On Nov 13, 1:26 am, John Cremona <john.crem...@gmail.com> wrote:
> No, you do not miss anything.  As someone has already reminded us (and
> I say clearly in the talk for which those are the slides), there is no
> known way of proving that the 3rd (or higher) derivative of an
> elliptic curve L-function is 0.  Any computations of higher derivative
> are always based on an assumption that some lower derivatives which
> have been computed to some approximation and which look as if they are
> zero, really are zero.

OK, just for posterity (the MathOverflow question points to this
discussion),
let's make clear here that to provide an *upper bound* on the order of
vanishing (say, r), one needs to prove that *one* of

L^(0)(1), L^(1)(1), ..., L^(r)(1)

is nonzero, not any particular one. With proper error bounds that's
doable in principle: as John points out, the error bounds used to
prove that L^(r)(1) is non-zero assume that L^(0)(1)=...=L^(r-1)(1)=0,
but if that assumption isn't valid then r is still a valid upper bound
on the order of vanishing of L at 1, just not a sharp one.

Every time that sage underreports the order of vanishing rather than
not finish, run out of memory, or throw an error "too much work for
me", I think we can consider it a bug. Of course *proving* that sage
is underreporting the order of vanishing is hard :-).

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