One way to do it (for a 10x10): sage: n = 10 sage: M = Matrix(n,n,[[1/(i+j) for i in range(1,11)] for j in range(1,11)]) sage: M
[ 1/2 1/3 1/4 1/5 1/6 1/7 1/8 1/9 1/10 1/11] [ 1/3 1/4 1/5 1/6 1/7 1/8 1/9 1/10 1/11 1/12] [ 1/4 1/5 1/6 1/7 1/8 1/9 1/10 1/11 1/12 1/13] [ 1/5 1/6 1/7 1/8 1/9 1/10 1/11 1/12 1/13 1/14] [ 1/6 1/7 1/8 1/9 1/10 1/11 1/12 1/13 1/14 1/15] [ 1/7 1/8 1/9 1/10 1/11 1/12 1/13 1/14 1/15 1/16] [ 1/8 1/9 1/10 1/11 1/12 1/13 1/14 1/15 1/16 1/17] [ 1/9 1/10 1/11 1/12 1/13 1/14 1/15 1/16 1/17 1/18] [1/10 1/11 1/12 1/13 1/14 1/15 1/16 1/17 1/18 1/19] [1/11 1/12 1/13 1/14 1/15 1/16 1/17 1/18 1/19 1/20] On Wed, Dec 10, 2008 at 5:19 PM, Alasdair <[EMAIL PROTECTED]> wrote: > > The title pretty much says it all - for example, how would I create a > 4x4 matrix whose (i,j)-th element is 1/(i+j)? > > Thanks, > Alasdair > > > > --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
