennison]

No kidding, but in that "other OS" the answer to the question "how can I create 
that report" is usually "You can't unless you spend money for a third-party 
application".

- Original Message -
From: "m roth" 
To: "centos" 
Sent: Wednesday, October 25, 2017 12:27:28 PM
Subject: Re: [CentOS] [OT] Bash help

Warren Young wrote:
> On Oct 25, 2017, at 11:00 AM, Leroy Tennison 
> wrote:
>>
>> Although "not my question", thanks, I learned a lot about array
>> processing from your example.
>
> Yeah, it’s amazing how many obscure corners of the Bash language must be
> tapped to solve such a simple problem.  I count 7 features in that script
> that I almost never use, because I’d have just written this one in Perl if
> not required to write it in Bash by the OP.

Let me say this: among the many reasons I like *Nix: in any other o/s,
it's "how co I create this report, and it takes from 2 days to 2 weeks. In
*Nix, it's "of all the ways I can create this report, how would I *prefer*
to do it"

___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos
___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Mark Haney]

On 10/25/2017 01:24 PM, m.r...@5-cent.us wrote:


This screams out for associative arrays.  (Also called hashes,
dictionaries, maps, etc.)

That does limit you to CentOS 7+, or maybe 6+, as I recall.  CentOS 5 is
definitely out, as that ships Bash 3, which lacks this feature.


Associative arrays?

Awk! Awk! (No, I am not a seagull...)

sort file | awk '{ array[$1] += $2;} END { for (i in array) { print i "\t"
array[i];}'

   mark "associative arrays, how do I love thee? Let me tot the arrays..."

Okay, I'm impressed with this one.  I use awk for simple stuff when sed 
starts getting weird, but this is absolutely elegant. No offense to the 
other examples, they are all awesome, but I had no idea awk could do 
this with such little effort.  Well, I know what I'm studying up on this 
weekend.


--
Mark Haney
Network Engineer at NeoNova
919-460-3330 option 1
mark.ha...@neonova.net
www.neonova.net

___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[m . roth]

Mark Haney wrote:
> On 10/25/2017 01:24 PM, m.r...@5-cent.us wrote:
>>>
>>> This screams out for associative arrays.  (Also called hashes,
>>> dictionaries, maps, etc.)
>>>
>>> That does limit you to CentOS 7+, or maybe 6+, as I recall.  CentOS 5
>>> is definitely out, as that ships Bash 3, which lacks this feature.
>> 
>> Associative arrays?
>>
>> Awk! Awk! (No, I am not a seagull...)
>>
>> sort file | awk '{ array[$1] += $2;} END { for (i in array) { print i
>> "\t" array[i];}'
>>
>>mark "associative arrays, how do I love thee? Let me tot the
>> arrays..."
>>
> Okay, I'm impressed with this one.  I use awk for simple stuff when sed
> starts getting weird, but this is absolutely elegant. No offense to the
> other examples, they are all awesome, but I had no idea awk could do
> this with such little effort.  Well, I know what I'm studying up on this
> weekend.
>
The perl script was about the same. It's just, well, I learned awk when I
first got into *nix, in '91. Had a project where We were going to be the
center and Tell All Agencies The Format of the data they would give us,
and we'd load a d/b I wrote the d/b loader in C..and then they all
said, "sorry, no budget for that, here's the format we've got it in, ya
want it or not?"

Before that project finished, I had 30 awk scripts, ranging in length from
100-200 lines (yes, really), to reformat, and validate the data before
feeding it to the loader I'd written. The other thing - there may be more
succinct ways to write it (my manager, these days, uses regular
expressions to the point I have to look what it's doing up), while more
than half my career was as a programmer, and I write code such that if I
get hit by a car, or take another job, or get called at 16:30 on a Friday,
or 02:00, I want to fix the problem without spending hours trying to
remember how clever I'd been last year... so I make it easily readable and
comprehensible.

awk is just fun.

 mark

___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[m . roth]

Leroy Tennison wrote:
> No kidding, but in that "other OS" the answer to the question "how can I
> create that report" is usually "You can't unless you spend money for a
> third-party application".
>
"Other", singluar? Did you mean WinDoze, or on an IBM mainframe, or...?

 mark "been around the block"

> - Original Message -
> From: "m roth" 
> To: "centos" 
> Sent: Wednesday, October 25, 2017 12:27:28 PM
> Subject: Re: [CentOS] [OT] Bash help
>
> Warren Young wrote:
>> On Oct 25, 2017, at 11:00 AM, Leroy Tennison 
>> wrote:
>>>
>>> Although "not my question", thanks, I learned a lot about array
>>> processing from your example.
>>
>> Yeah, it’s amazing how many obscure corners of the Bash language must be
>> tapped to solve such a simple problem.  I count 7 features in that
>> script
>> that I almost never use, because I’d have just written this one in Perl
>> if
>> not required to write it in Bash by the OP.
> 
> Let me say this: among the many reasons I like *Nix: in any other o/s,
> it's "how co I create this report, and it takes from 2 days to 2 weeks. In
> *Nix, it's "of all the ways I can create this report, how would I *prefer*
> to do it"
>
> ___
> CentOS mailing list
> CentOS@centos.org
> https://lists.centos.org/mailman/listinfo/centos
> ___
> CentOS mailing list
> CentOS@centos.org
> https://lists.centos.org/mailman/listinfo/centos
>


___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Leroy Tennison]

Not enough experience with the mainframe: I meant WinDoze.

