Is there a way to change the default when calling "solve"?
Fernando
On 12/3/2023 8:37 AM, Dima Pasechnik wrote:
Yes, Sage modifies the defaults of Maxima, in particular we set domain to
complex.
On 3 December 2023 12:28:45 GMT, Oscar Benjamin<oscar.j.benja...@gmail.com>
wrote:
On Wed, 29 Nov 2023 at 12:40, Eric Gourgoulhon<egourgoul...@gmail.com> wrote:
Le mardi 28 novembre 2023 à 18:25:04 UTC+1, kcrisman a écrit :
Yes. Maxima's attitude is that the square root of negative one is an
expression which might have multiple values, rather than just picking one you
hope might be consistent over branch points.
To enforce Maxima to work in the real domain, avoiding to play too much with
complex square roots, one can add at the beginning of the Sage session:
maxima_calculus.eval("domain: real;")
Then the second example in the initial message of this thread yields
[[x == 2/5*sqrt(6)*sqrt(5), y == 16, l == 1/9*18750^(1/6)], [x ==
-2/5*sqrt(6)*sqrt(5), y == 16, l == -1/9*18750^(1/6)]]
instead of an empty list.
When using Maxima (5.45.1) directly I get this result with default settings:
(%i1) f: 10*x^(1/3)*y^(2/3)$
(%i2) g: 5*x^2 + 6*y$
(%i3) solve([diff(f,x)=l*diff(g,x), diff(f,y)=l*diff(g,y), g=120], [x,y,l]);
1/6
2 sqrt(6) 18750
(%o3) [[x = ---------, y = 16, l = --------],
sqrt(5) 9
1/6
2 sqrt(6) 18750
[x = - ---------, y = 16, l = - --------]]
sqrt(5) 9
Does Sage modify some Maxima settings related to this or does it call
something other than solve?
--
Oscar
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Fernando Q. Gouveahttp://www.colby.edu/~fqgouvea
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