Hello List,
Can you recommend me if odeSolve can handle stiff delay differential equations
with discontinuities? Or any other package?
Best,
-m
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
On Wed, Dec 5, 2012 at 12:02 AM, arun wrote:
> Hi,
>
>
> p <- lapply(1:1e6, function(i)c(i, log2(i)))
>
> system.time(z1 <- t(sapply(p,function(x)x)))
> # user system elapsed
> # 2.568 0.048 2.619
> system.time(z1 <- do.call(rbind,p))
> # user system elapsed
> # 4.000 0.052 4.06
Le mardi 04 décembre 2012 à 16:17 -0500, sagnik ray choudhury a écrit :
> I am using R for hierarchical clustering of a number of documents.
>
> I have a distance matrix on which I have applied hclust method. When I plot
> the result of hclust method, I can see the dendogram plotted. What I need
>
Hi ,
I am writing a function in C and i wish to call it from R.
Thanks to this tutorial , this is easily possible -
http://www.nceas.ucsb.edu/scicomp/usecases/CreateRPackageWithC
Now , i have a server written in R which listens on a port for requests and
process the requests.
Now what i need is
Hello
I am running var on dataset
data1 is the name of my dataset
cn.chf us.chf
2005-07-01 -1.18656633 -1.18656633
2005-07-04 -0.48835920 -0.48835920
2005-07-05 -0.01534272 -0.01534272
2005-07-06 0.08825279 0.08825279
2005-07-07 0.34223563 0.34223563
2005-07-08 -0.0577622
Dear Dr. bernhard
cc. r-help
Thank you very much for deverlopping rneos package. I read the document of
rneos.
however, due to my inability, i could not figure-out how to connect with
neos server from R environment.
let me explain the steps, i took. my laptop is using wireless of my
laboratory. t
Bonjour,
Je serais en congés jusqu'au Jeudi 6 Décembre.
Pour des raisons d'urgence, vous pourrez me contacter par téléphone au 06 46 34
81 03.
Cordialement,
--
Jérôme Boutet
Conservatoire d'espaces naturels de Picardie
1, place Ginkgo - village Oasis
80 044 AMIEN
Hello,
I have a dataframe
1 2006-11 NaN
2 2006-12 NaN
3 2006-10 0.1577647
4 2006-11 NaN
5 2006-12 NaN
6 2007-01 NaN
7 2007-02 NaN
8 2007-03 0.2956429
9 2007-01 NaN
10 2007-02 NaN
I need to trim first and last NaN rows
Result -
1 2006-10 0.1577647
2 2
HI, All
I met the following problem. I dont know how to handle it.
Country Price
1 CN 44.25
2 CN 21.07
3 CN 92.70
4 CN 47.41
5 CN
Hi Tammy,
Check ?cut and its examples.
HTH,
Jorge.-
On Wed, Dec 5, 2012 at 11:26 PM, Tammy Ma <> wrote:
>
> HI, All
>
> I met the following problem. I dont know how to handle it.
>
> Country Price
> 1 CN 44.25
> 2 CN
Dear UseRs,
I wanted to know that i have been using "leaps" for the proper models selection
for my work. I read so many articles from internet which categorically outlined
that "leaps" command for model selection should never be used as its not
efficient. Moreover, as a matter of fact, i pers
Hello,
Try the following.
dat <-
structure(list(V1 = structure(c(2L, 3L, 1L, 2L, 3L, 4L, 5L, 6L,
4L, 5L), .Label = c("2006-10", "2006-11", "2006-12", "2007-01",
"2007-02", "2007-03"), class = "factor"), V2 = c(NaN, NaN, 0.1577647,
NaN, NaN, NaN, NaN, 0.2956429, NaN, NaN)), .Names = c("V1", "V2"
Hi all.
What is "print print print"?
I don't see output of the print command in for loop and have found this
link:
http://stackoverflow.com/questions/1816200/chisq-test-doesnt-print-results-when-in-a-loop
It describes a problem, similar to mine.
My problem. I want to execute print command in fo
Dear R community,
I quite frequently run into errors while using the RNetCDF package which
do not seem to be recognised as normal R errors and, hence, do not stop
the execution of the code making it hard to debug the code.
