You can use an exception, something as follows:
def is_lp_solvable(P):
try:
P.solve()
return True
except:
return False
Am Sonntag, 28. April 2019 14:31:31 UTC+2 schrieb husi...@gmail.com:
>
> Hello everyone! I would like to ask a question about the solvability of a
> linear programming problem.
> I use sagemath to check whether my LP problem has any feasible solution or
> not.
> The program is similar to the following one without details
> sage: p = MixedIntegerLinearProgram(maximization=False, solver = "PPL")
> sage: w = p.new_variable(integer=True, nonnegative=True)
> sage: p.set_objective(w[0])
>
> Then I use p.solve() to solve this problem, and when there is no feasible
> solution, the program will
> print out quite a few sentences with the last one like this:
> MIPSolverException: PPL : There is no feasible solution
>
> My question is whether I can define a True/False function such that when
> the LP porble p has any feasible solution,
> then it returens True; otherwise it returns False?
>
> Thank you very much for your kind help!
>
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