Indeed, primitive_length only consider periods that are
integer divisors of the total length. If you want other
periods you can use the (very slow)
sage: Word(S).periods()
[3, 6, 9]
Vincent
Le 17/12/2018 à 09:52, pc.chandr...@gmail.com a écrit :
Thank you. However if S=[1,2,3,1,2,3,1,2,3,1,2], it is showing 11 although
period is 3.
On Monday, December 10, 2018 at 1:26:50 PM UTC+5:30, vdelecroix wrote:
You can use
sage: w = Word(S)
sage: w.primitive_length()
[3]
sage: w.primitive()
word: 123
Le 09/12/2018 à 11:57, chandra chowdhury a écrit :
I have a sequence which I stored in an array.
I want to find the period of the sequence.
But the following code gives error.
S=[1,2,3,1,2,3]
S=Sequence(S)
print S.period()
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