The string trick would do the job, but maybe the tree method would be
nicer. How can I walk in the tree ? Is the tree the one of simply or
another one ?
*Christophe BAL*
*Enseignant de mathématiques en Lycée **et développeur Python amateur*
*---*
*French math teacher in a "Lycée" **and **Python **amateur developer*
2015-03-09 15:44 GMT+01:00 slelievre <samuel.lelie...@gmail.com>:
> slelievre:
>
> projetmbc:
>>
>> suppose that I have *sqrt(6)*(sqrt(3)+5)*. How can I count
>>>
>> the number of square root in this expression ?
>>>
>>
>> sage: a = sqrt(6)*(sqrt(3)+5)
>> sage: a
>> sqrt(6)*(sqrt(3) + 5)
>> sage: s = str(a)
>> sage: s
>> 'sqrt(6)*(sqrt(3) + 5)'
>> sage: s.count('sqrt')
>> 2
>>
>
> or you could explore the expression's tree
> with a.operator(), a.operands(), etc., and
> count the number of 'sqrt' operators.
>
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