Consider, for example:
library(RNetCDF)
con <- create.nc('test.nc')
Hi,
May be this helps:
dat1<-read.table(text="
1 2006-11 NaN
2 2006-12 NaN
3 2006-10 0.1577647
4 2006-11 NaN
5 2006-12 NaN
6 2007-01 NaN
7 2007-02 NaN
8 2007-03 0.2956429
9 2007-01 NaN
10 2007-02 NaN
",sep="",header=FALSE,stringsAsFactors=FALSE)
res<-dat1[seq
Hello,
I am Trying to Build a project, Makefile written so that outer make file calls
the inner Makefiles to Build,
I am invoking the Makefile as gmake depend at the perent directory of project
(Makefile here digs in and executes inner Makefiles to build the project)
.DEFAULT:
@for su
Hi,
I guess with only one rev() should also work:
idx<-cumsum(!is.na(dat$V2))*rev(cumsum(!is.na(dat$V2)))!=0
dat[idx,]
# V1 V2
#3 2006-10 0.1577647
#4 2006-11 NaN
#5 2006-12 NaN
#6 2007-01 NaN
#7 2007-02 NaN
#8 2007-03 0.2956429
A.K.
- Original Message
On 05-12-2012, at 11:46, Vasilchenko Aleksander wrote:
> Hello,
> I have a dataframe
>
> 1 2006-11 NaN
> 2 2006-12 NaN
> 3 2006-10 0.1577647
> 4 2006-11 NaN
> 5 2006-12 NaN
> 6 2007-01 NaN
> 7 2007-02 NaN
> 8 2007-03 0.2956429
> 9 2007-01 NaN
> 10 2007-0
glm2 (1.1) is now available on CRAN.
glm2 fits generalized linear models using the same model specification
as glm, but with a modified fitting method that is more stable for
models that may fail to converge using glm (see: R Journal 3/2, 2011,
pp.12-15).
The previous version of glm2 had to be ar
Hi there,
I am glad to announce AQ-R 0.2 has been successfully built and is
available via install.packages("aqr",
repos="http://R-Forge.R-project.org";).
The most important new feature is real-time messaging from within R.
AQ-R 0.2 enables you to send and receive byte[] messages within R
thr
One correction, one comment, one suggestion:
On Wed, Dec 5, 2012 at 4:44 AM, eliza botto wrote:
>
> Dear UseRs,
>
> I wanted to know that i have been using "leaps" for the proper models
> selection for my work. I read so many articles from internet which
> categorically outlined that "leaps" com
Somebody knows about a MBA (Market Basket Analysis) implementation using
FP-Growth and Arules in R?. I'm no programmer, instead I am a user of this
application and given the computational cost of the APRIORI algorithm, this
does not work well with big Datasets like what you find in the real world.
Hello,
Also, t1 and min(xt) do not vary inside the loop so if it enters the
loop it never exits.
And
res1[j] <-(a*h)
res2 <-sum( res1[j])
is equivalent to
res2 <- a*h
so the inner-most loop is not needed at all.
Hope this helps,
Rui Barradas
Em 05-12-2012 04:20, Jim Lemon escr
Thanks you all
Maurice TEKO
Biostatisticien,Doctorant.
Université de Liège
Département des Sciences et Gestion de l'environnement
185 avenue de Longwy
6700 Arlon (Belgique)
Mail :teko_maur...@yahoo.fr
:anoumou.tekoahate...@ulg.ac.be
http://www.ulg.ac.be
___
Rui ,
I discover all this when running and rerunning my function one and thousand
times and per line.
Now it's perfect, and work so well.
Thanks.
À : Rui Barradas ; Jim Lemon
Cc : "r-help@r-project.org"
Envoyé le : Mercredi 5 décembre 2012 16h45
Objet : R
Dear all,
This is a reminder that the deadline for submitting a tutorial proposal
for the useR! 2013 conference is December 15, 2012. See details below.
Best wishes,
Virgilio
---
We are pleased to announce that the R user conference
useR! 2013
is scheduled for July 10-12, 2013, and will
Hi
I am working on educational assignment to produce an *Incidence matrix *from
a *BIB design *using R language software.
