On Tuesday, June 9, 2015 at 11:44:46 AM UTC-7, Nils Bruin wrote:
>
> On Tuesday, June 9, 2015 at 10:05:26 AM UTC-7, Phoenix wrote:
>>
>> @Lee Worden
>>
>> Your code is deciding the linear independence of the set
>> {v,v*A,v*A^2,...,v*A^{dim(A)}}
>>
>
> That would always be linear dependent and not what the proposed code does
>
>
>> But I want to decide the linear independence of the set {v,
>> A*v,..,,A^{dim(A)-1}*v}
>>
>
> Reading the documentation of A.iterates or the documentation of
> A.transpose will allow you to construct a solution to that problem quite
> easily.
>
Yes, I forgot the 'rows' option:
http://doc.sagemath.org/html/en/reference/matrices/sage/matrix/matrix0.html#sage.matrix.matrix0.Matrix.iterates
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