> any idea how to get the number of
> terms in a better way in Sage?):
>
> sage: K.<sqrt3> = QuadraticField(3)
> sage: L.<sqrt5> = K.extension(x^2-5)
> sage: R.<a1,a2,a3,a4,a5> = L[]
> sage: time f = (a1+a2+a3+sqrt5*a4+sqrt3*a5)^18
> CPU times: user 2.43 s, sys: 3.94 ms, total: 2.44 s
> Wall time: 2.44 s
> sage: len(str(f).split("+"))
> 7315
>
>
>
You may do "len(list(f))".
To avoid the creation of the list: "sum(1 for _ in f)".
Some timings:
sage: %time len(str(f).split("+"))
CPU times: user 8.2 s, sys: 3.14 s, total: 11.3 s
Wall time: 12 s
7315
sage: %time len(list(f))
CPU times: user 699 ms, sys: 98.1 ms, total: 797 ms
Wall time: 770 ms
7315
sage: %time len(f.monomials())
CPU times: user 127 ms, sys: 13.7 ms, total: 141 ms
Wall time: 135 ms
7315
sage: %time sum(1 for _ in f)
CPU times: user 69.6 ms, sys: 18.8 ms, total: 88.3 ms
Wall time: 85.2 ms
7315
Sébastien
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