I found a web page *http://wiki.math.yorku.ca/index.php/R:_Incidence_matrix
* about the problem. But it produces Data matrix instead of
Incidence matrix. can you please help me
Hi,
even though the help and the community was a greta plus and a very welcome
experience, I wanted to know I can I exit it?
thanks for you support.
BR
[[alternative HTML version deleted]]
__
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https://stat.ethz.c
Hello everyone,
I've conducted a Type III repeated-measures ANOVA using Anova() from the
car package, based on the suggestions at
http://blog.gribblelab.org/2009/03/09/repeated-measures-anova-using-r/(option
3) and
http://languagescience.umd.edu/wiki/EEG#ERP_ANOVA_in_R. My ANOVA has two
factors: C
Follow the link in the footer of any message from the list to the web page that
lets you modify your list subscription.
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#.
On Dec 4, 2012, at 1:44 PM, arun wrote:
Hi,
You can also do this:
dat1<-structure(list(group = c(4L, 3L, 4L, 4L, 4L, 2L),
X3.Hydroxybutyrate =
c(4e-04,
5e-04, 4e-04, 6e-04, 5e-04, 7e-04), X3.Hydroxyisovalerate = c(3e-04,
3e-04, 3e-04, 3e-04, 3e-04, 4e-04), ADP = c(5e-04, 6e-04, 6e-04,
5e
Dear Steve,
Usually the best place to look for information about functions in the car
package, along with the help files for the package, is the book with which the
package is associated. In this case, there's an on-line appendix to the book on
multivariate linear models which describes how to
Thank you John, I'll take a look at that!
Best,
Steve
On Wed, Dec 5, 2012 at 11:39 AM, John Fox wrote:
>
> Dear Steve,
>
> Usually the best place to look for information about functions in the car
> package, along with the help files for the package, is the book with which
> the package is asso
On Dec 4, 2012, at 8:56 PM, Gyanendra Pokharel wrote:
Thanks Dennis,
Your code also produces same as Jim's but I am not looking that one,
I need
to use "cbind" so that finally I will get the data frame of size
200X320
(i,e, 200 X(16X20)).
Thanks
Here we are a day later and your question
On Dec 5, 2012, at 5:03 AM, Vladimir eremeev wrote:
Hi all.
What is "print print print"?
I don't see output of the print command in for loop and have found
this
link:
http://stackoverflow.com/questions/1816200/chisq-test-doesnt-print-results-when-in-a-loop
It describes a problem, similar
Dear list,
I was curious how to subtract a vector from matrix?
Say, I have
mat <- matrix(1:40, nrow=20, ncol=2)
x <-c(1,2)
I want,
x-mat[1,] and x-mat[2,], and so on... Basically, subtract column elements
of x against column elements in mat.
But x-mat won't do it.
Thanks,
Mike
[[al
On Dec 5, 2012, at 8:33 AM, Sébastien Morant wrote:
Hi,
even though the help and the community was a greta plus and a very
welcome
experience, I wanted to know I can I exit it?
thanks for you support.
The same place you signed up ... and the link is at the bottom of
every posting to Rhe
I am sorry David, I don't mean to give the answer of the impossible
questions. Just you can say impossible. If there is no way to do what I
explained, that's fine, we do have other alternatives what I wrote in the
beginning.
Thank you so much.
On Wed, Dec 5, 2012 at 1:12 PM, David Winsemius wro
The only solution I found was
x-t(mu)
Is there a better way?
Mike
On Wed, Dec 5, 2012 at 1:30 PM, C W wrote:
> Dear list,
> I was curious how to subtract a vector from matrix?
>
> Say, I have
>
> mat <- matrix(1:40, nrow=20, ncol=2)
>
> x <-c(1,2)
>
> I want,
>
> x-mat[1,] and x-mat[2,], and so
Hi,
On Wed, Dec 5, 2012 at 1:30 PM, C W wrote:
> Dear list,
> I was curious how to subtract a vector from matrix?
>
> Say, I have
>
> mat <- matrix(1:40, nrow=20, ncol=2)
>
> x <-c(1,2)
Thanks for the actual reproducible example.
> I want,
>
> x-mat[1,] and x-mat[2,], and so on... Basically, su
On Dec 5, 2012, at 10:36 AM, Gyanendra Pokharel wrote:
> I am sorry David, I don't mean to give the answer of the impossible
> questions. Just you can say impossible. If there is no way to do
> what I explained, that's fine, we do have other alternatives what I
> wrote in the beginning.
