Is there a constructor for an mx.DateTime object which takes a
datetime.datetime object? It seems like a pretty common thing to do but
I didn't see such a constructor in the mx.DateTime docs.
Thanks
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I have html document titles with characters like >, , and
‡. How do I decode a string with these values in Python?
Thanks
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it occurs. It doesn't take too much code.
>
> On Nov 7, 1:34 pm, "mp" <[EMAIL PROTECTED]> wrote:
> > I have html document titles with characters like >, , and
> > ‡. How do I decode a string with these values in Python?
> >
> > Thanks
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there other options?
Second, is a cgi-bin directory really necessary? Are there security
issues with configuring Apache to allow cgi-bin execution in other
directories?
Thanks
MP
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rite(fin.fileno(),'blah')
fin.flush()
print os.read(fout.fileno(),256)
Calling try3() yields the error:
File "./test.py", line 54, in try3
print os.read(fout.fileno(),256)
OSError: [Errno 35] Resource temporarily unavailable
If anyone could help me accomplish t
se and what function should I use to modify a single
character once in that file mode?
Thanks
MP
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Code is at bottom. Basically, if I turn off socket blocking prior to
connecting, I get a "Socket is not connected" error when I try to send
data. However, if I do not turn off blocking, OR if I place a print
statement anywhere before the send call, it works! WTF?
I'd like to understand what's goin
Thanks Roy. I was just trying to understand someone else's code, but
in the end it turns out that this was just a bug.
What weirded me out was how injecting a print statement preventing the
error from occurring, but now I get it. Without blocking, the
connection handshake occurs in parallel after
to find the command 'clear'?
i'm using os x.
thanks
mp
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Does anyone know of an approximation to raising a negative base to a
fractional exponent? For example, (-3)^-4.1 since this cannot be
computed without using imaginary numbers. Any help is appreciated.
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On Oct 17, 4:05 am, Ken Schutte <[EMAIL PROTECTED]> wrote:
> [EMAIL PROTECTED] wrote:
> > Does anyone know of an approximation to raising a negative base to a
> > fractional exponent? For example, (-3)^-4.1 since this cannot be
> > computed without using imaginary numbers. Any help is appreciat
To compute the absolute value of a negative base raised to a
fractional exponent such as:
z = (-3)^4.5
you can compute the real and imaginary parts and then convert to the
polar form to get the correct value:
real_part = ( 3^-4.5 ) * cos( -4.5 * pi )
imag_part = ( 3^-4.5 ) * sin( -4.5 * pi )
|z
Just to clarify what I'm after:
If you plot (-3)^n where n is a set of negative real numbers between 0
and -20 for example, then you get a discontinuos line due to the
problem mentioned above with fractional exponents. However, you can
compute what the correct absolute value of the the missing poi
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