On May 6, 2009, at 7:44 PM, jimfar wrote: > After generating > sage: B=AlternatingGroup(5) > > and verifying an element is in it, > sage: c=(1,2,3) > sage: c in B > True > > How do I find the inverse of c in B?
Your c here isn't really a permutation element, it's just a tuple. To create (and manipulate) the actual permutation element do: sage: c = B((1,2,3)); c (1,2,3) sage: c^-1 (1,3,2) sage: c^2 (1,3,2) sage: parent(c) Alternating group of order 5!/2 as a permutation group - Robert --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