>
Thanks, Sarah. First time heard about sweep(), it worked just the way I
wanted.
Mike
On Wed, Dec 5, 2012 at 1:42 PM, Sarah Goslee wrote:
> Hi,
>
> On Wed, Dec 5, 2012 at 1:30 PM, C W wrote:
> > Dear list,
> > I was curious how to subtract a vector from matrix?
> >
> > Say, I have
> >
> > mat <
On 05-12-2012, at 03:37, Gyanendra Pokharel wrote:
> Hi group,
>
> I imported 16 data frames using the function "list.files"
>
> temp <- list.files(path="...")
> myfiles = lapply(temp, read.table,sep = "")
>
> Now I have 16 data set imported in R window.
>
> I want to combine them by
Thanks Berend, your Idea is great, that,s what I was looking.
Thanks again
On Wed, Dec 5, 2012 at 2:06 PM, Berend Hasselman wrote:
> do.call(cbind,lapply(mydf, function(df) df[,1:2]))
[[alternative HTML version deleted]]
__
R-help@r-project.
I looked at your data:
> table(x, cluster)
1 2 3 4 5 6
0 0 48 0 48 48 0
1 48 0 48 0 0 48
Your covariate "x" is perfectly predicted by the cluster variable.
If you fit a fixed effects model:
coxph(Surv(time, event) ~ factor(cluster) +x)
then the "x" variable is declared redu
I'm having trouble loading Ryacas. I've downloaded and extracted Ryacas
0.2-9 (also tried Ryacas ) and yacas 1.0.63, have the latest version of R
and have tried the following (this works for installing other packages):
install.packages("Ryacas")
library(Ryacas)
install.packages("yacas")
library(y
I have a reshaped data frame with value column headings concatenated from
two column headings in the melted data frame. I want to change all 56
headings in a single command, but 'names' allows me to change only one at a
time. In Hadley's 2007 article on reshape in the Journal of Statistical
Soft
x <- data.frame(a = 1:5, b = rnorm(5))
names(x) <- LETTERS[2:1]
print(x)
seems to work.
Can you be more explicit about your problem?
Michael
On Wed, Dec 5, 2012 at 6:51 PM, Rich Shepard wrote:
> I have a reshaped data frame with value column headings concatenated from
> two column headings
Hi
I have used fa() to perform a factor analysis of a psychological battery which
is thought to have 11 factors. I can identify which factors the loadings
relate to easily enough because I can see which items are loading onto each of
the columns in the $loading output. However, how can I ident
On Dec 5, 2012, at 10:21 AM, Alicia Ellis wrote:
I'm having trouble loading Ryacas. I've downloaded and extracted
Ryacas
0.2-9 (also tried Ryacas ) and yacas 1.0.63, have the latest version
of R
and have tried the following (this works for installing other
packages):
install.packages("R
Hi,
I am not sure why ?rename() is not working.
a <- list(a = 1, b = 2, c = 3)
rename(a, c(b = "a", c = "b", a="c"))
A.K.
- Original Message -
From: Rich Shepard
To: r-help@r-project.org
Cc:
Sent: Wednesday, December 5, 2012 1:51 PM
Subject: [R] Changing data frame column headi
Hello,
duplicated() does not seem to work for a long vector. For example, if
you download the data from
https://docs.google.com/open?id=0B6-m45Jvl3ZmNmpaSlJWMXo5bmc (a vector
with about 12,000 numbers) and then run the following code which does
duplicated() over the whole vector but just shows the
Hi,
duplicated() doesn't just look at consecutive values, but anywhere in
the object. Since your 12320-element vector has only 48 separate
values, and all of them occur before the last 30 elements, so
duplicated() returns TRUE.
You might be looking for something involving rle(). What are you
tryi
thanks, I knew about apply, but did not you you can put plus signs with
quotes. That's a cool tricky,
Mike
On Wed, Dec 5, 2012 at 4:05 PM, arun wrote:
> HI,
> In addition to ?sweep(), you can use
>
> apply(-mat,1,`+`,x)
>
> #or
> library(plyr)
> aaply(-mat,1,"+",x)
>
>
> A.K.
