I had a small typo in the last code.  The line that said

F = FractionField(K)

should have read

F = FractionField(R)

also after the line that starts with "vars = " should be the line

R = PolynomialRing(Rationals(),k,vars)

On Aug 5, 4:59 pm, VictorMiller <victorsmil...@gmail.com> wrote:
> Okay, Here's some code (in case anyone is interested, this was related
> to a problem that appeared on the math-fun mailing list):
>
> def ECurve(n,k):
>    vars = ['a%d_%d'%(n,i) for i in range(k)]
>    v = R.gens()
>    F = FractionField(K)
>    S.<x> = F[]
>    f = (x^n-1)//(x-1)
>    g = x^k + sum([v[i]*x^i for i in range(k)])
>    c = (f%g).coefficients()
>    return R.ideal([z.numerator() for z in c[1:]).groebner_basis()
> def Curve1(n,k)
>    I = ECurve(n,k)
>    if len(I) == 0:
>       return I
>    R = I[0].parent()
>    II = R.ideal(I)
>    J = II.elimination_ideal(R.gen()[:-2])
>    S.<b1,b2> = QQ[]
>    phi = R.hom((k-2)*[S(0)] + [b1,b2])
>    return Curve(phi(J.gens()[0]))
>
> C = Curve1(9,3)
>
> print C.genus()
>
> On Aug 5, 4:12 pm, William Stein <wst...@gmail.com> wrote:
>
> > On Wed, Aug 5, 2009 at 1:09 PM, VictorMiller <victorsmil...@gmail.com>wrote:
>
> > > I was asking SAGE to do a calculation that I knew was probably
> > > laborious -- I had a plane curve (over Q) and I wanted its genus.  I
> > > defined it with C=Curve(equation_in_two_variables) and then typed
>
> > > C.genus()
>
> > > after a while (I was in the notebook) I just got the mysterious error
> > > message:
>
> > > delaybeforesend: 0
>
> > > when I expanded it, at the end there was a lot of stuff, but the
> > > relevant line was
>
> > > pexpect.TIMEOUT: Timeout exceeded in read_nonblocking().
> > > <pexpect.spawn instance at 0xa1c170c>
> > > command: /u/victor/sage/local/bin/Singular
>
> > > So, there are two questions:
>
> > > a) is it possible to give a more informative error message.  It seems
> > > obvious that singular just took
> > > too long in getting back to sage.
>
> > This is not obvious to me.  That is really weird.  Sage should wait forever
> > for any subprocess to return.   The time limit on reading is purposely
> > disabled.  Weird.   Maybe the subprocess really crashed and the error
> > message is just wrong?    Or maybe something is screwy with pexpect.   Can
> > you post code?  Has anybody else seen anything similar?
>
> > William
>
> > > b) is it possible to give a longer timeout (if I really want the
> > > answer)?
>
> > > Victor
>
> > --
> > William Stein
> > Associate Professor of Mathematics
> > University of Washingtonhttp://wstein.org
>
>
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