This is what you really want to do (use a *callable* symbolic expression):
sage: def g(a,b,c):
f(x,y) = a*x^2 + b*y + c
return f
....:
sage: h = g(1,2,3)
sage: h
(x, y) |--> 2*y + x^2 + 3
sage: h(2,3)
13
On 8/27/07, Justin Walker <[EMAIL PROTECTED]> wrote:
>
> Hi, all,
>
> I want to create a "function" within a function, and return it as the value
> of the latter function, something along the lines of:
>
> def g(a,b,c):
> var('x y')
> f = a*x^2 + b*y + c
> return f
>
> This works, almost. I have to invoke the return value as a function
> returning a function:
>
> sage: f = g(1,2,3)
> sage: f(0)
> 2*y + 3
> sage: f(0)(1)
> 5
>
> I can't treat it as a function of two variables:
>
> sage: f(0,1)
> ---------------------------------------------------------------------------
> <type 'exceptions.TypeError'> Traceback (most recent call last)
>
> /SandBox/Justin/sb/Sage/Code/<ipython console> in <module>()
>
> <type 'exceptions.TypeError'>: __call__() takes at most 2 arguments (3 given)
> sage:
>
> It's not clear from the doc what should happen, but this is a bit of a
> surprise.
>
> Justin
>
> --
> Justin C. Walker, Curmudgeon-At-Large
> Institute for the Enhancement of the Director's Income
> --------
> When LuteFisk is outlawed,
> Only outlaws will have LuteFisk
> --------
>
> >
>
--
William Stein
Associate Professor of Mathematics
University of Washington
http://www.williamstein.org
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