>
>
>
>
>
>
>
?cut
> x <- read.table(text = " Country Price
+ 1 CN 44.25
+ 2 CN 21.07
+ 3 CN 92.70
+ 4 CN 47.41
+ 5 CN111.67
+ 6 CN
On Wed, 5 Dec 2012, R. Michael Weylandt wrote:
Can you be more explicit about your problem?
Michael,
Data frame contains water chemistry data; site, date, parameter, value.
The column names after dcast() are, for example, alk_quant, ph_quant,
tds_quant. I wanted to remove the '_quant' from
On Wed, 5 Dec 2012, arun wrote:
I am not sure why ?rename() is not working.
a <- list(a = 1, b = 2, c = 3)
rename(a, c(b = "a", c = "b", a="c"))
I have the reshape2 library loaded and ?rename did not find the help page.
Are the parentheses required in the command?
Thanks,
Rich
_
Without seeing what options you have specified in your call to fa(), it is
not possible to answer the question. There are detailed discussions in ?fa
and ?factor.scores in the psych package, but for the final word you should
probably contact the package maintainer:
Package: psych
Version: 1.2.8
D
HI,
In addition to ?sweep(), you can use
apply(-mat,1,`+`,x)
#or
library(plyr)
aaply(-mat,1,"+",x)
A.K.
- Original Message -
From: C W
To: Sarah Goslee
Cc: r-help
Sent: Wednesday, December 5, 2012 1:51 PM
Subject: Re: [R] data manipulation between vector and matrix
Thanks, S
On Wed, Dec 5, 2012 at 9:23 PM, Rich Shepard wrote:
> On Wed, 5 Dec 2012, R. Michael Weylandt wrote:
>
>> Can you be more explicit about your problem?
>
>
> Michael,
>
> Data frame contains water chemistry data; site, date, parameter, value.
> The column names after dcast() are, for example, alk
Thanks for the benchmark. I actually wanted to go with the winner, except
the x-t(mat) output is very different than the others.
Mike
On Wed, Dec 5, 2012 at 4:40 PM, arun wrote:
> Hi,
>
> By comparing the different methods:
> set.seed(5)
> mat1<-matrix(sample(1:1e6,1e6,replace=TRUE),ncol=1
If you check, the help files, you will find rename in reshape and plyr, but
not reshape2. But you have never shown us the command you used with names()
and what didn't work:
> a <- data.frame(alk_quant=rnorm(5, 5), ph_quant= rnorm(5, 5),
+ tds_quant=rnorm(5, 5))
> a
alk_quant ph_quant tds_q
On Wed, 5 Dec 2012, arun wrote:
You can get ?rename() by either loading library(reshape) or library(plyr).
A.K.
I wondered about that, but assumed that reshape functions would also be
found in reshape2. I now know that's not the case. :-)
Much appreciated,
Rich
__
Suzen, Mehmet gmail.com> writes:
>
> Hello List,
>
> Can you recommend me if odeSolve can handle stiff delay differential equations
> with discontinuities? Or any other package?
> Best,
> -m
>
>
I don't know, but I think you're probably best off trying it out for
yourself and seeing how i
Hi Sarah,
Thanks a lot for your explanation. I was mistakenly under the
impression that duplicated() only looked at immediately preceding
element, not all preceding elements.
What I was trying to do was get a vector saying, for each item,
whether that item is the same as the preceding item. Now t
> What I was trying to do was get a vector saying, for each item,
> whether that item is the same as the preceding item. Now that I think
> of it, I could do this easily by copying the vector, shifting it over
> one (by removing the first element and adding something to the end),
> and then just co
On Wed, 5 Dec 2012, David L Carlson wrote:
names(a) <- gsub("_quant", "", names(a))
a
David,
I did not pick that up from the names() help page. Thanks for the insight.
Rich
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listin
On Dec 4, 2012, at 10:05 AM, Sebastian Kruk wrote:
> Dear all,
>
> I cannot reading a .xlsm file using read.xls.
>
That doesn't surprise me. It's a macro format. Why should R be reading Excel
macros?