- Original Message -
From: "m roth" 
To: "centos" 
Sent: Wednesday, October 25, 2017 1:02:54 PM
Subject: Re: [CentOS] [OT] Bash help

Leroy Tennison wrote:
> No kidding, but in that "other OS" the answer to the question "how can I
> create that report" is usually "You can't unless you spend money for a
> third-party application".
>
"Other", singluar? Did you mean WinDoze, or on an IBM mainframe, or...?

 mark "been around the block"

> - Original Message -
> From: "m roth" 
> To: "centos" 
> Sent: Wednesday, October 25, 2017 12:27:28 PM
> Subject: Re: [CentOS] [OT] Bash help
>
> Warren Young wrote:
>> On Oct 25, 2017, at 11:00 AM, Leroy Tennison 
>> wrote:
>>>
>>> Although "not my question", thanks, I learned a lot about array
>>> processing from your example.
>>
>> Yeah, it’s amazing how many obscure corners of the Bash language must be
>> tapped to solve such a simple problem.  I count 7 features in that
>> script
>> that I almost never use, because I’d have just written this one in Perl
>> if
>> not required to write it in Bash by the OP.
> 
> Let me say this: among the many reasons I like *Nix: in any other o/s,
> it's "how co I create this report, and it takes from 2 days to 2 weeks. In
> *Nix, it's "of all the ways I can create this report, how would I *prefer*
> to do it"
>
> ___
> CentOS mailing list
> CentOS@centos.org
> https://lists.centos.org/mailman/listinfo/centos
> ___
> CentOS mailing list
> CentOS@centos.org
> https://lists.centos.org/mailman/listinfo/centos
>


___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos
___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Jason Welsh]

hrm.. seems like you were missing a }


sort file | awk '{array[$1] += $2;} END { for (i in array) {print i "\t" 
array[i];}}'



regards,

Jason



On 10/25/2017 01:24 PM, m.r...@5-cent.us wrote:

Warren Young wrote:

On Oct 25, 2017, at 10:02 AM, Mark Haney  wrote:

I have a file with two columns 'email' and 'total' like this:

m...@example.com 20
m...@example.com 40
y...@domain.com 100
y...@domain.com 30

I need to get the total number of messages for each email address.

This screams out for associative arrays.  (Also called hashes,
dictionaries, maps, etc.)

That does limit you to CentOS 7+, or maybe 6+, as I recall.  CentOS 5 is
definitely out, as that ships Bash 3, which lacks this feature.


Associative arrays?

Awk! Awk! (No, I am not a seagull...)

sort file | awk '{ array[$1] += $2;} END { for (i in array) { print i "\t"
array[i];}'

   mark "associative arrays, how do I love thee? Let me tot the arrays..."


___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos


___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[m . roth]

Jason Welsh wrote:
> hrm.. seems like you were missing a }
>
> sort file | awk '{array[$1] += $2;} END { for (i in array) {print i "\t"
> array[i];}}'
>

Oops. Well, it's not vi, it's webmail, so I couldn't check...  Thanks.

  mark


>
> regards,
>
> Jason
>
>
>
> On 10/25/2017 01:24 PM, m.r...@5-cent.us wrote:
>> Warren Young wrote:
>>> On Oct 25, 2017, at 10:02 AM, Mark Haney 
>>> wrote:
 I have a file with two columns 'email' and 'total' like this:

 m...@example.com 20
 m...@example.com 40
 y...@domain.com 100
 y...@domain.com 30

 I need to get the total number of messages for each email address.
>>> This screams out for associative arrays.  (Also called hashes,
>>> dictionaries, maps, etc.)
>>>
>>> That does limit you to CentOS 7+, or maybe 6+, as I recall.  CentOS 5
>>> is
>>> definitely out, as that ships Bash 3, which lacks this feature.
>> 
>> Associative arrays?
>>
>> Awk! Awk! (No, I am not a seagull...)
>>
>> sort file | awk '{ array[$1] += $2;} END { for (i in array) { print i
>> "\t"
>> array[i];}'
>>
>>mark "associative arrays, how do I love thee? Let me tot the
>> arrays..."
>>
>>
>> ___
>> CentOS mailing list
>> CentOS@centos.org
>> https://lists.centos.org/mailman/listinfo/centos
>
> ___
> CentOS mailing list
> CentOS@centos.org
> https://lists.centos.org/mailman/listinfo/centos
>


