Thank you very much for your kind help.

On 25 April 2010 17:00, Simon King <simon.k...@nuigalway.ie> wrote:

> On 25 Apr., 12:50, Santanu Sarkar <sarkar.santanu....@gmail.com>
> wrote:
> > Sorry again. Dependency needs over integer.
>
> Probably there is a better way of doing it, but the following works:
>
> Transform the problem into a matrix: One row for each polynomial, one
> column for each monomial that occurs in one of the polynomials, and
> the entries given by the coefficient of a monomial in a polynomial.
>
> Hence:
> sage: R.<x1,x2,x3>=ZZ[]
> sage: f1=1+x1+x2+x1*x2
> sage: f2=1+x1+x3+x1*x3
> sage: P = [f1, f2, f1*f2, x1*f2, x2*f2]  # the list of polynomials
> sage: V = list(set(sum([p.monomials() for p in P],[]))) # the list of
> all occuring monomials
> sage: V
> [1, x1*x2*x3, x1*x3, x1*x2, x1, x1^2, x3, x2, x1^2*x2, x1^2*x3, x2*x3,
> x1^2*x2*x3]
> sage: p_to_dict = lambda p: dict([(x[1],x[0]) for x in list(p)]) # an
> auxiliary function
> sage: D = [p_to_dict(p) for p in P]  # list of dictionaries providing
> the coefficients
> sage: M = Matrix(ZZ, [[d.get(m,0) for m in V] for d in D])
> sage: M
> [1 0 0 1 1 0 0 1 0 0 0 0]
> [1 0 1 0 1 0 1 0 0 0 0 0]
> [1 2 2 2 2 1 1 1 1 1 1 1]
> [0 0 1 0 1 1 0 0 0 1 0 0]
> [0 1 0 1 0 0 0 1 0 0 1 0]
> sage: M.kernel()
> Free module of degree 5 and rank 0 over Integer Ring
> Echelon basis matrix:
> []
>
> So, no linear dependency.
>
> But, as I said, I would expect that it can be done better, and I even
> don't know if the above transformations are efficiently done.
>
> Cheers,
> Simon
>
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