I learned too much from all your answers.
One has to remember, that sage looks like Python but is not. REMEMBERED ;-)
Peter
2010/2/8 davedo2 <dave...@gmail.com>
> Thanks to all of you...Dave
>
> On Feb 7, 3:23 pm, Alex Ghitza <aghi...@gmail.com> wrote:
> > On Sun, 7 Feb 2010 15:17:08 -0800 (PST), davedo2 <dave...@gmail.com>
> wrote:
> > > I want to run a range of numbers through the factor() function and if
> > > I run a loop through a list as in:
> > > for i in [25,37,205]:
> > > print i.factor()
> > > it works fine, but if I try
> > > for i in range(1,5):
> > > print i.factor()
> > > I get the error message 'int' object has no attribute 'factor' - how
> > > do I get
> > > factor() to work with a range? Thanks...Dave
> >
> > range() returns Python integers, which do not have a factor() method.
> > You need to get Sage integers instead, so use srange() or xsrange():
> >
> > sage: srange(5)
> > [0, 1, 2, 3, 4]
> > sage: type(srange(5)[2])
> > <type 'sage.rings.integer.Integer'>
> > sage: for i in srange(1, 5):
> > print i.factor()
> > 1
> > 2
> > 3
> > 2^2
> >
> > Best,
> > Alex
> >
> > --
> > Alex Ghitza -- Lecturer in Mathematics -- The University of Melbourne
> > -- Australia
> > --http://www.ms.unimelb.edu.au/~aghitza/<http://www.ms.unimelb.edu.au/%7Eaghitza/>
>
> --
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