On Thu, Aug 25, 2016 at 10:14 AM, Wei, Huayi <weihu...@xtu.edu.cn> wrote:
> Hi, David,
>
> Thanks for your reply.
>
> so `g1` is a expression and `g2` is a function.
>
> And `g1(t=2)` is a substitution and `g2(2)` is a function call.
>
> Have I understood correctly?
>

Yes.

> Best
>
> Huayi
>
>
>
>
> On 2016年08月25日 21:49, David Joyner wrote:
>>
>> On Thu, Aug 25, 2016 at 9:31 AM, 魏华祎 <weihu...@xtu.edu.cn> wrote:
>>>
>>> Hi, guys,
>>>
>>> I define `g1` and `g2` in the following code, but I am not so clear about
>>> their difference. Hope you guys show me some clues about it. Thanks very
>>> much.
>>> ```
>>> var('t')
>>> g1=4*t^2 + 3*t + 1
>>> g2(t)=4*t^2 + 3*t +1
>>> ```
>>
>>
>> sage: var('t')
>> t
>> sage: g1=4*t^2 + 3*t + 1
>> sage: g2(t)=4*t^2 + 3*t +1
>> sage: g1(2)
>>
>> /Users/wdj/sagefiles/SageMath/local/lib/python2.7/site-packages/IPython/core/interactiveshell.py:2885:
>> DeprecationWarning: Substitution using function-call syntax and
>> unnamed arguments is deprecated and will be removed from a future
>> release of Sage; you can use named arguments instead, like EXPR(x=...,
>> y=...)
>> See http://trac.sagemath.org/5930 for details.
>>    exec(code_obj, self.user_global_ns, self.user_ns)
>> 23
>> sage: g1(t=2)
>> 23
>> sage: g2(2)
>> 23
>>
>> Does that help?
>>
>>> Best
>>>
>>> Huayi
>>>
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>
>
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