On Sat, Sep 20, 2008 at 10:20 AM, John Cremona <[EMAIL PROTECTED]> wrote: > > That's a good point. > > 2008/9/20 pong <[EMAIL PROTECTED]>: >> >> This is not a bug report. But I'm not sure where to post a suggestion. >> >> In the SAGE tutorial, http://www.sagemath.org/doc/tut/node27.html >> >> there is an example: >> >> sage: c = factorial(25); c >> 15511210043330985984000000 >> sage: [valuation(c,p) for p in prime_range(2,23)] >> [22, 10, 6, 3, 2, 1, 1, 1] >> >> Since prime_range(2,23) does not include 23 itself, maybe it's better >> to change it to prime_range(2,25). In that case, the product of primes >> to the corresponding powers will actually give the factorial of 25. > > I would also include > sage: c.factor() > 2^22 * 3^10 * 5^6 * 7^3 * 11^2 * 13 * 17 * 19 * 23 > (which would be helpful to people who might know know this meaning of > "valuation", standard in number theory), and even perhaps > sage: list(c.factor()) > [(2, 22), (3, 10), (5, 6), (7, 3), (11, 2), (13, 1), (17, 1), (19, 1), (23, > 1)] > > John Cremona
I've made this trac #4163: http://trac.sagemath.org/sage_trac/ticket/4163 William --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
