On Feb 4, 11:21 am, Jason Grout <jason-s...@creativetrax.com> wrote: > On 2/4/12 11:24 AM, Keshav Kini wrote: > > > On Saturday, February 4, 2012 11:43:44 PM UTC+8, Andrey Novoseltsev wrote: > > > But in definite integrals the variable of integration is a dummy one > > and does not exist out of the integral! > > > +1. This behavior makes no sense to me. > > So what happens in a case like this? > > sage: f(x,y,z)=sin(x*y*z) > > sage: integrate(f,(y,0,3)) > > Does the result become a function > > (x,z) |--> whatever? > > I can see it making sense, but I can also see it causing problems. > > Thanks, > > Jason
What kind of problems can it cause?.. We have a function with variables which are named and have a particular order. If one of them is gone, the rest keeps both their names and the same ordering. -- To post to this group, send an email to sage-devel@googlegroups.com To unsubscribe from this group, send an email to sage-devel+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URL: http://www.sagemath.org
