On 16 říj, 21:32, Laurent <moky.m...@gmail.com> wrote:
> a = 1
> b = 2
> c = 3
> d = 8
> print "\\frac{",a,"-",b,"}{",c,"-",d,"}=",(a-b)/(c-d)
perhaps print "\\frac{",a,"-(",b,")}{",c,"-",d,"}=",(a-b)/(c-d) if
b<0
Robert
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