"range(2)" is not suited for cartesian product. If you want to
consider integer mod 2 you can use

cartesian_product([Zmod(2)] * 10)

Vincent

2014-08-14 11:47 UTC, Jori Mantysalo <jori.mantys...@uta.fi>:
> To get for example all bit vectors of size 3 one can say
>
> CartesianProduct(range(2), range(2), range(2)).list()
>
> To get this done for given n one can say at least
>
> a=CartesianProduct(range(2)).list()
> for n in range(1,n):
>      a=[flatten(x) for x in CartesianProduct(a, range(2)).list()]
>
> Is there any direct (and quite possibly faster) way to accomplish this?
>
> --
> Jori Mäntysalo
>
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