it seems just because t2 is composite. Justin C. Walker於 2020年5月7日星期四 UTC+8上午4時34分22秒寫道： > > > > > On May 6, 2020, at 12:42 , Taylor Huang <asd0001...@gmail.com > <javascript:>> wrote: > > > > for copying convenience, > t2=1309093727683013566817782825108625009747446954546358949698232965571021678022482795164257607242612437837777327711946435277119464351117309193681 > > > > This may be more feature than bug. If you break up the latter computation > (below), like > t3 = mod(-1,t2) # mod(-1,x) returns x-1 > t3.sqrt() > > you get a response quickly, but it may not be what you are after. > > t3 is 16*t4 > > but t4 is not prime, and is square-free (I believe Sage implicitly :-}). > > Trying to factor it seems interminable (i.e., it hasn’t completed in ~5 > minutes on my new iMac). It may well be beyond the software’s attention > span, hence the message you got. > > HTH > > Justin > > > > > Taylor Huang於 2020年5月7日星期四 UTC+8上午3時37分12秒寫道： > > As the attachment shown. kronecker(-1,t2) returns 1, but > mod(-1,t2).sqrt() says the square root cannot be done. > > It seems to be a bug. > > -- > Justin C. Walker, Curmudgeon at Large > Institute for the Absorption of Federal Funds > ----------- > Like the ski resort full of girls hunting for husbands > and husbands hunting for girls, the situation is not > as symmetrical as it might seem. > - Alan MacKay > -- > >
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