> I executed:
>
> read.xls("resultados.xlsm",
> colNames = TRUE,
> sheet = 1,
> type = "da
On 05/12/2012 21:08, Sarah Goslee wrote:
Hi,
duplicated() doesn't just look at consecutive values, but anywhere in
the object. Since your 12320-element vector has only 48 separate
values, and all of them occur before the last 30 elements, so
duplicated() returns TRUE.
You might be looking for s
Read the ?Startup page, it documents the files that are read on startup and
how to skip them, it may suggest another way to start a fresh session
without deleting files to see if that works for you, it also gives other
files or sources that you may investigate to find the differences in the 2
machi
Sorry, that's my mistake, I should not have said 'long vector'; mine
is just a normal vector. I'm not actually using a development version.
Best,
Steve
On Wed, Dec 5, 2012 at 4:22 PM, Prof Brian Ripley wrote:
>
>
> And BTW, 'long vector' is a technical term in R: not 12,000, but more than 2
> bi
On 12/5/2012 9:15 AM, Suzen, Mehmet wrote:
Hello List,
Can you recommend me if odeSolve can handle stiff delay differential
equations with discontinuities? Or any other package? Best, -m
Package deSolve (the successor of odesolve) can candle:
- stiff differential equations: yes (solvers: lso
On 12/06/2012 12:03 AM, Vladimir eremeev wrote:
Hi all.
What is "print print print"?
I don't see output of the print command in for loop and have found this
link:
http://stackoverflow.com/questions/1816200/chisq-test-doesnt-print-results-when-in-a-loop
It describes a problem, similar to mine.
On Dec 5, 2012, at 2:19 PM, David Winsemius wrote:
>
> On Dec 4, 2012, at 10:05 AM, Sebastian Kruk wrote:
>
>> Dear all,
>>
>> I cannot reading a .xlsm file using read.xls.
>>
>
> That doesn't surprise me. It's a macro format. Why should R be reading Excel
> macros?
>
>
>> I executed:
>>
Dear Prof Carlson
Thank you very much. As far as I can tell, factor.scores requires an object
from class grm, itm, rason, or tpm; which I think are part of the irt package
with which I am unfamiliar.
I had used the psych package to do the following factor analysis:
fa.11factors.rawdata <- fa(WIS
I think you are safe in assuming that the first factor is used to compute the
first factor score column. The factor.scores() procedure is used by fa() to
compute the factor scores so it provides details regarding how they are
computed beyond the information in the fa() help page. As I understand
Hi,
When I try your example, I simply get an error:
> library(RNetCDF)
> con <- create.nc('test.nc')
> test <- try(var.get.nc(con, 'dummy'))
Error : NetCDF: Variable not found
Regards,
Pascal
Le 05/12/2012 22:08, Jannis a écrit :
Dear R community,
I quite frequently run into errors while u
I would like to take the values of observations and map them to a new index. I
am not sure how to accomplish this. The result would look like so:
x[1,2,3,4,5,6,7,8,9,10]
becomes
y[2,4,6,8,10,12,14,16,18,20]
The "newindex" would not necessarily be this sequence, but a sequence I have
stored i
Hello,
I am sorry, but I sincerely don't understand what you are trying to do.
Regards,
Pascal
Le 06/12/2012 11:47, Brian Feeny a écrit :
I would like to take the values of observations and map them to a new index. I
am not sure how to accomplish this. The result would look like so:
x[1,2
On Dec 5, 2012, at 6:47 PM, Brian Feeny wrote:
I would like to take the values of observations and map them to a
new index. I am not sure how to accomplish this. The result would
look like so:
x[1,2,3,4,5,6,7,8,9,10]
becomes
y[2,4,6,8,10,12,14,16,18,20]
This suggests to me that you a
If you `source("test.R", keep.source=FALSE)`, you will see that the
> line number is not reported.
>
>
Not always.
I have code that uses sapply to call another function and all I get back is
the line of the sapply.
Useful but in the 21st century I do think I could get more aid from the
runtime an
Hi,
On Thu, Dec 6, 2012 at 12:01 AM, Worik R wrote:
>
>
>> If you `source("test.R", keep.source=FALSE)`, you will see that the
>> line number is not reported.
>>
>
> Not always.
>
> I have code that uses sapply to call another function and all I get back is
> the line of the sapply.
