Thank you.

On 18 July 2013 16:09, William Stein <wst...@gmail.com> wrote:

> On Thu, Jul 18, 2013 at 12:53 PM, Santanu Sarkar
> <sarkar.santanu....@gmail.com> wrote:
> > Over integer.
>
> I did
>
> R.<x> = QQ[x]
> f = x*(x^3+1)*(x-17)
>
> then looked at f.roots?? which says it uses f.factor.  So I looked at
> f.factor?? and it uses Pari.  (It probably helped that I wrote a lot
> of this code.)
>
> So the answer appears to be the Sage completely factors the polynomial
> using Pari, then pulls off the degree 1 factors to give the roots.
>
> I make no claim that this is in any way the best approach -- it really
> can't be in general.  For example, if you can factor the constant term
> of the polynomial, then simply checking through divisors might be
> dramatically faster (depending on how many divisors there are).
>
> William
>
> >
> >
> > On 18 July 2013 15:50, William Stein <wst...@gmail.com> wrote:
> >>
> >> On Thu, Jul 18, 2013 at 11:54 AM, Santanu Sarkar
> >> <sarkar.santanu....@gmail.com> wrote:
> >> > What algorithm is used in Sage to calculate the roots of a polynomial
> >> > f(x)?
> >> > Corresponding Sage function is f.roots()
> >>
> >> What is the base ring?   There are a dozen answers, depending on the
> >> ring in which the coefficients of f live...
> >>
> >> >
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> >>
> >>
> >>
> >> --
> >> William Stein
> >> Professor of Mathematics
> >> University of Washington
> >> http://wstein.org
> >>
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> --
> William Stein
> Professor of Mathematics
> University of Washington
> http://wstein.org
>
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