> Mhh, why not? If A = LUP we just write AP^-1 = LU, hence for each LU we > construct there are as many As as there are permutation matrices, or am I > missing something (again :))?
I am not sure that the LUP decomposition is unique (I understand that the LU is). If A has more distinct LUP factorizations than B, then A is more likely to be produced by this process than B.... Charles -- To post to this group, send an email to sage-devel@googlegroups.com To unsubscribe from this group, send an email to sage-devel+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URL: http://www.sagemath.org