___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Robert Arkiletian]

On Wed, Oct 25, 2017 at 9:59 AM, Robert Arkiletian  wrote:
> On Wed, Oct 25, 2017 at 9:41 AM, Mark Haney  wrote:
>> On 10/25/2017 12:33 PM, Robert Arkiletian wrote:
>>>
>>> here is a python solution
>>> #!/usr/bin/python
>>> #python 2 (did not check if it works)
>>> f=open('yourfilename')
>>> D={}
>>> for line in f:
>>>  email,num = line.split()
>>>  if email in D:
>
>>>  D[email] = D[email] + int(num)
>
>>>  else:
>
>>>  D[email] = int(num)
>
>>> f.close()

not to be outdone, python can sort them based on the totals

for k in sorted(D, key=d.get, reverse=True):
print k, D[k]
___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Robert Arkiletian]

On Wed, Oct 25, 2017 at 12:08 PM, Robert Arkiletian  wrote:
> On Wed, Oct 25, 2017 at 9:59 AM, Robert Arkiletian  wrote:
>> On Wed, Oct 25, 2017 at 9:41 AM, Mark Haney  wrote:
>>> On 10/25/2017 12:33 PM, Robert Arkiletian wrote:

 here is a python solution
 #!/usr/bin/python
 #python 2 (did not check if it works)
 f=open('yourfilename')
 D={}
 for line in f:
  email,num = line.split()
  if email in D:
>>
  D[email] = D[email] + int(num)
>>
  else:
>>
  D[email] = int(num)
>>
 f.close()
>
> not to be outdone, python can sort them based on the totals
>
> for k in sorted(D, key=d.get, reverse=True):

oops. that's a capital D.get

 for k in sorted(D, key=D.get, reverse=True):

> print k, D[k]
___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Tony Mountifield]

In article ,
  wrote:
> Warren Young wrote:
> > On Oct 25, 2017, at 10:02 AM, Mark Haney  wrote:
> >>
> >> I have a file with two columns 'email' and 'total' like this:
> >>
> >> m...@example.com 20
> >> m...@example.com 40
> >> y...@domain.com 100
> >> y...@domain.com 30
> >>
> >> I need to get the total number of messages for each email address.
> >
> > This screams out for associative arrays.  (Also called hashes,
> > dictionaries, maps, etc.)
> >
> > That does limit you to CentOS 7+, or maybe 6+, as I recall.  CentOS 5 is
> > definitely out, as that ships Bash 3, which lacks this feature.
> 
> Associative arrays?
> 
> Awk! Awk! (No, I am not a seagull...)
> 
> sort file | awk '{ array[$1] += $2;} END { for (i in array) { print i "\t"
> array[i];}'

Why the sort? It doesn't matter in what order the lines are read.
Wouldn't this give you the same?

awk '{ array[$1] += $2;} END { for (i in array) { print i "\t" array[i];}}' 
http://www.softins.co.uk
Play: t...@mountifield.org - http://tony.mountifield.org
___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Warren Young]

On Oct 25, 2017, at 11:28 AM, Mark Haney  wrote:
> 
> An associative array was the first thing I thought of, then realized BASH 
> doesn't do those.

But it does: in Bash 4, only.

If you mean you must still use Bash 3 in places, then yeah, you’ve got a 
problem… one probably best solved by switching to some other language once the 
program grows beyond Bash 3’s natural scope.

I was trying to think of which languages I know well which require even more 
difficult solutions than the Bash 4 one.  It’s a pretty short list: assembly, 
C, and MS-DOS batch files.  By “C” I’m including anything of its era and 
outlook: Pascal, Fortran…

I think even Tcl beats Bash 4 on this score, and it’s notoriously minimal in 
its feature set.

Here’s a brain-bender: You could probably do it with sqlite3 with fewer lines 
of code than my Bash 4 offering. :)

> I honestly expected there to be a fairly straight forward way to do it in 
> BASH, but I was sadly mistaken.

Oh, I don’t know, there must be a way to do it without associative arrays, but 
you’d only get points for the masochism value in doing without.
___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Bowie Bailey]

On 10/25/2017 3:34 PM, Warren Young wrote:

On Oct 25, 2017, at 11:28 AM, Mark Haney  wrote:

An associative array was the first thing I thought of, then realized BASH 
doesn't do those.

But it does: in Bash 4, only.

If you mean you must still use Bash 3 in places, then yeah, you’ve got a 
problem… one probably best solved by switching to some other language once the 
program grows beyond Bash 3’s natural scope.

