i tried the first example in the given link and i get the following error:
sage: V0 = span([[1/2,0,0],[3/2,2,1],[0,0,1]],ZZ)
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
/home/j_schn14/<ipython console> in <module>()
/usr/lib/python2.5/site-packages/sage/modules/free_module.pyc in span(R,
gens, check, already_echelonized)
349 [1 0 1]
350 """
--> 351 if len(gens) == 0:
352 return FreeModule(R, 0)
353 else:
/usr/lib/python2.5/site-packages/sage/rings/integer_ring.so in
sage.rings.integer_ring.IntegerRing_class.__len__
(sage/rings/integer_ring.c:3903)()
TypeError: len() of unsized object
is this a bug, or am I doing something wrong?
greatz Mad
Am 19.06.2010 00:32, schrieb William Stein:
> On Fri, Jun 18, 2010 at 3:26 PM, Mad <dajo.m...@web.de> wrote:
>
>> Hi folkz,
>> i want to create a quotient of two submodules generatet by some
>> vektors and i don't know how to do this.
>>
> See the examples here:
>
> http://sagemath.org/doc/reference/sage/modules/fg_pid/fgp_module.html
>
> Already, the first example there is what you're asking about.
>
> William
>
>
>> i tried this:
>> m = ZZ^2
>> m1 = m.submodul([2,1],[1,2]) #this is ZZ^2 again, but of type
>> 'sage.modules.free_module.FreeModule_submodule_pid'
>> m2 = m.submodul([3,2],[2,1])
>> #i want to do something like:
>> mQuot = m1.quotient(m2)
>>
>> but m1 (or FreeModule_submodule_pid) does not have a member quotient
>> like it has sage.modules.free_module.FreeModule_ambient_pid (of wich
>> typ m is).
>>
>> How do i have to do it?
>>
>> greatz and thnx for your tipps and answers Mad
>>
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>
>
>
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