Hello, I am trying to use Sage in my class with some basic problems about matrices. Several of the problems in the book are of the form “find all values of k such that … is consistent” where the … is some linear system where k appears. If doing these problems by hand, one would take the determinant and solve for the values of k where the determinant is not zero. Sometimes the linear system is large, so I want to be able to use the .determinant() command (or .echelon_form() for similar problems) on a matrix where k is an element. However, Sage is not letting me create such a matrix object, because it does not recognize my assume() command telling it that the variable k is rational (or real, for that matter; neither works).
I’m trying to mimic what is going on here: http://doc.sagemath.org/html/en/reference/calculus/sage/symbolic/assumptions.html When I type the following code, I get an error saying Sage is "unable to convert k to an element of a rational field" (I get this error with and without the assume()) var('k') assume(k,'rational') v = vec(QQ,[k,k,k]) Can someone please tell me how to make variables and matrices play nicely together? -- You received this message because you are subscribed to the Google Groups "sage-support" group. To unsubscribe from this group and stop receiving emails from it, send an email to sage-support+unsubscr...@googlegroups.com. To post to this group, send email to sage-support@googlegroups.com. Visit this group at https://groups.google.com/group/sage-support. For more options, visit https://groups.google.com/d/optout.
