On 10/11/2013 11:36 AM, Stuart Reedy wrote:
Greetings,
We are having some rights issues on Samba 3.6.18 running on Slackware64
14.0 (the official Slackware Package). One of our users is having
access issues and I believe I have traced the problem to the following
entry in the log.smbd:
Primary group is 0 and contains 0 supplementary groups
Issuing the groups command for this user returns the 8 Linux groups in
which the user has membership.
In researching this, I found another reference to this log entry for
which the solution had to do with Windows groups and their relationship
to local groups.
Since we are using Samba stand-alone, we do not create any Windows
groups and use local Linux groups for privileges. (I'm assuming Samba
can still be used this way.)
My question is: How does Samba calculate these group memberships?
I'll look through the source code and see what I can see, but I am no
programming wizard, so I doubt I'll find what I need there.
Thanks!
Stu...
OK, I found where Samba gets the Linux group information created a C
program that uses the same function (getgroups). Of course, this returns
the correct groups for the user for which Samba claims: Primary group is
0 and contains 0 supplementary groups
Also, the "id" command returns the Linux groups as expected:
uid=6032(REDACTED) gid=6000(REDACTED)
groups=6000(REDACTED),6001(REDACTED),6007(REDACTED),6009(REDACTED),6010(REDACTED),6011(REDACTED),6012(REDACTED),6013(REDACTED),6014(REDACTED)
I'm a a loss as to why this user is not getting the proper rights from
Samba.
Any ideas?
--
Stuart Reedy Working hard for a great university!
s...@coe.uky.edu
859 257-7966 http://www.coe.uky.edu/~stu/
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