On May 4, 2009, at 11:19 AM, kcrisman wrote: > >> Actually, Dokchitser's algorithm only handles functions with finitely >> many poles, so it won't be able to handle this if L(s) = 1/zeta(s). > > Yes, the series which comes from Moebius mu ends up being 1/zeta, > essentially "because" mu is the Dirichlet inverse of the unit function > u (where u(n)=1 for all n). The Euler product makes this trivial by > hand as well, but I didn't know if the computer also could do that > manipulation, similarly to when one "verifies" that diff(x^3,x)==3*x^2 > with Sage to show it at least does the right thing for obvious > examples. > > Hmm, so what now? I would have tried using lcalc but it doesn't seem > to have a way to accept input of this type. I really just want to > show a few values/graph this function.
Given that it's a theorem that (your) L(s) = 1/zeta(s), then just plot 1/zeta(s). - Robert --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
