The ith element of a list is M[[i]]. An expression ending in & is a
lambda function, with # being the first parameter. f /@ B is equivalent
to map(f, B) (f is applied to each element of B). If[# == 0, 0, 1] is
equivalent to lambda x: x==0 ? 0 : 1
So to me, it looks like:
m2 = [m[2][i] for i in [x[2] for x in m[3]]
m3 = [m2[i] for i in [x[2] for x in m[4]]
lM = [[0 if i==0 else 1 for i in x] for x in m3]
There's a decent chance that I missed something, though. It's been a
long while since I did anything in mathematica, and I've realized that
mathematica quickly starts looking like line noise after I've stopped
using it.
Thanks,
Jason
P.S. I was curious about the online mathematica the other night. If I
understood the marketing material correctly, it seems you get
interactive computation included in the base price, and you are charged
for offline computation. I checked the prices, and saw that the credit
system they offer sells computational time for about $10.80/hour (in $15
increments), down to $6.47/hour (if you buy $180 at a time), billed in
100ms chunks [1]. In comparison, the highest price an Amazon Linux EC2
On Demand instance is a 32 processor, 244GB Ram, 8 800GB SSD instance
for $6.82/hour. I realize I didn't count Amazon's bandwidth charges
($0.12/GB after 1GB out from EC2 to internet each month), but
regardless, that seems like relatively expensive computational time.
[1] http://www.wolfram.com/cloud-credits/ (down at the bottom)
[2] http://aws.amazon.com/ec2/pricing/
On 11/21/14, 20:45, William Stein wrote:
On Nov 21, 2014 11:46 AM, "Dr. David Kirkby (Kirkby Microwave Ltd)"
<drkir...@kirkbymicrowave.co.uk <mailto:drkir...@kirkbymicrowave.co.uk>>
wrote:
>
>
> On 18 Nov 2014 22:37, "Stefan" <stefanvanz...@gmail.com
<mailto:stefanvanz...@gmail.com>> wrote:
> >
> > I don't know if I simply lack the appropriate Mathematica
knowledge, but years ago, when I implemented matroids
> > lM = Map[If[# == 0, 0, 1] &, M[[2]][[#[[2]] & /@ M[[3]], #[[2]] &
/@ M[[4]]]], {2}];
>
> I am no expert on Mathematica, but Mathematica code does not need to
be so cryptic.
>
Can anybody rewrite the above line of mathematica code so that it does
something equivalent, but is less cryptic?
> Anyway, is it any less readable than this code to plot the
Mandelbrot set?
>
>
http://preshing.com/20110926/high-resolution-mandelbrot-in-obfuscated-python/
>
> Or this C code
>
> http://www.ioccc.org/2013/birken/birken.c
>
> Dave.
>
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