> > sage: foo.edges() > [(0, 1, 2), (0, 2, 1), (2, 3, 3)] > sage: bar.edges() > [(0, 1, 1), (0, 2, 2), (2, 3, 3)] > sage: bar.is_isomorphic(foo, edge_labels = True) > True
I think there is a label-preserving isomorphism here, isn't there? 0->0 1->2 2->1 3->3 Nathan --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
