thank you On 9 déc, 12:52, achrzesz <achrz...@wp.pl> wrote: > On Dec 9, 12:18 pm, David Joyner <wdjoy...@gmail.com> wrote: > > > > > > > > > > > This is a question for sage-support, which I am ccing. > > > On Fri, Dec 9, 2011 at 5:04 AM, Jean-Patrick Pommier > > > <jeanpatrick.pomm...@gmail.com> wrote: > > > Hi, > > > Is it possible to solve equation with complex variable such 1/z=1+i? > > > > I try without success: > > > > show(solve(1/z==i,z)) > > > which returns > > > [] (-i waited). > > > > I didn't succeed well with: > > > z/conjugate(z)=z which is z0=1 > > > > I try also: > > > z=1+i > > > abs(z)=sqrt(2) > > > > but arg(z) gives 0.785398163397 > > > How to get the symbolic value pi/4? > > > > Thank you > > > Jean-Patrick > > > > -- > > > You received this message because you are subscribed to the Google Groups > > > "sage-edu" group. > > > To view this discussion on the web visit > > >https://groups.google.com/d/msg/sage-edu/-/I9Tv6zZKtg4J. > > > To post to this group, send email to sage-...@googlegroups.com. > > > To unsubscribe from this group, send email to > > > sage-edu+unsubscr...@googlegroups.com. > > > For more options, visit this group at > > >http://groups.google.com/group/sage-edu?hl=en. > > sage: var('z') > z > sage: solve(1/z==i,z) > [z == -I] > > sage: solve(z/conjugate(z)==z,z) > [z == 1] > > sage: (1+i).maxima_methods().polarform() > sqrt(2)*e^(1/4*I*pi) > sage: (1+i).maxima_methods().carg() > 1/4*pi
-- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org