thank you

On 9 déc, 12:52, achrzesz <achrz...@wp.pl> wrote:
> On Dec 9, 12:18 pm, David Joyner <wdjoy...@gmail.com> wrote:
>
>
>
>
>
>
>
>
>
> > This is a question for sage-support, which I am ccing.
>
> > On Fri, Dec 9, 2011 at 5:04 AM, Jean-Patrick Pommier
>
> > <jeanpatrick.pomm...@gmail.com> wrote:
> > > Hi,
> > > Is it possible to solve equation with complex variable such 1/z=1+i?
>
> > > I try without success:
>
> > > show(solve(1/z==i,z))
> > >  which returns
> > >  [] (-i waited).
>
> > > I didn't succeed well with:
> > > z/conjugate(z)=z which is z0=1
>
> > > I try also:
> > > z=1+i
> > > abs(z)=sqrt(2)
>
> > > but arg(z) gives  0.785398163397
> > > How to get the symbolic value  pi/4?
>
> > > Thank you
> > > Jean-Patrick
>
> > > --
> > > You received this message because you are subscribed to the Google Groups
> > > "sage-edu" group.
> > > To view this discussion on the web visit
> > >https://groups.google.com/d/msg/sage-edu/-/I9Tv6zZKtg4J.
> > > To post to this group, send email to sage-...@googlegroups.com.
> > > To unsubscribe from this group, send email to
> > > sage-edu+unsubscr...@googlegroups.com.
> > > For more options, visit this group at
> > >http://groups.google.com/group/sage-edu?hl=en.
>
> sage: var('z')
> z
> sage: solve(1/z==i,z)
> [z == -I]
>
> sage: solve(z/conjugate(z)==z,z)
> [z == 1]
>
> sage: (1+i).maxima_methods().polarform()
> sqrt(2)*e^(1/4*I*pi)
> sage: (1+i).maxima_methods().carg()
> 1/4*pi

-- 
To post to this group, send email to sage-support@googlegroups.com
To unsubscribe from this group, send email to 
sage-support+unsubscr...@googlegroups.com
For more options, visit this group at 
http://groups.google.com/group/sage-support
URL: http://www.sagemath.org

Reply via email to