On Thursday, June 5, 2014 11:24:39 PM UTC-4, Robert Dodier wrote:
>
> On 2014-06-06, kcrisman <kcri...@gmail.com <javascript:>> wrote: 
>
> > lim(1/n^2*integrate(sin((2*n+1)*x)/sinh(x),x,0,pi/2),n=infinity) 
>
> I couldn't make any progress with the integral (in Maxima). 
> Computing the integral numerically with quad_qawo (same function should 
> be in Sage somewhere) suggests that it's pi/2 as n increases without 
> bound. So I'm guessing the limit is zero. 
>
> If you need a proof, maybe you can show the integral is bounded, 
> therefore the limit is zero. 
>

See also http://sourceforge.net/p/maxima/mailman/message/32423506/ for a 
few more comments on this. 

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