On Tue, Oct 21, 2008 at 9:35 PM, Jason Merrill <[EMAIL PROTECTED]> wrote: > > sage: 1492.digits(10) > [2, 9, 4, 1] > > Now is there an easy way to take this list and get back the integer > 1492?
I'm not sure if there is a single function that does it, but you can use the following one liner which does what you think you should do to reconstruct the number from its digits: sage: n = 10; sum([d*n**i for i,d in enumerate(1492.digits(n))]) 1492 sage: n = 10; sum([d*n**i for i,d in enumerate(123.digits(n))]) 123 sage: n = 3; sum([d*n**i for i,d in enumerate(123.digits(n))]) 123 --Mike --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
