Not really relevant to your question but e = 1 + 1 + 1/2 + 1/6 + ... On Feb 23, 10:22 am, Santanu Sarkar <sarkar.santanu....@gmail.com> wrote: > How I calculate the integer part of e^100, where e=1+1/2+1/6+.... i,e > logarithmic e ?
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