thank you! ))
but I need to use my values, now just variables (Ts,Pole1 etc)
I was trying this:
r=2*2*pi
Pole1=r*exp(I*2*pi/3)
Pole2=-r
Pole3=r*exp(-I*2*pi/3)
Ts=0.1
z = exp(I*2*pi*Ts*f)
p = (2/Ts)*(z-1)/(z+1)
H = (p^3)/((p-Pole1)*(p-Pole2)*(p-Pole3))
show(H)
show() works fine, but if i want to use H function now:
round(H(4).abs(),5)
a have got "Type error" message :-\
On Dec 9, 2:11 am, bsdz <[EMAIL PROTECTED]> wrote:
> (Sorry if this reply appears twice - 1st one disappeared?)
>
> This worked for me: -
>
> H, p, Pole1, Pole2, Pole3, Ts, z, f = var("H p Pole1 Pole2 Pole3 Ts z
> f")
> p = (2/Ts)*(z-1)/(z+1)
> z = exp(I*2*pi*Ts*f)
> H = (p^3)/((p-Pole1)*(p-Pole2)*(p-Pole3))
> show(H)
>
> The only difference is that I have declared the variables in the first
> line. Hope that helps.
>
> On Dec 8, 5:58 pm, Sand Wraith <[EMAIL PROTECTED]> wrote:
>
> > Hi all! Please help me to replace variables:
>
> > I have this function:
>
> > H(p)=(p^3)/((p-Pole1)*(p-Pole2)*(p-Pole3))
>
> > where Pole1,Pole2,Pole3 - complex:
>
> > r=2*2*pi
> > Pole1=r*exp(I*2*pi/3)
> > Pole2=-r
> > Pole3=r*exp(-I*2*pi/3)
> > Ts=0.1
>
> > And I need to make a few replaces:
>
> > need to replace "p" with "(2/Ts)*(z-1)/(z+1)", where z is a new
> > variable, and then replace "z" with "exp(I*2*pi*Ts*f)". To have H(f)
> > function at the end.
>
> > I am trying to write:
>
> > z=exp(I*2*pi*Ts*f)
> > p=(2/Ts)*(z-1)/(z+1)
> > H=(p^3)/((p-Pole1)*(p-Pole2)*(p-Pole3))
>
> > and now if I want to look at H:
> > H
> > or
> > show(H)
> > I've got many errors...
>
> > tail of long output:
>
> > <sage-display>
> > stdin:16:Incorrect syntax: Syntax error
> > _tmp_ : (8000.0(
> > ^
> > <sage-display>(%o90)
>
> > what is wrong with it?
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