Using the following (on PIC14):
var_u_char_8_b = (unsigned char) (var_int_16 / 8);
where:
var_u_char_8_b is unsigned char
var_int_16 is int
var_u_char_8_b always seems to be zero.
If I get rid of the /8 bit var_u_char_8_b appears (I assume) to hold the
least significant byte of var_int_16.
Is there a problem here? Am I missing something? The work round is
obvious, right shift by 4 bits, but that is less useful if I want to
divide by say 3 or 7.
Any thoughts?
Pete
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