Hi, I'm trying to convert a bunch of strings representing integers to sage Integers using the Integer function. The problem is that the Integer function assumes the number is in octal if there is a 0 before the number. Is there a way to disable this assumption and force Integer to treat the strings I am giving it as decimal numbers. If this can't be done, I suggest adding this option in the Integer function. As a workaround, I give my string to int before passing it to Integer. like this:
number = Integer( int( "09" ) ) But it would be great to be able to do something like: number = Integer( "09", radix=decimal ) thanks Marco Robado --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
