Thanks for the swift reply! That is a neat function, but I don't think
it is what I need. I was being too unclear, so here is an example:

Let R = Q[x], f1 = x^2 + 1 and f2 = x + 3 and g = x4+x3+4x2+x+3. We
wish to write g as a polynomial in f1 and f2 over Q; more precisely,
we wish to find a q



On Apr 5, 1:42 pm, Mike Hansen <mhan...@gmail.com> wrote:
> On Tue, Apr 5, 2011 at 1:24 PM, Johan S. R. Nielsen
>
> <santaph...@gmail.com> wrote:
> > Let's say that I have a multivariate polynomial ring R which contains
> > the polynomials p, f1, ..., fn. I also know that p is in the ideal J =
> > <f1,..., fn>. Now I wish to write p as a polynomial in the f-
> > polynomials. How can I do that with Sage?
>
> The main tool for you to use is the lift method.
>
> sage: R.<x0,x1,x2,x3> = PolynomialRing(QQ)
> sage: f = x0^2*x1 + x1^2*x2 + x2^2*x3 + x3^2*x0
> sage: (f0, f1, f2, f3) = [f.derivative(v) for v in [x0, x1, x2, x3]]
>  sage: I = R.ideal(f0, f1, f2, f3)
> sage: p = x0*f0 + x1*f1 + x2*f2 + x3*f3; p
> 3*x0^2*x1 + 3*x1^2*x2 + 3*x2^2*x3 + 3*x0*x3^2
> sage: p in I
> True
> sage: p.lift(I)
> [x0, x1, x2, x3]
> sage: p.lift(I.gens()) #Also works
> [x0, x1, x2, x3]
>
> Those are the coefficients in front of the f-polynomials used to form p.
>
> --Mike

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