Tim Lahey wrote:
>
> On Nov 25, 2008, at 12:33 AM, Jason Grout wrote:
>> sage: import sympy
>> sage: var('x,a,b')
>> (x, a, b)
>> sage: f1=1/(a*x+b)
>> sage: sympy.integrate(sympy.sympify(f1),sympy.sympify(x))
>> 1/a*log(b + a*x)
>> sage: sympy_integrate = lambda f,x: sympy.integrate(sympy.sympify(f),
>> sympy.sympify(x))
>> sage: sympy_integrate(f1,x)
>> 1/a*log(b + a*x)
>>
>
> Good to know. But, in order to get proper timings, I need to
> skip the sympify inside the integrate.
I suppose you could separately run timeit on the sympy.sympify calls,
then subtract that from the integration, if you wanted to work that way.
But it sounds like you already have a way worked out.
Thanks for working on this!
-Jason
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