On Fri, Jan 9, 2009 at 3:49 AM, Sand Wraith <omegat...@gmail.com> wrote: > > Hi! > > Is it possible to get order of root of equation? For example equation: > > f(x)=(x+1)^2 > and it's solution "solve(f,x)" will be "[x == -1]", but this is not > perfect clear, because x==-1 have second order. This equation actually > must have two same roots: [x == -1,x == -1].
Use the roots command: sage: f = (x + 1)^2 sage: f.roots() [(-1, 2)] The 2 is the multiplicity. William --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
