On Dec 7, 2007 9:32 AM, pgdoyle <[EMAIL PROTECTED]> wrote:
>
> Consider this python program:
>
> ----------------
> def foo():
> return 'foo'
>
> print foo()
>
> def mumble():
> print 'mumble',foo()
>
> mumble()
> ----------------
>
> If put this in a file foo.py and type `python foo.py' it prints
>
> foo
> mumble foo
>
> Same thing if I type 'sage foo.py'. Same thing if I put it in a cell
> of a sage notebook and evaluate with sage.
> But if switch the evaluation option for the notebook from sage to
> python I get an error:
>
> foo
> mumble
> Traceback (most recent call last):
> File "<stdin>", line 1, in <module>
> File "/home/doyle/.sage/sage_notebook/worksheets/admin/2/code/
> 68.py", line 12, in <module>
> print mumble()''', '/home/doyle/.sage/sage_notebook/worksheets/
> admin/2/cells/5')
> File "/usr/local/sage/local/lib/python2.5/site-packages/sage/server/
> support.py", line 258, in syseval
> return system.eval(cmd, locals = sage_globals)
> File "/usr/local/sage/local/lib/python2.5/site-packages/sage/misc/
> python.py", line 21, in eval
> eval(z, globals, locals)
> File "/usr/local/sage-2.8.15-ubuntu32bit-i686-Linux/data/extcode/
> sage/", line 1, in <module>
>
> File "/usr/local/sage-2.8.15-ubuntu32bit-i686-Linux/data/extcode/
> sage/", line 7, in mumble
>
> NameError: global name 'foo' is not defined
>
> I get the same error if I change the notebook evaluation option back
> to sage, put %python at the beginning of the cell, and evaluate.
>
> Is this a bug or a feature?
This is definitely a bug. Thanks for reporting it! I've put it here:
http://trac.sagemath.org/sage_trac/ticket/1423
I only have a minute at the moment, but just want to remark
that when you do %python in the notebook or use python
mode, here is the Python code that actually evaluates the
input to the cell:
sage: python.eval??
File: /Users/was/s/local/lib/python2.5/site-packages/sage/misc/python.py
Source Code (starting at line 5):
def eval(self, x, globals={}, locals={}):
x = x.strip()
y = x.split('\n')
if len(y) == 0:
return ''
s = '\n'.join(y[:-1]) + '\n'
t = y[-1]
try:
z = compile(t + '\n', '', 'single')
except SyntaxError:
s += '\n' + t
z = None
#else:
# s += '\n' + t
eval(compile(s, '', 'exec'), globals, locals)
if not z is None:
eval(z, globals, locals)
return ''
Looking at that code, does anybody see why the second global foo gets
ignored inside
the function body of mumble? I don't immediately see why.
William
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