On Saturday, April 9, 2016 at 9:17:27 AM UTC-7, David Roe wrote:
>
>
> Is there any ambiguity?  g is a function of one variable and we're 
> specifying the variable of integration.  Is there a reason that we 
> shouldn't allow indefinite_integral(g, x) to work?
> David
>
> In you just use integral, this already does work. And it does NOT work by 
using the specified variable as argument to a single variable function:

sage: f(x)=x^2+y^2
sage: integral(f,x)
x |--> 1/3*x^3 + x*y^2
sage: integral(f,y)
x |--> x^2*y + 1/3*y^3

I'm not sure that these semantics are particularly desirable, but they do 
preclude assigning any other meaning to idefinite_integral(g,x).

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