Thanks for the answers. By the way: > Infinite fields of characteristic p aren't perfect,
Isn't the algebraic closure of F_p perfect? For fields of characteristic p, perfect should mean that every element has a pth root. (I agree that some infinite fields of characteristic p aren't perfect, but this is not true for all of them.) John > because the definition > of perfect is that "every finite extension is separable". > In any case, Sage is I think very limited regarding non-finite characteristic > p fields, unfortunately (e.g., function fields of curves over finite fields). > This is one of those things that Magma is unusually good at. > > William --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