The function
No, because it does not assign the indexes of myindex.
If its not possible, which I am assuming its not, thats OK. I thought that if
I had say 10 observations, sequentially ordered (or any order, it doesn't
matter), and I wanted to assign them specific indexes, and not have NA's, that
it was
Bert
R is compiled. Compile and go cycle is quick, but it is compiled. Not to
a machine executable but to an object the R runtinme can interperet.
Steve
It is all a bit hard. I can make progress the old fashioned way with debug
messages and conditional execution and dozens of other techniques
Hi Rich,
You can get ?rename() by either loading library(reshape) or library(plyr).
A.K.
- Original Message -
From: Rich Shepard
To: R help
Cc:
Sent: Wednesday, December 5, 2012 4:24 PM
Subject: Re: [R] Changing data frame column headings
On Wed, 5 Dec 2012, arun wrote:
> I am not
Hi,
By comparing the different methods:
set.seed(5)
mat1<-matrix(sample(1:1e6,1e6,replace=TRUE),ncol=1)
set.seed(25)
x<-sample(1:1e6,1,replace=TRUE)
system.time(z1<-sweep(-mat1,2,x,"+"))
# user system elapsed
# 0.076 0.000 0.069
system.time(z2<-apply(-mat1,1,`+`,x))
# user
Dear Dr. Bernhard
Thank you very much for quick reply. One good news is that i can connect
with Neos server. I appreciate your suggestion to change 'protocols' to
'proxy'. after assigning proxy, i can connect with my desired website.
Thankyou very much
With best regards
Rubel
On Thu, Dec 6, 2012
I'm trying to find a bootstrap based confidence band for a linear model.
I have created a data set with X and Y
X=runif(n,-1.25,1.25)
e=rnorm(n,0,1)
Y=exp(3*X)+5*sin((30*X)/(2*pi))+2*e
fit=lm(Y~X)
summary(fit)
I define a bootstrap function named PairedBootstrap which is not listed here.
Than I t
Hi,
This could be done using ?gsub()
set.seed(5)
dat1<-data.frame(alk_quant=sample(1:15,6,replace=TRUE),ph_quant=sample(5:9,6,replace=TRUE),tds_quant=sample(10:20,6,replace=TRUE))
names(dat1)<-gsub("(.*)\\_.*","\\1",names(dat1))
head(dat1,2)
# alk ph tds
#1 4 7 13
#2 11 9 16
A.K.
HI,
The option z5 takes care of it.
z5<-t(x-t(mat)) #still faster than ?sweep()
dim(z5)
[1] 20 2
identical(sweep(-mat,2,x,"+"),z5)
#[1] TRUE
A.K.
From: C W
To: arun
Sent: Wednesday, December 5, 2012 5:09 PM
Subject: Re: [R] data manipulation between vec
Hi,
Would it be okay to use:
y<-na.omit(y[myindex]<-x)
y
# [1] -1.36025132 -0.57529211 1.18132359 0.41038489 1.83108252 -0.03563686
#[7] 1.25267314 1.08311857 1.56973422 -0.30752939
A.K.
- Original Message -
From: Brian Feeny
To: "r-help@r-project.org help"
Cc:
Sent: Wednes
Dear All,
I am fitting scallop count data to negative binomial GAMs. I have two
significant parameters that explain 43%of the deviance. The adjusted r square
is 0.25. The gam.check function gives me the figure attached. In the graph of
linear predictor vs. residuals there seems to be more negat
Hi
see inline
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Lara Reichmann
> Sent: Wednesday, December 05, 2012 1:53 AM
> To: r-h...@lists.r-project.org
> Subject: [R] nlme starting values are not the correct length
>
> De
Yes, now I see.
It's ridiculous that I haven't noticed this elementary error, which I know
of for over 10 years. :)
Now my problem, it's another question.
Here is the code and data, as requested.
Sample data, I've copied a part of text file:
Charge Strobe [1]
Charge FC [2]
Charge SG
Can anyone please shed any light on why R DateTimeClasses give weird times for
when daylight saving time information changes, and which aren't consistent with
the OS?
Example:
Expected result: in New Zealand DST stopped (NZDT -> NZST) at 03:00
NZDT on 2010-04-04, as confirmed by the O
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