I have spent quite a bit of time trying to find the answer on this
group, but I've been unsuccessful. Here is what I'd like to be able to
do:
def A(**kwargs):
kwargs['eggs'] = 1
def B(**kwargs):
print(kwargs)
def C(**kwargs):
A(**kwargs)
B(**kwargs)
I'd like to be able to make a
On Mar 16, 9:59 pm, Chris Rebert wrote:
> On Mon, Mar 16, 2009 at 7:48 PM, Aaron Garrett
>
>
>
> wrote:
> > I have spent quite a bit of time trying to find the answer on this
> > group, but I've been unsuccessful. Here is what I'd like to be able to
> &g