Thanks, Nils.
A further question is thus how to do something like
v0,...,v*k*=SR.var('v', n=*k*)
when *k* varies.
Should I look at the implementation of SR.var?
Guillermo
On Sun, 6 Mar 2022 at 19:26, Nils Bruin <nbr...@sfu.ca> wrote:
> On Sunday, 6 March 2022 at 09:13:42 UTC-8 list...@gmail.com wrote:
>
>>
>> Beginner's questions, I guess.
>>
>> Some time ago, Emmanuel Charpentier wrote
>>
>> var("v", n=2)
>>
>> which gives
>>
>> (v0, v1)
>>
>> Where is this documented? I have been unable to find keywords for var
>> other than domain and latex_name. Are there any others?
>>
>
> This is documented on SR.var , which is slightly different from the
> top-level "var" you are referring to. It looks like the documentation on
> the top-level one wasn't updated when the feature was added to SR.var.
> Since top-level var just wraps SR.var, it automatically got the feature too.
>
>
>> Another question:
>> I have learnt to write
>> x,y,z=var('x,y,z')
>>
>
> You can do that, but with the top-level var it's not necessary (this is
> exactly where it differs from SR.var) :
> it will inject bindings for the created symbols in the current name space.
> This is a hack that is convenient for interactive use. In library code, you
> must use SR.var instead, in which case you have to write
>
> x,y,z = SR.var('x,y,z')
>
> ( with just "SR.var('x,y,z')" you'd create the symbols but you wouldn't
> bind them to anything).
>
> Is it possible to do the same for
>> v0,v1,v2=var('v', n=3)
>> without having to write explicitly the LHS?
>>
>
> Yes, that already works. If you use
>
> var('v', n=3)
>
> the names v0,v1,v2 in your current scope will be bound to the newly
> created symbols.
>
> There's been discussion about this when it was implemented:
>
> https://trac.sagemath.org/ticket/22813
>
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