I was trying to think of which languages I know well which require even more 
difficult solutions than the Bash 4 one.  It’s a pretty short list: assembly, 
C, and MS-DOS batch files.  By “C” I’m including anything of its era and 
outlook: Pascal, Fortran…

I think even Tcl beats Bash 4 on this score, and it’s notoriously minimal in 
its feature set.

Here’s a brain-bender: You could probably do it with sqlite3 with fewer lines 
of code than my Bash 4 offering. :)


I honestly expected there to be a fairly straight forward way to do it in BASH, 
but I was sadly mistaken.

Oh, I don’t know, there must be a way to do it without associative arrays, but 
you’d only get points for the masochism value in doing without.


Array N holds the names and array T holds the totals.  For each line in 
the file, you iterate through N to find the name and then add the number 
to the same index in T (or create a new entry in both arrays if you 
don't find it).  Then you just have to iterate through both arrays and 
print off the names from N and the totals from T.  It's a pain, but it's 
doable.


Sorry, I'm too lazy to write code for this...  :)

--
Bowie
___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Chris Adams]

Once upon a time, Warren Young  said:
> I was trying to think of which languages I know well which require even more 
> difficult solutions than the Bash 4 one.  It’s a pretty short list: assembly, 
> C, and MS-DOS batch files.  By “C” I’m including anything of its era and 
> outlook: Pascal, Fortran…

Heh, even C on SVR4 and newer (including POSIX from 2001) have pretty
straight-forward hash routines: hcreate(), hsearch(), and hdestroy().
-- 
Chris Adams 
___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[Jon LaBadie]

On Wed, Oct 25, 2017 at 10:47:12AM -0600, Warren Young wrote:
> On Oct 25, 2017, at 10:02 AM, Mark Haney  wrote:
> > 
> > I have a file with two columns 'email' and 'total' like this:
> > 
> > m...@example.com 20
> > m...@example.com 40
> > y...@domain.com 100
> > y...@domain.com 30
> > 
> > I need to get the total number of messages for each email address.
> 
> This screams out for associative arrays.  (Also called hashes, dictionaries, 
> maps, etc.)
> 
> That does limit you to CentOS 7+, or maybe 6+, as I recall.  CentOS 5 is 
> definitely out, as that ships Bash 3, which lacks this feature.
> 
> 
> #!/bin/bash
> declare -A totals
> 
> while read line
> do
> IFS="\t " read -r -a elems <<< "$line"
> email=${elems[0]}
> subtotal=${elems[1]}
> 
> declare -i n=${totals[$email]}
> n=n+$subtotal
> totals[$email]=$n
> done < stats
> 
> for k in "${!totals[@]}"
> do
> printf "%6d  %s\n" ${totals[$k]} $k
> done

A slightly different approach written for ksh
but seems to also work with bash 4.

typeset -A arr

while read addr cnt
do
arr[$addr]=$(( ${arr[$addr]:-0}  + cnt))
done < ${1}

for a in ${!arr[*]}
do
printf "%6d   %s\n" ${arr[$a]} $a
done

Jon
-- 
Jon H. LaBadie j...@jgcomp.com
 11226 South Shore Rd.  (703) 787-0688 (H)
 Reston, VA  20190  (703) 935-6720 (C)
___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos

Re: [CentOS] [OT] Bash help

[m . roth]

Tony Mountifield wrote:
> In article
> ,
>   wrote:
>> Warren Young wrote:
>> > On Oct 25, 2017, at 10:02 AM, Mark Haney 
>> wrote:
>> >>
>> >> I have a file with two columns 'email' and 'total' like this:
>> >>
>> >> m...@example.com 20
>> >> m...@example.com 40
>> >> y...@domain.com 100
>> >> y...@domain.com 30
>> >>
>> >> I need to get the total number of messages for each email address.
>> >
>> > This screams out for associative arrays.  (Also called hashes,
>> > dictionaries, maps, etc.)
>> >
>> > That does limit you to CentOS 7+, or maybe 6+, as I recall.  CentOS 5
>> is
>> > definitely out, as that ships Bash 3, which lacks this feature.
>> 
>> Associative arrays?
>>
>> Awk! Awk! (No, I am not a seagull...)
>>
>> sort file | awk '{ array[$1] += $2;} END { for (i in array) { print i
>> "\t"
>> array[i];}'
>
> Why the sort? It doesn't matter in what order the lines are read.
> Wouldn't this give you the same?
>
> awk '{ array[$1] += $2;} END { for (i in array) { print i "\t"
> array[i];}}' 
You're right, not really necessary in this case. I was working with a
couple of awk scripts here at work, and it was needed in the middle

 mark

___
CentOS mailing list
CentOS@centos.org
https://lists.centos.org/mailman/listinfo/centos