Hello, I apologize if I am confused but I have some behavior that surprises me. Both of these `in' expressions return True. (I just tested it on cloud.sagemath.com so I think it is not from my having an old version.)
V = VectorSpace(RDF,3) v1 = vector(RDF, [1, 2, 3]) v1 v1 in V v2 = vector(RDF, [1, 2, 3, 4]) v2 in V Naturally, I think the second should say False (I am working with a two year old doc and I believe it used to come back False). The behavior that I expect happens for subspaces, so I think it is reasonable to expect `in' to do that. V = VectorSpace(RDF,3) v1 = vector(RDF, [2, 1, 0]) v2 = vector(RDF, [-2, 0, 1]) W = V.span([v1, v2]) v3 = vector(RDF, [0, 1, 1]) v3 in W v4 = vector(RDF, [1, 0, 0]) v4 in W Here the first `in' return True and the second returns False, as I expect. Regards, Jim -- You received this message because you are subscribed to the Google Groups "sage-support" group. To unsubscribe from this group and stop receiving emails from it, send an email to sage-support+unsubscr...@googlegroups.com. To post to this group, send email to sage-support@googlegroups.com. Visit this group at http://groups.google.com/group/sage-support. For more options, visit https://groups.google.com/d/optout.
