Hello Simon
thanks for this. One problem
with the solution you mention is that I can't do the
general case. What I need is the sage equivalent
of mathematica's Reduce[] function.
Is there one?
rksh
On Thu, Aug 19, 2010 at 10:06 PM, Simon King <simon.k...@nuigalway.ie> wrote:
> Hi!
>
> On 19 Aug., 22:41, robin hankin <hankin.ro...@gmail.com> wrote:
>> sage>solve([a*b==15*I-5,a*conjugate(b)==-13*I+9],[a,b])
>> []
>>
>> So, from the first two lines I know that a=2+I, b=1+7I should
>> be a solution to the system in the third, yet solve() returns empty.
>
> Admittedly I am no expert for symbolics, and I don't know if maxima
> (which is used when you do the above solve command) can do those
> things in principle.
>
> But it would certainly be allowed to reformulate the equations in a
> way that makes it more easy to solve: Express the equations by real
> and imaginary part. Hence, writing a as xa+I*ya and b as xb+Iyb, you
> would do
> sage: var('xa ya xb yb')
> (xa, ya, xb, yb)
> sage: solve([xa*xb-ya*yb==-5, xa*yb+ya*xb==15, xa*xb+ya*yb==9, -
> xa*yb+ya*xb==-13],[xa,ya,xb,yb])
> [[xa == 2/r1, ya == (1/r1), xb == r1, yb == 7*r1]]
>
> So, r1=1 yields the solution that you found.
>
> Cheers,
> Simon
>
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--
Robin Hankin
Uncertainty Analyst
hankin.ro...@gmail.com
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